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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
2. Mala has a collection of bangles. She has 20 gold bangles and 10 silver banglesWhat is the percentage of bangles of each type? Can you put it in the tabular fornmas done in the above example? |
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Answer» Total bangle =20+10=30 percentage of gold bangle= 20/30=66.6% and for silver=10/30=33.3% by rounding off the figure 67% and 33 % . |
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| 2. |
MATHEMATICSlection of bangles. She has 20 gold bangles and 10 ilver honiyeu put t n hetlat2 Mtalt has aWhat is the pertentage of bangles of each type? Canas done in the above example?THINK, DISCUSS AND WRITE1. Look at the examples holu |
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Answer» total no. of Bangles = 20+10 = 30 now % of gold bangle = 20/30×100 = 66.7% % of silver bangles =10/30×100 = 33.3 % I have not understand |
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| 3. |
) [ Side of square (in cm)216Area (in em)Is it a linear graph? |
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| 4. |
3. (a) Anjana wore 8 out of the 11 bangles she bought from a fair. Whatfraction of the bangles did she wear? |
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Answer» 8/11 is the correct answer of the given question. Anjana wore 8/11 bangales. 8/11 bangles is right answer 8/11 bangles is a correct answer 8/11 is the correct answer |
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| 5. |
??area is49 121 441 ?13. How many square metre of glass will berequired for a window, which has 12 panes,each measuring 25 cm by 16 cm?Tu man tilancm square? |
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Answer» area of 12 such panes = 12x0.04=0.48m2 |
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| 6. |
,)s per square metre. | Take Ď =e circumference of the base of a cylindrical vessel is 132 em and its height is 25 cm. How many litresof water can it hold ? |
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| 7. |
A semicircular grass lawn has a radius of 56 m.(a) What is the cost of planting grass on it if it costs sh 25 per square metreto plant grass?How many flower bushes can be planted around the lawn at 4 m apart?(b) |
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Answer» Area of lawn = (πr^2)/2 =(22/7 * (56)^2)/2 =9856/2 =4928 m^2Cost of planting= 4928×25 =Rs 123200 |
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| 8. |
two and a half litres of paint is used to cover 725 square metre of area how much will be required to paint 2001 square metre of area |
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| 9. |
6. A red carpet 12 m long and 1.5 m wide iskept for welcoming foreign dignitaries andheads of state. A 10 cm wide border runsparallel to the lengths on both the edges.Along the width of one edge the border is25 cm wide and on the other side the borderis .5 m broad with 'WELCOME' inscriptedon it. Find the total area of the border.1.5 mO12 m |
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Answer» Given a red carpet with dimensions Length = 12 m Width = 1.5 m Now, A 10 cm wide border runs parallel to the lengths on both the edges.Along the width of one edge the border is 25 cm wide and on the other side the border is .5 m broad with WELCOME' inscripted ón it. We have to find total area of border Area = Area (1) +Area(2)+Area(3)+Area(4) = 0.5*1.5+11.25*0.1+0.25*1.5+11.25*0.1+0.75+1.125+0.375+1.125=3.375m^2 Hence, the total area of border is 3.375m^2 |
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| 10. |
oдоооо,o o o o 605 o o o o )s ost t |
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Answer» 60249 hoga like my comment by adding=8774 is correct result. 13774 is correct answer. 13774 is the right answer according to your question 13774 the correct answer of the given question 13774 is correct answer. 13774 is the correct answer 13774 is the correct answer 13774 is the write answer |
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| 11. |
८०598 sin8 - "V“L Ao= sinfg 4+ €ostProve that — % > 1-cotf ६ |
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Answer» please like my answer if you find it useful |
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| 12. |
2 and3do Make a reauancy dubctolitRabution 어 the bellesSeries, 21 2,33 31 31 3iiu6,5,5)5, 6,i |
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Answer» terms. frequency1. 12. 23. 54. 95. 76. 47. 2 |
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| 13. |
(text*((b*y)*(-sqrt(7) %2B sqrt(3))))*(sqrt(3) %2B sqrt(7)) |
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| 14. |
1. उस त्रिभुज क़ा क्षेत्रफल ज्ञात की® 2.3),-1,0,2,-49P - गा s S A 21 8 i s R |
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| 15. |
If a and b are rational numbers and \frac{7-4 \sqrt{3}}{7+4 \sqrt{3}}=a+b \sqrt{3}, find the ralues of a andb. |
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| 16. |
oguph measuring 25 um by 20em is nounted ona rectangularsheiofcardboardA photographkeeping a uniform border o em wide all aroundthe pliotograph. Find the arca of theborder |
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| 17. |
A saree is 6 m long and 2.3 m wide. A border of width 25 cm is printed along its sides. Find the cost of printingthe border at 1 per 10 cm2 |
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| 18. |
A sareeis 6 m long and 1.2 m wide. A border of width 30 em is printed along its side. Find thecost of printing the border at 1 per 20 cm |
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| 19. |
A red carpet 12 m long and 1.5 m wide iskept for welcoming foreign dignitaries andheads of state. A 10 cm wide border runsparallel to the lengths on both the edges.OAlong the width of one edge the border is325 cm wide and on the other side the borderis.5 m broad with 'WELCOME' inscriptedop it. Find the total area of the border.1.5 msN.NN12 m |
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| 20. |
17. On selling a tea-set at 5% loss and a dinner set at 15% gain, a crockery seller gains Rs.7. If hesells the tea-set at 5% gain and the dinner set at 10% gain, he gains Rs.13. Find the actual price |
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| 21. |
2. If tbc manut acturer gains 10%, the whole-seller gains 15% and the retailer giun, 25-i ouiaoanticle, then lind the cost of production of the article whose retail price is Rs.1265 0(aj Rs 725.00ic) Rs. 9650(b) Rs. so0oo(d) Rs. 10I1200 |
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Answer» kindly upload a more clear image. this is blurred |
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| 22. |
On selling a bat forRs. 100, a man gains Rs.20. His gain% is |
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Answer» Sp of the bat=Rs 100gain=g=Rs20Cost price=cpcp=sp-gcp=100-20=80gain %= gain/cp ×100 =(20×100)/80=25% |
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| 23. |
Cost price of a bag is Rs. 250 and after selling i gains Rs. 50. Find the gain percentage |
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| 24. |
\begin{array}{l}{\text { The value of } \frac{1}{2+\sqrt{7}}+\frac{1}{\sqrt{7}+\sqrt{10}}+\ldots+\frac{1}{\sqrt{28}+\sqrt{31}} \text { is }} \\ {\text { (1) } \frac{4-\sqrt{28}}{3}} \\ {\text { (3) } \frac{\sqrt{28}-4}{3}}\end{array} |
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Answer» not understand by me |
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| 25. |
\frac 5 %2B 2 \sqrt 3 7 %2B 4 \sqrt 3 = a - b \sqrt 3 , \text find a \text and b |
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Answer» Thank you so much |
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| 26. |
\begin{array}{l}{\text { RATIO AND PROPORTION: }} \\ {\text { 32. Solve for } x : \frac{\sqrt{a+x}+\sqrt{a-x}}{\sqrt{a+x}-\sqrt{a-x}}=b} \\ {\text { 33. If } a : b=2 : 3, b : c=4 : 5 \text { and } c : d=6 : 7, \text { fo }}\end{array} |
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| 27. |
7 \operatorname { sin } ^ { 2 } \theta + 3 \operatorname { cos } ^ { 2 } \theta = 4 \text { then } \operatorname { tan } \theta \text { is- a } ) \pm \frac { 1 } { \sqrt { 3 } } , b ) - \frac { 1 } { \sqrt { 3 } } , c ) \frac { 1 } { \sqrt { 3 } } , d ) - \sqrt { 3 } |
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| 28. |
\left. \begin{array} { l } { - 39 x ^ { 4 } \text { by } \sqrt { 13 } x ^ { 2 } } \\ { 49 p ^ { 3 } b y - 7 \sqrt { 7 } p ^ { 2 } } \end{array} \right. |
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Answer» thanks bro |
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| 29. |
how do MNCs help the growth of local companies |
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Answer» thanks |
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| 30. |
The parallel sides of a trapezium are 25 cm and 11 cm, while its non-parallel sidesare 15 cm and 13 cm. Find the area of the trapezium. |
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| 31. |
The edges of a triangular board are 6 cm, 8 cm and 10 cm. The cost of painting it at the rate of 9paiseper cm2 is (A) Rs 2.00 (B) Rs 2.16 (C) Rs 2.48 (D) Rs 3.00. |
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| 32. |
4. While helping father put in a new driveway, Kapil carried11 bags of sand from the garage to the cement mixer. Ifeach bag weighted 15 Âź kg, what was the total weight ofall the sand that Kapil carried? |
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Answer» One bag weighs 15 1/4kg=61/4kgHence 11 bags=61/4*11=671/4kg |
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| 33. |
A man has 50 coins each of 25 paise, 50 paise and 1 rupee.The total amount Aman has with him is7.(a)(b)(c)(d)77.57987.5乏100 |
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Answer» Total money is = 50(25) + 50*(50) +50*(100)= 1250+2500+5000= 8750 paise so, in Rs it is = 8750/100 = 87.5rs thank you |
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| 34. |
t. While helping father put in a new driveway, Kapil carriedof sand from the garage to the cement mixer. Ifeach bag weighted 15 4 kg, what was the total weight ofagsall the sand that Kapil carried? |
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Answer» Each bag weighed = 15 1/4 kg= 61/4 kg Weight of 11 bags = 11x61/4 kg= 671/4 kg= 167 3/4 kg ans |
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| 35. |
[(2/3)^2]^3*(1/3)^-4*(3)^-1* (1/6) |
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| 36. |
ABCD is an isosceles trapezium. Its parallel sidesmeasure 13 cm and 25 cm. Its non-parallel sidesare equal and measure 10 cm. Find the area ofthe trapezium |
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Answer» thnx |
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| 37. |
3. ABCD is a parallelogram with area 80 sq. cm.the diagonal AC and BD intersect at o.P is the mid-point of OA.Calculate ar (ABOP).0 |
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Answer» area of parellalogram ABCD = 80sq cm. we know diagonal of parellaogram divides it 2 traingle of equal area so area of [ABD] = [DBC] = 40 sq cm. BD & AC are the diagonals & we know diagonals bisect each other. So, area of [AOD] = [BOA] = 40÷2 i.e. 20 sq. cm. P is the mid point of OA it means BP is the median of [ABO] & we know median divides triangle in 2 of equal area so, ar[BOO] = ar[ABP] = 10 sq cm. Hence, ar[BOP] = 10 sq cm. hit like if you find it useful |
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| 38. |
6. ABCD is an isosceles trapezium. Its parallel sidesmeasure 13 cm and 25 cm. Its non-parallel sidare equal and measure 10 cm. Find the area ofthe trapezium. |
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| 39. |
B5-324218. The area of a trapezium is660 sq. metre. The two parallel sides are 28 m and 16 m. Find thedistance between the two parallel sides.9 he ano |
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| 40. |
is 4 times the laulu17 A yessel is in the form of a hemispherical bowl surmounted by a hollowcylinder. The diameter of the hemisphere is 21 cm and the total heightof the vessel is 14.5 cm. Find its capacity. |
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| 41. |
- यदि V3।3+10+63 हो, तो a तथा 6 कामान है- |
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| 42. |
10. Show that 7- v3 is irrational, given that 3 is irrational. |
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| 43. |
3. A saree is 5 m long and 1.3 m wide. A border of width 25 cm is printed along its sides. Findthe cost of printing the border at 1 per 10 cm. |
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| 44. |
10. Show that 7- 3 is irrational, given that v3 is irrational.OR |
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Answer» root(3) is an irrational given now in 7 - root(3) 7 is rational and root(3) is irrational so combination of rational and irrational is irrational. so 7-root(3) is irrational. |
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| 45. |
7) Show that 5-3v3 is an irrational, given that v3 is irrational. |
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Answer» Suppose 5 -3√3 is rational .Let5 +3√3= r where r is a rational.∴ (5 -3√3)^2= r^2∴ 25+27 -30√3 = r^2∴√3 = (r^2- 52) / 30Now , LHS =√3 is an irrational number .RHS (r^2- 7) / 2 is arational number .But rational number cannot be equal to an irrational.∴our supposition is wrong.∴ 5 + 3√3 is irrational . |
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| 46. |
a the cost of digging à well ia스,A4.nght circular cylinder is closed at its both ends. Find the cost of painting its total surfaceareaat 50 paise per sq cm if the radius is 3.5 cm and height 14 cm. |
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| 47. |
1. A copper wire, 3 mm in diameter, is wound about a cylinder whose lepgthiT$12 cm,.audiameter 10 cm, so as to cover the curved surface of the cylinder. Find the lengtharmass of the wire, assuming the density of copper to be 8.88 g per cm |
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Answer» It is assumed that one round of copper wire will cover 3 mm or 0.3 cm height of cylinder.Number of rounds = Height of the cylinder/diameter of the wire= 12/0.3= 40 roundsNow, The length of the wire required in one round = Circumference of the base of the cylinderDiameter of the cylinder = 10 cm, so the radius = 5 cm.circumference = 2πr= 2*π*5Length of wire required in one round = 10πLength of wire required in 40 rounds = 10π*40= 400*22/7= 8800/7Length of the wire = 1257.14 cmRadius of the wire = 0.3/2 = 0.15 cmVolume of wire = Area of cross section of wire× length of the wire=π*r²× 12.5722/7 × (0.15)²× 1257.14Volume of the wire = 88.898 cm³Mass = Density× Volume= 8.88× 88.898Mass = 789.41 gmAnswer. |
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| 48. |
3. The inner length, breadth and height of an openbox are 95 cm, 75 cm and 97.5 cm respectively. Ifthe wood in 25mm thick the cost of painting outside6of the box (the bottom is not to be painted) at 50paise per 100 sq, cm is |
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| 49. |
28. A fez, the cap used by a jocker is shaped like frustum of a cone. If its radius on the open side is10 cm, radius at upper base is 4 cm and its slant height is 15 cm, find area of material used formaking it. Also find the cost of the material used to make the cap, if its cost 7 per 10 cm2 |
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| 50. |
47-447a + V3b तोऔर 6 का मान ज्ञात करें। |
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Answer» 5+V3/7-4V3 5+V3/7-5√3 X 7+5√3/7+5√ 3. =(5+√3)(7+4√3)/. (7+4√3/)(7-4√3). =. (5+√3)(7+4√3)/(7)^2-(4√3)^2 = (35+20√3+7√3+(4√3)^2) / (49-16*3). =(35+27√3+16(3))/(49-48). =*(35+48+27√3)/1 =. = (83+27√3) |
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