te, stada sade(each 42m).frd two-n

1.	te, stada sade(each 42m).frd two-n
Answer» Area of shaded region is 5544 cm^2 Step-by-step explanation: From the given figure, we can see that there are 2 large shaded semicircle and 2 small shaded semicircle Let R be the radius of large semicircle and r be the radius of small semicircle. Area of large semicircle Area = (piR^2)/2 There are two large semi circle, therefore total area = 2 x (piR^2)/2 = piR^2 Area of small semicircle Area = (pir^2)/2 There are two large semi circle, therefore total area = 2 x (pir^2)/2 = pir^2 Area of shaded region Area = [piR^2 -pir^2] - pir^2 join all the shaded region we get a circle with radius 42 Area of circle with radius 42 = πR^2=22/7 x 42 x 42 = 5544 cm^2

Answer»

Area of shaded region is 5544 cm^2

Step-by-step explanation:

From the given figure, we can see that there are 2 large shaded semicircle and 2 small shaded semicircle

Let R be the radius of large semicircle and r be the radius of small semicircle.

Area of large semicircle

Area = (piR^2)/2

There are two large semi circle,

therefore total area = 2 x (piR^2)/2 = piR^2

Area of small semicircle

Area = (pir^2)/2

There are two large semi circle,

therefore total area = 2 x (pir^2)/2 = pir^2

Area of shaded region

Area = [piR^2 -pir^2] - pir^2

join all the shaded region we get a circle with radius 42

Area of circle with radius 42 = πR^2=22/7 x 42 x 42 = 5544 cm^2

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