Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

o supplementary angles is 40° then the measurement of theIf the difference of twgreater angle is

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Supplementary angle is sum of angles is 180°Hence let the angle be X and (180-x)now given that difference.is 40°hencex-(180-x)=40x-180+X=402x=40+1802x=220x=110°hence greater angle is 110°

2.

iii)On a certain article, if the rate of CGST is 9%, then find the amount of GST onarticle oftaxable valueSolution:700.GST = []00 of 700× 700=The amount of GST is□.

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3.

Factorize using identity: d-36b2

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a cube + 52 b square + 2

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4.

20 tickets, on which numbers 1 to 20 are written,are mixed thoroughly and then a ticket is drawnat random out of them. Find the probability thatthe number on the drawn ticket is a multiple of 3or 7.[Foreign Set I, II, III, 2016]

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5.

2 मेक:v, L/tw"fc 2 ० थी क् = CTAn (%) हर

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6.

twof each thianglep

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7.

te, stada sade(each 42m).frd two-n

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Area of shaded region is 5544 cm^2

Step-by-step explanation:

From the given figure, we can see that there are 2 large shaded semicircle and 2 small shaded semicircle

Let R be the radius of large semicircle and r be the radius of small semicircle.

Area of large semicircle

Area = (piR^2)/2

There are two large semi circle,

therefore total area = 2 x (piR^2)/2 = piR^2

Area of small semicircle

Area = (pir^2)/2

There are two large semi circle,

therefore total area = 2 x (pir^2)/2 = pir^2

Area of shaded region

Area = [piR^2 -pir^2] - pir^2

join all the shaded region we get a circle with radius 42

Area of circle with radius 42 = πR^2=22/7 x 42 x 42 = 5544 cm^2

8.

If 31 litres of milk are poured into 4-litrevessels, how many such vessels will becompletely filled and how much milk willthere be in the partly filled vessel

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9.

=of a number is 20 less than the original number. Find the number.

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10.

0.6 of a number is 20 less than the original number. Find the number.

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11.

6. The sum of two digits of a two-digit number is 10.If the number obtained on reversing the digits is54 less than the original number, find the originalnumber.

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the correct answer is 28 so 28 is the number which you want . please give it thank

28 is the right answer of the question

28 is the right answer of the question

28 is the right answer

28 is the perfect answer

12.

s of a number is 20 less than the original number. Find the number.3

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13.

wat of the digit 8 in(3) One lakh sixteen thouse(4) Sixteen hundred6. How many times is the place value of the digit 2 than that of the digitthe number 34.32.058 ?(1) 2000 (2) 2000 (3) 250 (4) 250alace values of the digits 3 and 6 in the

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option 2 2000is correct answer

Answer:

4). 250

Step-by-step explanation:

see the place Value of 2 in 3432058 is:-

2000

and Place Value of 8 in 3432058 is:-

8

A.T.Q

2000÷8

=250

hope this answer will help you

Plz like my answer Plz accepted as bestPlz

option 22000is correct answer

14.

1. In the number 53.436. how many times is the place value of the digit 3 to the rightof the digit 4 to that of the digit 3 to the left of the digit 4?

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0.03x = 3x=100100 times

15.

n the number 9540732, how many times is the place value of the digit 4 than thatof the digit 2?1) 200 (2) 2000 (3) 20900 (4) 20

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In which of the following numbers the place value of the digit 2 is 20000?

16.

16. I he angles of elevation of the top of a tower from two points ut ρ distance of 4 m and9 m from the base of the tower and in the same sraight line wih i ae compiensoianyProve that the heighi of the tower is 6m

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17.

The digits of a positive number of three digits are in A.P. and their sum is 15The number obtained by reversing the digits is 594 less than the originalnumber Find the number.

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18.

6. ABC is a triangle right angled at C. A line through the midpointAM ofhypotenuse AB and Parallel to BC intersects AC at D. Show that0) D is the midpoint ofAC(ii) MD ACAe(ii) CM MA ABCr

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19.

The digits of a positive number of three digits are in A.P and their sum is 15. The number obtained byreversing the digits is 594 less than the original number. Find the number

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Let the digits be a, a+d and a+2d. Their sum i.e. 3a + 3d = 15 => a + d = 5 => second digit must be 5.

The number has to be of descending order as difference between this and reversed one is positive. So your choices are 654, 753, 852 and 951. Clearly, 852 is the one you're looking for. Let's formally solve it anyway.

100a + 10x5 + (a+2d) = given no.

a + 10x5 + 100(a+2d) = reversed no>

Subtracting,

99a - 99(a+2d) = 594 (gn.)

a - (a+2d) = 6

-2d = 6

d = -3

a + d = 5, so a = 5 + 3 = 8

Now substitute for a, a+d, and a+2d and you'll get the digits and hence the number required

20.

A number of three digits has the hundred digit 4 times the unit digit and the sthe three digits are written in the reverse order, the valuenumber is decreased by 594. Find the number.

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21.

(1) Ticket numbered from 1 to 20 are mixed up together and then a ticket is drawn atrandom. What is the probability that the ticket drawn has a number which is amultiple of 3 or 7?

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22.

yee9(1) Ticket numbered from 1 to 20 are mixed up together and then a ticket is drawn atrandom. What is the probability that the ticket drawn has a number which is amultiple of 3 or 7?O The

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total numbers=20multiple of 3=3,6,9,12,15,18multiple of 7=7,14probability= favourable outcome/total no. of outcomes6/20 or 2/20

23.

Q.10) Tickets numbered 1 to 20 are mixed up & then a ticket is drawn What is the probabilitythat the ticket drawn has a number which is multiple of 3 or 5.

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24.

In Fig. 13.77, from a rectangular region ABCD with AB 20 cm, a right triangeAED with AE 9 cm and DE 12 cm, is cut off. On the other end, taking B asdiameter, a semicircle is added on outside the region. Find the area of the shaded region.(Use t 22/7).[CBSE 2014]

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25.

8. Tickets are numbered from 1 to 100. They are well shuffed and a ticket is drawn at random. Whatis the probability that the drawn ticket has a number which is a square?

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from 1 to 100 there are 10 perfect squares so probability of getting square number 10/100 = 1/10

26.

Suppose you drop a dieat random on the rectangular region shownim Fig. 15.6 Whthe probabiliny that ii wil land inside the circlewith diameter Im2 mFig. 15.6

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27.

19, what must be added to the polymormialf(x) = x4 + 2x3-2r + x-l so that the resultingpolynomial is exactly divisible by a +2r 3?

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28.

. Suppose you drop a die at random on the rectangular region shown in Fig. 14.6. What isthe probability that it will land inside the circle with diameter 1m?2 m

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29.

In the given figure, from a rectangular regionABCD with AB 20 cm, a right triangle AEDwith AE 9 cm and DE = 12 cm, is cut off. Onthe other end, taking BC as diameter, asemicircle is added on outside the region.Find the area of the shaded regiorn.(Use π = 3.14.]ICBSE 2014]

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thanks

30.

Show that the equation 2r2-ху-3y2-6x + 19y-20Show further that the angle between them is tan-1(5)0 represents a pair of intersecting lines.

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31.

a rectangular region A is 440 sq m. The length of a rectangular region B is half thegion A and its breadth is half the breadth of A. What is the area of the region B?7. The area ofreg

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For Plot A :Let the length be l and breath be b then lb = 440 . ....................1

For Plot B :length will be l/2 and breath be b/2 then area = l/2 * b/2 = lb/4

From eq 1 we get lb / 4 = 440 / 4 = 110 sq. m

32.

Sample Papers forQ 25: In figure, from a rectangular region ABCD with AB 20 cm, a right triangle AED wih AEcm and DE 12 cm, is cut off. On the other end, taking BC as diameter, a semi-circle is added onoutside the region. Find the area of the shaded region.9 cm15 cm12 m

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33.

यदि tan theta=frac{{cos 9+sin 9}{cos 9-sin 9}} तो theta बताइए?

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cos9°+sin9°/cos9°-sin9°dividing numerator and denominator by cos9°=(cos9°+sin9°)/cos9°/ (cos9°-sin9°)/cos9°=1+tan9°/1-tan9°=tan45°+tan9°/1 - tan45°×tan9°=tan(45°+9°)=tan54°so the answer is tan54°

34.

cos 9° + sin 9°cos 9º - sin 90 f A(a) cot 64°(c) tan 26°(b) cot 36°(d) tan 54°

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Answer:d)tan 54°

Explanation:(cos 9°+sin 9°)/(cos 9°+sin 9°)

={(cos 9°+sin 9°)/cos 9°}/{(cos 9°+sin 9°)/cos 9°}

=(1+tan 9°)/(1-tan 9°)

=(tan 45°+tan 9°)/(1- tan 45°tan 9°)

=tan (45°+9°)

=tan 54°

35.

Which of the following needs a proof 1) axiom 2) heorem 3) postulate 4) definition

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theorem needs। a proof

36.

\frac{(\cos \theta+i \sin \theta)^{4}}{(\sin \theta+i \cos \theta)^{5}}=\sin 9 \theta-i \cos 9 \theta

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37.

\begin{array}{l}{\cos 225^{0}+\sin 165^{\circ}=} \\ {\text { 1) } 0 \quad 2 ) \frac{\sqrt{3}-1}{\sqrt{3}} 3 ) \frac{\sqrt{3}-1}{2 \sqrt{2}} 4 ) \frac{\sqrt{2}+1}{\sqrt{2}}}\end{array}

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the answer is not in the option.

38.

2. Find the roots of equation、/2r2+ 9 = 9.-)

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√(2x2+ 9) = 92x2+ 9 = 922x2= 81 - 92x2= 72x2= 36so, x = 6 or - 6

39.

2r2+(2r+1)3x +

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40.

1.Find the nature of the roots of the following quadratic equations. Ifthe real roots exist,find them:G) 2r2-3x+5 0(ii) 2x2-6x+3-0(ii) 302-4 3 x +4-0

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41.

equations by factorisation:(ii) 2r2 +x-6 0

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2x^2+(4-3)x-6=02x^2+4x-3x-6= 02x(x+2)-3(x+2)=0(2x-3)(x+2)= 0x= -2 and x = 3/2

42.

Find the solution of the equation x4 2x3 - 2r2 2x +1 0.

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x^4–2x^3+2x^2–2x+1=0

divide both side by x^2.

x^2–2x+3–2/x+1/x^2=0

x^2+1/x^2–2(x+1/x)+3=0

x^2+2+1/x^2–2(x+1/x)+1=0

(x+1/x)^2–2(x+1/x)+1=0

Let x+1/x=t

t^2–2t+1=0

(t-1)^2=0

t-1=0

t=1 , put t=x+1/x

x+1/x=1

or x^2+1=x

or x^2-x+1=0

or (x)^2–2×x×1/2+(1/2)^2+1–1/4=0

or (x-1/2)^2=-3/4=(3i^2)/4=3(i/2)^2.

or x-1/2=+/-3^1/2.(i/2)

or x=1/2+/-3^1/2.(i/2).

or x=(1+/-i.3^1/2)/2

43.

ERRES.company manufactures two types of clothmaterial. Ifone of them is cotton on which thecompany earns i 4 on each metre sold. Ifcompany sold 500 metres of cotton cloth. Whatis the profit earned?Aman hann sich bin50

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Company earn Rs 4 on each metre of cotton cloth sold.

Then,Amount company earn on 500 metre of cotton cloth sold= 500*4= Rs 2000

Therefore,Profit earned by company = Rs 2000

44.

int toinFind two equivalent ratios of :(ii) 5:3Which of tho fall

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1) two equivalent ratio of 1:2are 2:4 and 4:8

2)two equivalent ratio of 5:3are 10:6 and 15:9

45.

Sighal lequnes tho uu3. Four children are running a race.(i) In how many ways can the first two places be filled?(ii) In how many different ways could they finish the race?

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out of 4 only two can be in first two placeand only one child can be at one placeso nCr = 4C2= 4!/2!2!=6

they can finish in 4! ways24 ways

46.

_ (पं) झा 9(1+ दा 9) + 005 0(1 + 00 0) न (567 9+ 00560 9का 0 + .(*_fi_____)l+cose = 2cosec 0+cos6) sin 9 4

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ii) According to given sum,

sin (1+tan)+cos (1+cot)=sec+cosec

=> LHS= sin (1+tan)+cos (1+1/tan)

=> sin (1+tan)+cos (1+tan)/tan

=> (1+tan)(sin+cos/tan)

=> (1+tan)(sin.tan+cos)/tan

=> (1+tan)(sin^2/cos+cos)/tan

=> (1+tan)(sin^2+cos^2)/tan.cos

=>(1+tan)/tan.cos

=>(1/tan.cos)+tan/tan.cos

=>( cot/cos)+(1/cos)

=> cosec +sec

LHS= RHS.

Like my answer if you find it useful!

47.

0 9 sec A - 9 tan2 A-(B) 9t sec e) (1 + cot θ _ cosec 0) =(A) 1(C) 8(D) 0

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Answer : B) 9

48.

\frac{\cos 9^{0}+\sin 9^{\circ}}{\cos 9^{0}-\sin 9^{0}}=\cot 36^{\circ}: Prove that

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49.

) Is 336 the multiple of 21?

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yes as 336 consists 21 in factorization

336 ÷21=16yes 336 is a multiple of 21

50.

7. Radha walks 2.275 km allulstarting point? How much distance should she cover more iorder to be &the starting point?s. Mr. Mohan requires 1.05 litres of petrol every day for his carHow mandoes he use in a month? If the petrol costson petrol every month?y litres ofte, how much does he71.90per litr1 4 hotel needs 165 ifres of milk every day. How many litres of milk does itopor litres how much does the hotel owmer s

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