Saved Bookmarks
This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
A sol id tot is inJor calindes withaand a Cone at end This Commen diameks 42 m and the heigkt ol the cyedindhical and Cenicala hemispherical Shape at one endthe othePo tions are 10 om and t om Respectively Find the Volumea the lo lid to |
|
Answer» Height of the conical portion = 7 cm and height of the cylindrical portion = 12 cm Radius = Diameter/2 = 4.2/2 = 2.1 cm Volume of the solid toy = Volume of the conical portion + Volume of the cylindrical portion + Volume of the hemispherical portion ⇒1/3πr²h +πr²h + 2/3πr³ ⇒ (1/3*22/7*2.1*2.1*7) + (22/7*2.1*2.1*12) + 2/3*22/7*2.1*2.1*2.1 ⇒ 679.14/21 + 1164.24/7 + 407.484/21 ⇒ (32.14 cu cm) + (166.32 cu cm) + (19.404 cu cm) ⇒ 217.864 cu cm Like my answer if you find it useful! |
|
| 2. |
2.Simplify each of the following expressions:o (3+3) (2+2)(3+ V1 |
|
Answer» thanks |
|
| 3. |
The number of constant functions possiblfrom R to B where B- 2,4,6,8,..24) are1) 24 2) 125053) 84) 6 |
|
Answer» Number of Constant functions possible in this case = Number of elements in set B Elements in set B forms an AP with First term, a = 2; Common Difference, d = 2 Let n be the number of elements in set B. Thus, 24 = a +(n-1)d = 2 + (n-1)d 22 = (n-1)*2 (n-1) = 11n = 12 Therefore, there are 12 elements in B and thus the total constant functions are 12. Hence, Option 2 is correct |
|
| 4. |
Cassiry the following numbers as rational or irrational:02-55m (3 + V23) – 23 ( 217(v) 211(iv)lifurch of the following expressions: |
|
Answer» option 1, option 5, option 4 are irrational and option 2 and 3 are rational |
|
| 5. |
EXERCISE 2./butionable and we valy1. Which of the following expressions are polynomials in one vpor State reasons for your answer.42-3ct?(vy + 2(i) 3/1 + 12 |
|
Answer» 3 and 4 is correct according to me this answers is correct |
|
| 6. |
Find an irrational between 3 and 5. |
| Answer» | |
| 7. |
e the following expressions.(i) a2 + 8a + 16 (i)-10 |
|
Answer» a² + 8a + 16 a² + 2 × 4a + 4² (a + 4)² |
|
| 8. |
Write the constant term of each of the following algebraic expressions0) 6x + 2ii) s(vill x +6x-9(v) 3e-4x+5 ((vi) 6-x'+ 3y |
|
Answer» (i)2(ii)-7(iii)8(iv)5(v)6(vi)-9 |
|
| 9. |
ercise 9.1Identify the terms, their coefficients for each of the following expressions(iii) 4x2y2 4x2y2z" + 1(vi) 0.3a -0.6ab+0.56IVg+qr-p (v |
| Answer» | |
| 10. |
What is the ratio of the volume of the new cylÄąnder ll Ol Il UNI1. A rectangular piece of tin of size 30 cm x 18 em is rolled in two ways, once along itslength (30 cm) and once along its breadth. Find the ratio of volumes of two cylindersso formed.lindrical pipe of internal diameter 7 cm at 5 m per sec. |
|
Answer» If you find this solution helpful, Please give it a 👍 |
|
| 11. |
हा.” Mars 2 ol 5 2w 6००"'&LLGAK'_L“%[;E& cnee. 3 |
| Answer» | |
| 12. |
Ol tHe cylinderparticular brand of talcum powder is available in two packs. a plastic can with a squarebase of side 5 cm and of height 14 cm, or one with a circular base of radius 3.5 cm and oheight 12 cm. Which of them has greater capacity and by how much?12. A13. Find the cost of naintin 1 |
| Answer» | |
| 13. |
Eind the value ol5^{5 / 9} |
| Answer» | |
| 14. |
12. Vikas spent 78% of his salary and saved?5500. Find his salary. |
| Answer» | |
| 15. |
The probability of getting a rotten egg from a lot of 400 eggs is0.25. Find the numbers of the rotten eggs. |
|
Answer» Probability is 0.25 that is 25%hence 25% of 400400*25/100=25*4=100 eggs are rotten thanks bhai |
|
| 16. |
Show that the product of the perpendicular distances from a point (ι, β) to the pair of10.by-0 is (a-b)a-b) +4h Maro4, 07, May-07,08,201b? 4h2 (Mar-04, 07, May-07,08,2011)ent nes 2hy |
|
Answer» this is part 1 of soln this is part 2 of soln |
|
| 17. |
NESAND ANGLES6.14, lines XY and MN intersect at o.POY = 90° and a : b = 2 : 3, find c97 |
| Answer» | |
| 18. |
ofthelinepoint (4. 6.Find the equation of the circle passing through the point of intersectionrth#0and2x7y 0and whose centre is the point of intersection of the linrty+1 0and x -2y +4 0.nes. Aitive direction of u-avi |
| Answer» | |
| 19. |
sugar should we use?Salaries of Ravi and Sudhir are in the ratio 2:3. If the salary of each is increased bybecomes 40 : 56. What is Sudhir's salary?4000 the nes |
|
Answer» please like my answer if you find useful |
|
| 20. |
ABCandDEFABDCandABIDE; BC = EF and BCI EF. Vertices A, B=,and C are joined to vertices D, E and F respectively (see figure). Show that(i) ABED is a parallelogram(ii) BCFE is a parallelogram(iii) AC=DF(iv)ΔΑ BCΔDEF |
|
Answer» thanks for answer |
|
| 21. |
7.The area of a square is numerically less than six times its side.List some squares in which this happens. |
| Answer» | |
| 22. |
Find 3 irrational nes butiveen3 and 5. |
|
Answer» √3 = 1.732......√5 = 2.236.....The numbers which can be expressed in the form of p/q, where q ≠ 0 are called rational numbers. A terminating decimal and a non-terminating non-repeating decimal can be represented as a rational number.Therefore, a rational number between √3 and√5 is 2. |
|
| 23. |
MATHSSHORT QUES:1. Zero hasreciprocal.2. The reciprocal of a positive number is3. Represent these numbers on the number line:1) 774ii) -5/64. The product of two rational numbers is always a5. Find ten rational numbers between 3/5 and 4. |
|
Answer» (1)no reciprocal (2)negative no is it's reciprocal (4)rational noagbjc reciprocal of zero, 1/0 is infinity. reciprocal of positive number is also a positive number.7/4 and-5/6 can be represented by this method, product of two rational numbers also an rational, |
|
| 24. |
3. The area of AACD in Fig. 13.47 is 8cm2.IfEF 4cm,find the altitude of le BCFE.E D FFig. 13.47 |
| Answer» | |
| 25. |
The volume of a cube is 512 cm2. Find its surface area. |
| Answer» | |
| 26. |
The base of a parallelogram is twice its height. If the area of the parallelogram is 512 cm2,findthe base and height.10. |
| Answer» | |
| 27. |
0. The base of a parallelogram is twice its height. If the area of the parallelogram is 512 cm2, findthe base and height. |
| Answer» | |
| 28. |
14. The base of a parallelogram is twice its height. Itsarea is 512 cm2, find its base and height.15. Afloral design on the floor of a building consistsof 2800 tiles. Each tile is in the shape of aparallelogram of altitude 3 cm and base 5 cm. Findthe cost of polishing the design at the rate of 50paise per dm |
| Answer» | |
| 29. |
SHOC1511 x333Section CQ 13. Rashid spent Rs. 35.75 for Maths book and Rs. 32.60 for Science book.Find the total amount spent by Rashid.dotn nf choice of food by 50 people in a locality |
|
Answer» Amount spent by Rashid for maths book = Rs 35.75 Amount spent by Rashid for Science book = Rs 32.60 Total amount spent = 35.75 + 32.60= Rs 68.35 |
|
| 30. |
I have Rs. 50 with me. I spent 12% of the sum of Rs. 50 to purchase a pen.work out the amount I spent for purchasing the pen |
|
Answer» pen' s amount= 50*12/1006 rupeesremaining amount =44 rupees |
|
| 31. |
1. From a wholesaler, Santosh bought400 eggs for R 1500 and spent 300 ontransport. 50 eggs fell down and broke.He sold the rest at 5 each. Did hemake a profit or a loss? How much? |
| Answer» | |
| 32. |
) यदि sin 0 = 2, तो cos 0 और tan e के मान ज्ञात करें |
|
Answer» cos theeta=3/5,tan theeta=4/3 sinx = 4/5; ( adj)^2=(5)^2-(4)^2= 25-16=9, adj = 3; cosx = (3/5); tan x = (4/3) cosx=3/5 and tanx=4/3 is the right answer cos x=3/5 and tanx=4/3 is the answer by using trigonometry ratios |
|
| 33. |
1. From a wholesaler, Santosh bought400 eggs for 1500 and spent 300 ontransport. 50 eggs fell down and broke.He sold the rest at 5 each. Did hemake a profit or a loss? How much? |
| Answer» | |
| 34. |
cost Rs 36 per dozen. How much will 1S esgs cost?Eggs |
| Answer» | |
| 35. |
A man buys 5 dozen eggs at 36 per dozen. Out of which 5% got brremaining eggs for 48 per dozen. What was his total gain? |
|
Answer» CP = 5 x 36= 180total number of eggs = 5x 12= 60number of broken eggs= 5/100 x 60=3remaining eggs = 60-3 = 57Now number of dozen = 57/12 =( 4+ 3/4) dozencost of 4 dozen = 48 x 4= 192cost of 3/4 dozen = 3/4 x 48 = 36total money = 192 + 36 = 228gain = 228 - 180 = 48 |
|
| 36. |
4. A man buys 5 dozen eggs at 36 per dozen. Out of which 5% got broken. He sold theremaining eggs for 48 per dozen. What was his total gain? |
|
Answer» answer is 62 this is wrong Cost price of eggs CP = 5*36= Rs 180 Now,5% eggs get broken So, remaining eggs= 5*12(1 - 5/100)= 60 * 19/20= 19*3= 57 Now selling price of 12 eggs= 48Selling price of 1 egg = 48/12= 4 Selling price of 57 eggs SP= 4*57 = Rs 228 Total gain = SP - CP= 228 - 180 = Rs 48 |
|
| 37. |
A man buys 5 dozen eggs at 36 per dozen. Out of which 5% got broken. He sold theremaining eggs for 48 per dozen. What was his total gain? |
| Answer» | |
| 38. |
Due to an increase of 30% in the price of eggs, six eggs less are available for Rs 7.80. The presentrates of eggs per dozen is ? |
|
Answer» price is increased by 30% so130% *7.8 - 7.8 = 2.34 is rate for 3 eggsprice of 1 egg is 0.78for 12 eggs = 0.78*12 = 9.36 |
|
| 39. |
\begin{array} { l } { \text { Find the ratio of the price of banana to that } } \\ { \text { of an egg. If bananas cost ? } 18 \text { per dozen } } \\ { \text { ind the eggs cost } 3125 \text { per hundred. } } \end{array} |
| Answer» | |
| 40. |
Divide the following.1. (i) 12x2 by 3x(iv) a2b3c4 by - 5 a4b5c2. (a + 4 a + 3a“) by 4a4.7 - 38 + 1 / ² by 3y6. (20a - 16a²b + 4b2) by 4a2 |
|
Answer» 1.(i) 4x (iv) c^3/-5a^2b^22. (1+4a^2+3a^3)/4 36x³ is right answer (i)4x is the right answer for this question this and is same like 16x is the answer because 12x/3x=4x, now power of two =4x x 4x=16x ANS 1. 12x^2 by 3x2×2×3×x×x/3×x cut 3 and x by 3 and x after cutting4x is the answer. I) =4xif)!=-5a^2b^2 a-4xb-5aabbccc3yyy-3yyy +one by two you 1) 4x iska answer 4x hi hoga 1.(i) 12x² by 3x=12x²/3x=4x 1.(i)4x(iv)c^3/-5a^2b^22.(1+4a^+3a^3)/44.y/3-y+1/6y 1.(I) 4x^2 (iv) 5a^2b^2c4 2.a^23*#+-&+-~×× 1. (4x) answers no 1 1)(i) 4x is right answer 1.(i)ans(4x) (iv)ans (-c*c*c/5a*a*b*b)2.ans (1/4+a*a+3*a*a*a/4)4.ans( y*y*y/3-y*y+y/6)6.ans (5a/b-4+b/a*a) 1. (i). 4x (iv). c ^3/5a^2b^22. 1+4a^2+3a^3/44. 2y^3-6y^2+y/66. 5a^3-4a^2b+b^2/a^2b question no 1 ans 4x 1.) 4X is the correct answer 36x³ is the best answer 12x²/3x=4xis the best answer a²b³c⁴/5a⁴b^5ca²b²c³is the best answer answer are:-1(i).4x(iv). c³/-5a²*b²2. (1+4a²+3a³)/4 1. i-4x.iv-c ^3/5a^2 b^2 download solution Book from play store 1.(i) 4x (iv) - c3/5a2b22.(1+a2+3a3)/44. 1) i)4x iv) -c3 /5a2 b22)1/4+a2+3a3/44)y3/3-y2+y/6 |
|
| 41. |
:- What are life processes? |
|
Answer» Alllivingthings performlife processes, which areprocessesthat the organism completes that are necessary to keep it alive and functioning well. Theselife processesinclude nutrition, excretion, reproduction, movement, respiration, growth, and sensitivity. Please hit the like button if this helped you. |
|
| 42. |
1.What are life processes? |
|
Answer» Ans :- Alllivingthings performlife processes, which areprocessesthat the organism completes that are necessary to keep it alive and functioning well. Theselife processesinclude nutrition, excretion, reproduction, movement, respiration, growth, and sensitivity. |
|
| 43. |
5. Find four rational numbers between „ andą.al |
|
Answer» and 19/35 |
|
| 44. |
and7. Find four rational numbers between |
|
Answer» To find 4 rational numbers between - 1/7 and 2/7 Divide and Multiply each rational number by 2 Then,-1/7 = - 1*2/7*2 = - 2/142/7 = 2*2/7*2 = 4/14 Therefore,Four rational numbers between - 2/14 and 4/14 are - 1/14, 1/14, 2/14, 3/14 |
|
| 45. |
s. Find four rational numbers betweenand |
|
Answer» 3/7*5/5=15/355/7*5/5=25/35ration numbers are 16/35, 17/35 ,18/35 ,19/35........24/35 |
|
| 46. |
10. If coseco2. show that (cot 0 + sin02.It coso) 2. |
|
Answer» Sinx=1/2; cos x =-1/2; (cot x +sinx/1+cosx)=(1+1/2/1-1/2)=(2+1/2/2-1/2)=2 |
|
| 47. |
(6) 10(4) 3If o be acute and tan 6 + cot 0 = 2, then the value of tanocotto o is. |
|
Answer» tan theta + cot theta = 2tan theta + 1/theta = 2tan^2 theta + 1 = 2tan thetatan^2 theta + 1^2 - 2tan theta = 0(tan theta - 1)^2 = 0tan theta = 1tan theta = tan 45theta = 45° Therefore,Value of tan^5 theta + cot^10 theta = tan^5 45° + cot^10 theta= (1)^5 + (1)^10= 1 + 1= 2 |
|
| 48. |
35. Find four rational numbers betweenand |
|
Answer» 4 rational numbers between 3/7 and 5/73.5/7,4/7,4.5/7,4.6/7 |
|
| 49. |
4. For what value of k will k +9,2k-1and2k + 7 are the consecutive terms of an AP? |
| Answer» | |
| 50. |
Q 6: IfanBC ~ ΔΡ。R arAABC) = 16 cm2 and ar(APQR) = 81 cm, AB = 2 cm find PQ. |
|
Answer» 16÷81=AB^2÷PQ^216÷81=2^2÷PQ^2PQ^2=4×81÷16PQ^2=81÷4PQ=9/2 |
|