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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
13, 0 LI 22s0 |
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Answer» hi |
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| 2. |
The product of two positive integers p and q is 100. What is the largest possible value of p+q? |
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Answer» PQ = 100 ==> P = 100/Q.S = P + Q = 100/Q + Q. By differentiating:dS/dQ = 1 - 100/Q^2. Then, setting dS/dQ = 0 gives:1 - 100/Q^2 = 0Q^2 - 100 = 0 Q^2 = 100 Q = 10.(Pick Q > 0 as we require positive integers) Then, since 1 <= P, Q <= 100, we see that the critical values are:(P, Q) = (10, 10), (1, 100), and (100, 1). We see that the maximum sum occurs when (P, Q) = (1, 100) or (100, 1), which gives 101. |
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| 3. |
7.If two positive integers p and q are written as p ab and q a b; a, b are primenumbers, then verify:LCM (p, q) x HCF (p, pq |
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Answer» Like my answer if you find it useful! |
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| 4. |
9. If two positive integers p and q are written as p=a2b3 and q=aba, b are primenumbers, then verify: LCM (p, q) x HCF (p, q)- pq. (CBSE 2017-2M) |
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Answer» p = a²b³ q = a³b HCF ( p,q ) = a²b [∵Product of the smallest powerof each common prime factors in the numbers ] LCM ( p , q ) = a³b³ [∵ Product of the greatest power of each prime factors , in the numbers ] Now , HCF ( p , q )× LCM ( p , q ) = a²b× a³b³ = a∧5b∧4 --------( 1 ) [∵ a∧m× b∧n = a∧m+n ] pq = a²b³× a³b = a∧5 b∧4 ---------------( 2 ) from ( 1 ) and ( 2 ) , we conclude HCF ( p , q )× LCM ( p ,q ) = pq |
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| 5. |
If two positive integers p and q are written as p a b' and q a'b; a, b are primenumbers, then verify:LCM (p, q) x HCF (p, q)p2n Find the sixteenth term of |
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Answer» p = a*ab*b q = a*a*ab LCM(p,q) = a*a*ab*b HCF(p,q) = a*ab LCM(p,q)*HCF(p,q) = a*a*ab*b*a*ab = a*ab*b*a*a*ab = pq |
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| 6. |
18Sahitya Bhawan Sample Paper (Issued by CeSECTION B7. If twopositive integers p and q are written as p a2b3 and q ab; a,b are prime numbers, then vriLCM (p, q) x HCF (p, q) pq. |
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| 7. |
Question numbers 7 to 12 carry 2 marks each.If two positive integers p and q are written as p a bnumbers, then verify:and q ab; a, b are prime7LCM (p, q) x HCF (p, q)-pq |
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Answer» p = a²b³ q = a³b HCF ( p,q ) = a²b [∵Product of the smallest powerof each common prime factors in the numbers ] LCM ( p , q ) = a³b³[∵ Product of the greatest power of eachprime factors , in the numbers ] Now , HCF ( p , q )× LCM ( p , q ) = a²b× a³b³ = a∧5b∧4 --------( 1 )[∵ a∧m× b∧n = a∧m+n ]pq = a²b³× a³b = a∧5 b∧4 ---------------( 2 )from ( 1 ) and ( 2 ) , we conclude HCF ( p , q )× LCM ( p ,q ) = pq |
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| 8. |
60. To complete a work, A takes 50% more time than B. If togenethey takes 18 days to complete the work, then B takes the time todo the work in : |
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Answer» We have,B =3/2*A→A =2/3*BOne day's work, (A+B) =1/18(2/3* B + B) =1/185/3*B =1/18One day's work of B =3/90B alone can complete the work in,=90/3= 30 days. |
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| 9. |
(3) 72 72(4) 78#ou. To complete a work, A takes 50% more time than B. It togetherthey takes 18 days to complete the work, then B takes the time todo the work in : |
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Answer» We have,B =3/2*A→A =2/3*BOne day's work, (A+B) =1/18(2/3* B + B) =1/185/3*B =1/18One day's work of B =3/90B alone can complete the work in,=90/3= 30 days. |
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| 10. |
60. To complete a work, A takes 50% more time than B. If togetherthey takes 18 days to complete the work, then B takes the time todo the work in : |
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Answer» We have,B =3/2*A→A =2/3*BOne day's work, (A+B) =1/18(2/3* B + B) =1/185/3*B =1/18One day's work of B =3/90B alone can complete the work in,=90/3= 30 days. |
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| 11. |
0Li |
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Answer» sinA + cosA √2(sinA/√2 +cosA/√2) = √2(sinπ/4sinA + cosπ/4cosA)= √2cos(A-π/4) |
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| 12. |
LI |
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Answer» 1/17 = 0.0588235294,which decimal form of 1/17 |
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| 13. |
Mr. Gonzales needs to be to the movie theater at 6:00 pm. If it takes him 42 minutes to get there, what time must he leave? |
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Answer» 5:18 5:8 5:18wo wala galti se ho gaya tha....... 5 : 18 pm. |
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| 14. |
18)Resolve .info pa rRolă.octorn2. |
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Answer» thanks |
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| 15. |
nvert the following factions info deci1/2 |
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Answer» The answer is :- 1/2=0.5 |
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| 16. |
A photograph measuring 25 cm by 20 cm is mounted on a rectangular sheet of cardboard keeping a uniform border 6 cm wide, all around the photograph. Find the area of the border. |
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| 17. |
of the pupils in the info club are boys. If there are 30 girls in the info club, howboys are there?(A) 18(B) 48(C) 50(D) 801There were 810 apples in a basket. Karan gave of them to Kawai andremainder to Sapna. How many apples did he have left?(A) 360 apples(C) 540 apples(B) 450 apples(D) 630 apples |
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Answer» (1)suppose there are x pupilsso 3x/8 boysand 5x/8 girlsNow girls are 30.5x/8=30so x=48so total boys 3×48/8=18(2)Initially 810 apples1/3 of given to kawal so 810-810/3=540 left1/6 given to Sapna so 540-540/6=450 leftso 450 apples left |
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4. The area of a rhombus is 1080 m2 and one ofits diagonals is 72 m. What is the perimeter ofthe rhombus? |
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| 19. |
a+b+c=4√3,a×a+b×b+c×c=16,finda:b:c=? |
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| 20. |
Replace by the sanestli 5897x is divisibie by 3. ind all the possible values of digit x |
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Answer» Concept:When a number is divisible by 3 then sum of its digits must be divisible by 3. Here we have 5897x so,5+8+9+7+x = 29 + x must be divisible by 3 So, x can be 1, 4, 7. Hit like and share this app |
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| 21. |
Sudhir borrowed rupees 1600 at 12 percent simple interest per annum. How much should he pay at the end of 2 years 10 months to clear his debt? |
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Answer» time = 2 10/12 years = 2 5/6 years simple interest = 1600*12*17/6*100 = 16*2*17 = 544 rupees |
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| 22. |
12. If 72401, then 7n-5-(3) 7(4) 497 |
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| 23. |
-400000 %2B 2 |
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Answer» the right answer is 399999 388888 the right answer |
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| 24. |
he time taken by a person to cover 150 km was2hrs. more than the time taken in the return. T2journey. If he returned at a speed of 10 km/h morethan the speed of going, what was the speed per hourin each direction? |
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18. The train taken by a person to cover 150 km was2hours more than the time taken in the return2journey. If he returned at a speed of 10 km/hrmore than the speed while going, find the speedper hour in each direction. |
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| 26. |
3Lakh+400000÷40 |
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Answer» twelve thousand five hundred12,500is the right and |
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EXERCISE 20.1. A flooring tile has the shape of a parallelogram whose base is 24 cm and thecorresponding height is 10 cm. How many such tiles are required to cover a floor ofarea 1080 m2? |
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dooring tile has the shape of a parallelogram whose base is 24 cm and theesponding height is 10 cm. How many such tiles are required to cover a loor ofUI3L 20.11 A floarea 1080 m2? |
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s the shape of a parallelogram whose base is 24 cm and theeight is 10 cm. How many such tiles are required to cover a floor ofuired you can split the tiles in whatever way you want to fill uptile ha4. A flooringcorresthe corners). |
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| 30. |
3,Replace□in each ormd7□ (b) |
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Answer» 2/7=8/28 |
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| 31. |
(vii) FRT 2x2+x-6=0 R(Discriminant) & : 1 49 ® 7© -12 (D) इनमें से कोई नहींएप७८पंफ्संघशणा एव हतूपशणा 2: *ै+ ऋण 6 न 015:(5) 49 ® 7© -12 (D) of these |
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Answer» D= b^2-4ac= (2)^2-4*2(-6)4-(-48)= 52Option D |
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| 32. |
- 5% of 400000?A) 4000OB) 16000C) 8000D) 20000 |
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| 33. |
Replace x-by the smallest no. to make it divisible by 3.432 x71 |
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Answer» to be multiple by 3, the sum of numbers must be a multiple of 3 4+3+2+7+1 = 17 + 1 = multiple of 3 The number x is 1 |
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| 34. |
9 a ^ { 2 } + 4 b ^ { 2 } + 16 c ^ { 2 } + 12 a b - 16 b c - 24 c a |
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Answer» tq very much actually I didn't got the sum I am confusing at changing of symbols and taking common |
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| 35. |
Factorise: \frac { 16 } { 9 } x ^ { 2 } - \frac { 1 } { 4 } y ^ { 2 } |
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Answer» 16x²/9 - 1y²/4 (4x/3)² - (y/2)² (4x/3 - y/2) ( 4x/3 + y/2) |
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| 36. |
National Fruit |
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Answer» mango is our India's national fruit mango is our national fruit |
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| 37. |
The length of the minute hand of a clock is 14cm. Find the area covered by the minute hand on thecircular dial in an interval of 20 minutes.(Conn) |
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Answer» length= 14 cm Minutes = 20 (1 min = 6 degree) Angle = 20 * 6 = 120 degree Area = π * r^2 * (θ/360) = 3.14 * 14 * 14 * ( 120 /360 ) = Area = 205.14cm^2 |
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| 38. |
0.The time taken by a person to cover 150 km was 2 hours more than the time taken inthe return journey. If he returned at a speed of 10 km/h more than the speed while going,find the speed per hour in each direction. |
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| 39. |
1%+1ege one and Iational Iicorne7. How does the rise of the Multinational Companies affect the poor workers? Explain |
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Answer» Nowadays the growth in multinational companies has been a great affect in poor because these multinational companies get the agricultural land of these poor farmers and they also affect their job . farmers are already struggling from various problems and the interference of these multinational companies are a great sin in their life . let us all help the farmers |
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| 40. |
a flooring tiles has the shape of parallelogram whose beseech 24 cm and corresponding height is 10centimetre how many such tiles are required to cover law of area 1080 m square |
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Answer» nice ans. |
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| 41. |
the volumes of two squares are in the ratio 64:27. the ratio of their surface area isa)1:2b)2:3c)9:16d)16:9 |
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Answer» how you prepare this ans quickly |
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| 42. |
3. Sudhir borrowed 400000 at 12% per annum from a money lender. At the end of threeyears he cleared the account by paying 260000 and a diamond necklace. Find the cost ofthe necklace.After 12 monthcho doared his account by paying |
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Answer» 400000/260000.12%so find it |
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| 43. |
Radha purchased a ear ring for 800.70 and a gold chain foräš2000and bangles for 25.00. How much money did she spend in all? |
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Answer» ear ring cost is 800.70gold chain cost is 2000Bangles cost is 25.00 total spend equal to800.70 + 2000 + 25.00 = Rs. 2825.70 |
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| 44. |
20Q.16 What is the area of trapezium given in Figure:꾏cm2 |
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Answer» a=10cmb=8cmh=7cmarea of trapezium=1÷2(a+b)×h1÷2(10+8)×71÷2×18×71×9×763cm |
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| 45. |
4. Find the area of the region bounded by the ellipse x^2/16+y^2/9=1 |
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| 46. |
14.What are various evidences to trace evolutionary relationships ? |
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Answer» Thus, the homologous and analogous characteristics helpto traceanevolutionary relationshipbetween different species. We use living speciesto trace evolutionary relationships. ... They can be used fortracingtheevolutionary relationshipbetween species. Fossils are one of the examples |
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| 47. |
A pearl necklace has 52 pearls. How many pearls are therein 7 necklaces? |
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Answer» 1 necklace has 52 pearls. So, 7 necklace has 52×7 = 364. |
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| 48. |
a flooring tile has the shape of parallelogram whose base is 24cm and the corresponding height is 10 cm how many such tiles r required to cover a floor of area 1080 metre square if required you can spell it the tiles in whatever way you want to fill up the corners |
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Answer» kal chudana |
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| 49. |
A pearl necklace has 52 pearls. How many pearls are therein necklaces? |
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Answer» 1 necklace has 52 pearls.So, 7 necklace have 52×7=3664 pearls. 364 is the right answer# |
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| 50. |
ALGEBRAIC EXPRESSIONSCLAPEARL PACKAGEb) -8 xya) -12xy(5 p2oYa) 10 p2 q32.b)25 p.3.5x=a) 5 ×xb) |
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Answer» please crop the image before you post it it would be easy to answer the questions for you |
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