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(6) 10(4) 3If o be acute and tan 6 + cot 0 = 2, then the value of tanocotto o is. |
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Answer» tan theta + cot theta = 2tan theta + 1/theta = 2tan^2 theta + 1 = 2tan thetatan^2 theta + 1^2 - 2tan theta = 0(tan theta - 1)^2 = 0tan theta = 1tan theta = tan 45theta = 45° Therefore,Value of tan^5 theta + cot^10 theta = tan^5 45° + cot^10 theta= (1)^5 + (1)^10= 1 + 1= 2 |
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