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_ (पं) झा 9(1+ दा 9) + 005 0(1 + 00 0) न (567 9+ 00560 9का 0 + .(*_fi_____)l+cose = 2cosec 0+cos6) sin 9 4 |
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Answer» ii) According to given sum, sin (1+tan)+cos (1+cot)=sec+cosec => LHS= sin (1+tan)+cos (1+1/tan) => sin (1+tan)+cos (1+tan)/tan => (1+tan)(sin+cos/tan) => (1+tan)(sin.tan+cos)/tan => (1+tan)(sin^2/cos+cos)/tan => (1+tan)(sin^2+cos^2)/tan.cos =>(1+tan)/tan.cos =>(1/tan.cos)+tan/tan.cos =>( cot/cos)+(1/cos) => cosec +sec LHS= RHS. Like my answer if you find it useful! |
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