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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
name two types of graphs other than line graphs |
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Answer» pie chart and bar graph two types of graphs other than line graphs are bar graph and pie chart |
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| 2. |
5. Prove that it secco-DameIt see o* tanol-ainecase |
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Answer» Sol:-L.H.S = 1 + secA – tanA / 1 + secA + tanA , R.H.S =1 – sinA / cosA = L.H.S(sec2A – tan2A) + secA – tanA / 1 + secA + tanA As we know that [sec2A – tan2A = 1] Here, L. H. S= (secA – tanA) (secA + tanA) + (secA – tanA) / 1 + secA + tanA L.H.S = (secA – tanA) (1+secA + tanA) / 1 + secA + tanA L.H.S = secA – tanA We know about the formula of secA and tanA,[secA = 1 / cosA], [ tanA = sinA / cosA] putting the value of secA and tanA so = 1 / cosA - sinA / cosA L.H. S= 1 – sinA / cosA So here L.H. S is equal to R.H.S....Proved |
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| 3. |
The radii of two concentric circles are 13 cm and & 8 cmAB is a diameter of the bigger circle. BD is a tangento the smaller circle touching it at D. Find thelength ADA. 19 cmB. 15 cmC. 17 cmD 13 cm |
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Answer» GIVEN: 2 Concentric circles with centre O. Radius OB of bigger circle = 13cm, Radius OD of smaller circle = 8cm. EB is tangent to the inner circle at point D. So, OD is perpendicular to EB.( as tangent is perpendicular to the radius segment through the point of contact.) Construction: Join AD & Join AE. PROOF: In right triangle ODB DB² = OB² — OD² ( by pythagoras law) DB² = 13² — 8² = 169 — 64 = 105 => DB = √105 => ED = √105 ( as perpendicular OD from the centre of the circle O, to a chord EB , bisects the chord) Now in triangle AEB, angle AEB = 90°( as angle on a semi circle is a right angle). And, OD // AE & OD = 1/2 AE ( as, segment joining rhe mid points of any 2 sides of a triangle is parallel to the third side & also half of it. So, AE = 16cm Now, in right triangle AED, AD² = AE² + ED² => AD² = 16² + (√105)² => AD² = 256 +105 => AD² = 361 => AD = √361 = 19cm |
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| 4. |
27.The radii of two concentric circles are 13cm and 8 cm. AB is a diameter of the biggercircte. BD is a tangent to the smaller circletouching it at D. Find the length AD. |
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Answer» To know AD,we need to know AC & CD. To findthem, we need BC and BD first. Given OA=OB = R ,OD= r Let theradii of circles be R & r. R > r.R= 13cm r = 8cm. Finally: AD =√(R²+3 r²) =√(13²+3*8²) = 19 cm |
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| 5. |
Anu bought a hair dryer forsold it for 2400. Find the gainPercentage.2.2000 and |
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Answer» PLEASE LIKE IT, IF YOU FIND THE ANSWER HELPFUL. |
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| 6. |
Anu bougn0. 6 bananas were bought for ? 5 and sold at 5 for 6. What is the Gain? |
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| 7. |
400 on its transportation. He sold it for4. Sudhir bought an almirah for 136016800. Find his gain per cent.O and spent11500g on its renairs Then,he sold |
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| 8. |
shubham deposited ₹1500 in his savings bank accounts find the compound interest earned by him after 3 year at the rate of 4% per annum |
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Answer» ɢɪᴠᴇɴ ----ᴩ = ₹ 1500ʀᴀᴛᴇ = 4%ᴛɪᴍᴇ = 3 yᴇᴀʀꜱᴄɪ = ??? ᴀꜱ ᴡᴇ ᴋɴᴏᴡ ,ᴄɪ = ᴩ(1+i)^n -ᴩ ꜱᴏ , CI = 1500 ( 1+0.04)^3 - 1500= 1500 ( 1.04)^3 - 1500= 1500( 1.124864) -1500= 1687.296 - 1500= ₹ 187.296 ꜱᴏ ᴛʜᴇ ᴄɪ ᴇᴀʀɴᴇᴅ ʙy ꜱʜᴜʙʜᴀᴍ = ₹187.296 |
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| 9. |
21. Dnesh sold his motorcycle to Naveen at a loss of 28%, Naveen spent 1680 on its repairs and soldmotorcycle to Saran for 35,910 making a profit of 12.5%. Find the cost of the motorcycle for Din |
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| 10. |
lf sec theta + tan theta = p then find the value of cosec theta |
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Answer» The value of cosec theta is p^2+1/ p^2-1 |
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| 11. |
Ravi sold his car to Sunil at a loss of 28%. Sunil spent5,040 on its repairs and sold the car to Rahul for1,07,730, thereby making a profit of 125%. Find thecost of the car for Ravi. |
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Answer» Let CP of dinesh motorcyvle = Rs xSP of dinesh motorcycle = (72/100) x = 0.72 x [There is a loss of 28%]CP of saran motorcycle including the cost of repairs = (0.72x + 5040)SP of saran motor = Rs 107730Profit Percentage = 12.5% [(107730) - (0.72x + 5040)] x 100 / (0.72x + 5040) = 12.5/100 ⇒ x= 140777.7 |
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| 12. |
8. Find the area of a regular hexagon ABCDEF in which each side13 cmmeasures 13 cm and whose height is 23 cm, as shown in thegiven figureHint. Let AL DM x. LM BC 13 cmIL13 cImIMlx23 cmFL2A(13)2 52 (169 25) 144FL 12 m.area of the given hexagon 2 x (area of trap. ADEF) |
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| 13. |
Find the area of a regular hexagon ABCDEF in which each side is equal to 13 cmand whose height is 23 cm, as shown in the figure below.2.13 cm23 cm13 cm |
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| 14. |
5. Find the area of the following regular hexagon.M i23 cm13 cmFig. 20.52 |
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| 15. |
Poge NoDadsGiven that tano 12 tan2prove that Cos2d + cos2 O |
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| 16. |
प्रश्न 5. ८०४० 15? - 0 15" का मान होगा :i F pog |
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| 17. |
14. Im trapezium ABCD, AB AD BC 13 cm and CD 23 cm. Find the areatrapezium. |
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| 18. |
ages of mother and her daughter is 50 years. After 20 yearsmother's age will be twice her daughter's age at that time. Find their present ages. |
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| 19. |
In given figure ABCD is a trapezium in which AB Il DC and DA L AB. If AB 13AD 8 cm and CD -7 cm, then find area of trapezium.13 |
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| 20. |
15. In the given figure, a circle with centre Ois inscribed in a quadrilateral ABCD suchthat it touches the side BC, AB, AD andCD at points P. Q. R and S respectively. SIf AB 29 cm, AD 23 cm, B 90 andDS-5 cm then find the radius of thecircle.CBSE 2008, 13] |
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| 21. |
A merchant has three kinds of milk : 435 litres, 493 litres and 551 htres. 1f casks of equal size required to store all the milk without mixing,A wholesale tea dealer has 408 kg, 468 kg and 516 ky of three different qyit all to be packed into boxes of equal size without mixing, Find thepossible box.mased Question |
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| 22. |
A merchant has 120 litres of oil of one kind, 180 litres of another kind and 240 litres of third kind. FHe wantsthe oil by filling the three kinds of oil in tins of equal capacity. What should be the greatest capacityto sellof such a tin?nd of the field whil |
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| 23. |
\begin{array} { l } { \text { In square PQRS: } } \\ { \text { (i) if } P Q = 3 x - 7 \text { and } Q R = x + 3 ; \text { find PS. } } \\ { \text { (ii) if } P R = 5 x \text { and } Q S = 9 x - 8 \text { . Find } Q S \text { . } } \end{array} |
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| 24. |
Tens Ones |
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Answer» the answer of your question is 89 |
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| 25. |
a b-=-b+c C+ ac=_+ band a + b + C+0 then the value ofb-- is:a + b + c(d) 11of 3 kinds of petrol PP, and P, is |
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| 26. |
p : q = 4 : 9 \text { and } q : r = 2 : 5 , \text { find } p : q : r |
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| 27. |
Poge NoDate3 |
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| 28. |
sum of the present ages of mother and her daughter is 50 years. After 20 years,mother's age will be twice her daughter's age at that time. Find their present ages |
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Answer» Let daughter present age = xThen mother present age = 50 - x After 20 yearsMother age = (50-x) + 20Daughter age = x + 20 As per given condition70 - x = 2(x + 20)70 = 2x + x + 403x = 30x = 30/3 = 10 Therefore,Daughter present age = x = 10 yearsMother present age = 50 - x = 50 - 10 = 40 years |
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| 29. |
(2) The sum of the present ages of mother and her daughter is 50 years. After 20 yearsmother's age will be twice her daughter's age at that time. Find their present age |
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Answer» Like if you find it useful |
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| 30. |
4z-3. o 0R Ll4 3i i o ŕ¤ŕ¤ |
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| 31. |
2।एक परिवार में ही 'ध हैं। यदि यह ज्ञात हो कि बच्चों में से कम से कम एकबच्चा लड़का है, तो दोनों बच्चों के लड़का होने की प्रायिकता ज्ञात कीजिए।A family has two children. What is the probability that both the children areboys given that at least one of them is a boy ?अथवा । 0R |
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Answer» 2/1 iska answer hoga |
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| 32. |
DafepogPoge |
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| 33. |
ăPoge.21 Sin |
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Answer» take the denominator of lhs to rhs, and we will get the required output |
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| 34. |
Find the square root of the following numbers by using their ones and tens digits (0r) 2304 |
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Answer» The tens digit must be 4,since 40 x 40 = 1600 (too small)and 50 x 50 = 2500 (too large) I agree that the units digit must be 2 or 8. (since 2x2 = 4, and 8x8=64)42 x 42 is obviously too small48 x 48 is correct |
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| 35. |
9)Nishant sold his scooter for24150making a profof 15%. Find the cost price of the scooter |
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Answer» 21000 will be the cost price of the scooter sp x 100―――–––(100+ 15) full salv qus plzz SP=24150profit=15%so CP=24150/1.15=21000 |
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| 36. |
A man sold a chair and a table together for 760, thereby m aking a profit of 25% on chairand 10% on table. By selling them together for 767.50, he would have made a profit of10% on the chair and 25% on the table. Find the cost price of eachチ0950 But ifhe |
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| 37. |
615.) Jamila sold a table and a chair for 1050,thereby making a profit of 10% on the tableand 25% on the chair. If she had taken aprofit of 25 % on the table and 10% on thechair, she would have got 1065. Find thecost price of each. |
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Answer» let cost of table=100x cost of chair=100y110x+125y=105022x+25y=210---(1)125x+110y=106525x+22y=213---(2)22x+25y=210---(2)by adding 47x+47y=42347(x+y)=423x+y=9---(3)25x+22y=21322x+25y=210by substrating3x-3y=3x-y=1---(4)x+y=9--+(3)by adding 2x=10x=5putting the value of x in eq 3x+y=9y=9-5=4cost of table= 500cost of chair=400 Let the cost price of the table be Rs x and the cost price of the chair be Rs y.The selling price of the table, when it is sold at a profit of 10% = Rs x + 10x/100 = 110x / 100 The selling price of the chair when it is sold at a profit of 25% = Rs y + 25y/100 = 125y / 100 So, 110x / 100 + 125y / 100 = 1050 ... (1) When the table is sold at a profit of 25%, its selling price = Rs (x + 25x/100) = Rs 125x / 100 When the chair is sold at a profit of 10%, its selling price = Rs (y + 10y/100) = Rs 110y / 100 So, 125x / 100 + 110y / 100 = 1065 ... (2) Solve (1) and (2), to get x = 500 and y = 400 Hence. the cost price of the table is Rs 500 and the cost price of the chair is Rs 400. cost of table is 500 ; cost of the chair is 400 |
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| 38. |
Aman sold a chair and a table together forand 1 0% on table. By selling them together for 767.50, he would have made a profit of10% on the chair and 25% on the table. Find the cost price of each.34.760, thereby making a profit of 25% on chair |
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| 39. |
A shopkeeper sells a saree at 8% profit and a sweater at 10% discount, thereby, getting asum Rs.1008. If she had sold the saree at 10% profit and the sweater at 8% discount, shewould have got Rs1028. Find the cost price of the saree and the list price (price beforediscount) of the sweater.12, |
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Answer» Let the CP of saree and that of sweater be x and y respectively. Case 1. Given that saree is sold at 8% profit => SP of saree = x + 8x/100 = 108x/100 Also, sweater is sold at 10% discount => SP of sweater = y - 10y/100 = 9y/10 Given that saree and sweater fetch Rs 1008, 108x/100 + 9y/10 = 1008 => 108x+90y/100 = 1008 => 108x + 90y = 100800 => 6x + 5y = 5600 => x = 5600-5y/6 (i) Case 2. Given that saree is sold at 10% profit SP of saree = x + 10x/00 = 11x/10 Also, sweater is sold at 8% discount => SP of sweater = y - 8y/100 = 92y/100 = Given that saree and sweater fetch Rs 1028, 11x/10 + 92y/100 = 1028 => 110x+92y/100 = 1028 => 110x+92y = 102800 Putting value of (i) 110 (5600-5y/6) + 92y = 102800 => 616000-550y/6 + 92y = 102800 => 616000-550y-552y/6 = 102800 => 616000+2y/6 = 102800 => 616000+2y = 616800 => 2y = 800 =>y = Rs400 From (i), x = 5600 - 5*400/6 x = 5600-1200/6 x = 4200/6 => x = Rs700 Therefore, SP of saree = Rs700 List price of sweater = Rs 400 |
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| 40. |
6. The ages of Aatif and Asif are in the ratio of 5: 7. Four years from now the ratio of their ageswill be 3: 4. Find their present age. |
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| 41. |
2. Show that any positive odd integer is of the form 69 + 1, or 69 +3, or 69 +5, where q issome integer. |
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Answer» Let a be the positive odd integer which when divided by 6 gives q as quotient and r as remainder. according to Euclid's division lemmaa=bq+r a=6q+r where , a=0,1,2,3,4,5then,a=6qora=6q+1ora=6q+2ora=6q+3ora=6q+4ora=6q+5 but here,a=6q+1 & a=6q+3 & a=6q+5 are odd. |
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| 42. |
Sonia can copy 50 pages in 10 hours. PriyaSonia can copy 300 pages in 40 hours. In hmuch time can Priya copy 30 pages? |
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Answer» Sonia can copy one page in 10/50 = 1/5 hr Priya and Sonia together can copy one page in 40/300 = 2/15 hr Then, Priya can copy one page in = 1/5 - 2/15= (3 - 2)/15 = 1/15 Therefore, Priya can copy 30 pages in= 30/15 = 2 hours |
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| 43. |
LINES AND ANGUSIn Fig. 6.14, lines XY and MN intersect at O. IfPOY = 90° and a :b 2:3, find c.Fig. 6.14 |
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Answer» answer is 126 degree 2x + 3x= 90x = 182x = 36°, 3x = 54°C = 180°- 54°126° |
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| 44. |
The age of Priya and Rati is ratio 5:7. After 4 years from the present time, the ratio of their age will be 3:4. Whattthe present age of Priya and Rati? |
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Answer» Priya's age is 20Rati's age is 29 |
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| 45. |
In Fig. 6.14, lines XY and MN intersect at O. If<POY=90° and a : b = 2: 3, find c.2. |
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Answer» thanks |
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| 46. |
In Fig. 6.14, lines XY and MN intersect at O. If<POY=90° and a : b = 2 : 3, find c.2.Fig, 6.14 |
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| 47. |
The number of lines of symmetry of an isosceles triangle a) 0b) 1c) 2 |
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Answer» Anisosceles trianglehas oneline of symmetry. |
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| 48. |
The number of lines of symmetry of an isosceles triangle isa) Ob) 1c) 2d) 3 |
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Answer» Anisosceles trianglehas oneline of symmetry |
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| 49. |
1515. In a parallelogram ABCD, E and F are themid-points of sides AB and CD respectively(see Fig. 8.31). Show that the line segments AFand EC trisect the diagonal BD. |
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| 50. |
In a chemical compound, 34% of thecompound is chemical A, 26% ofcompound is chemical B, 17% of tompound is chemical C and the remainingpercentage is of chemical D. If the totalompound is 15 L, what is the quantity ofchemicals A, B, C and D?4.the |
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Answer» 34+26+17=77100-77=23%-percent of Dnow quantity of A B C DA-34/100*15=5.1litreB-26/100*15=3.9litreC-17/100*15=2.55litreD-23/100*15=3.45litre |
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