3. ABCD is a parallelogram with area 80 sq. cm.the diagonal AC and BD

1.	3. ABCD is a parallelogram with area 80 sq. cm.the diagonal AC and BD intersect at o.P is the mid-point of OA.Calculate ar (ABOP).0
Answer» area of parellalogram ABCD = 80sq cm. we know diagonal of parellaogram divides it 2 traingle of equal area so area of [ABD] = [DBC] = 40 sq cm. BD & AC are the diagonals & we know diagonals bisect each other. So, area of [AOD] = [BOA] = 40÷2 i.e. 20 sq. cm. P is the mid point of OA it means BP is the median of [ABO] & we know median divides triangle in 2 of equal area so, ar[BOO] = ar[ABP] = 10 sq cm. Hence, ar[BOP] = 10 sq cm. hit like if you find it useful

3. ABCD is a parallelogram with area 80 sq. cm.the diagonal AC and BD intersect at o.P is the mid-point of OA.Calculate ar (ABOP).0

Answer»

area of parellalogram ABCD = 80sq cm.

we know diagonal of parellaogram divides it 2 traingle of equal area so area of [ABD] = [DBC] = 40 sq cm.

BD & AC are the diagonals & we know diagonals bisect each other.

So, area of [AOD] = [BOA] = 40÷2 i.e. 20 sq. cm.

P is the mid point of OA it means BP is the median of [ABO] & we know median divides triangle in 2 of equal area so, ar[BOO] = ar[ABP] = 10 sq cm.

Hence, ar[BOP] = 10 sq cm.

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