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oi= 2/5 + 5/2 - 1/10

= 4+25-1/10

= 28/10 = 2.8

1/10!+1/11×10!+1/12×11×10!=1/10!(1+1/11+1/132)=(132+11+1)/132×12!=145/12×11×10!=145/12!

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let number =xAccording to Question17×x+4=22517x+4=22517x=225-417x=221x=221÷17x=13So number is 13

Let x be the unknown number.

So the equation is :- 17x + 4 =225 Transpose 4 to RHS.17x = 225-417x= 221x= 221 ÷ 17x = 13

let the number be x,According to question17x + 4 = 22517x = 221x = 221/17x = 13

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(Sin75+Sin15).

We will expand it by using the Identity:

Sina+Sinb=2 sin(a+b)/2•cos(a-b)/2.

Hence, we get

Sin75+Sin15

= 2•sin(75+15)/2•cos(75–15)/2

= 2•sin45•cos30

= 2×1/√2×√3/2

=√3/√2*√2/√2=√6/2

identity - the fact of being who or what a person or thing is, a close similarity or affinity, a transformation that leaves an object unchange

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sin(75°)=sin(45+30)=sin45cos30+cos45sin30=(1/√2)(√3/2)+(1/√2)(1/2)=(√3+1)/2√2=0.9659

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maximum outcomes:36

possible outcomes as product of prime

numbers: (1,2), (2,1), (1,3), (3,1), (1,5), (5,1).

therefore P(getting product a prime number)

=>6/36

=>1/6

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GIven that two dice are rolled.

Then the probability of outcomes n(S) = 6 * 6

= 36.

Let E be the event of getting a product less than 9.

The number whose product is less than 9

= ,{1,2},{1,3},{1,5},{2,1},}{3,1},,{5,1},

= 6

Therefore the required probability

P(E) = n(E)/n(S)

= 6/36

= 1/6

maximum outcomes:36

possible outcomes as product of prime

numbers: (1,2), (2,1), (1,3), (3,1), (1,5), (5,1).

therefore P(getting product a prime number)

=>6/36

=>1/6

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The brain is protected by the skull (cranium), cerebrospinal fluid and 3 protective membranes (Meninges).

The spinal cord is protected similarly but with vertebrae instead of the cranium.

Selling price = 510Discount % = 15

Marked price = (100/100 - discount%) × Selling price= (100/100-15) × 510= (100/85 ) × 510= 51000/85= Rs 600

Dicount = Discount%/100 × Marked price= 15/100 × 600= 9000/100= Rs 90

Therefore discount = 90 & Marked price = 600

Given that A^2+A - I = 0

If we multiply both sides by A^-1we have,

A^-1(A^2+ A - I) = A^-1 .0 = 0

Hence, A +I - A^-1= 0

This gives A-1= (A + I)

by BODMAS rule(350+15)/(14+15)=365/29=12.5862

Multiply N and D by 1/√2

1/√2 cos15 + 1/√2 sin 15)/ ( 1/√2 cos 15 - 1/√2 sin 15)

sin 45 cos 15 + cos45 sin 15)/( sin 45 cos 15 - cod 45 sin 15)

sin ( 45 +15)/ sin( 45-15)

sin ( 60)/ sin 30

√3

1/ under root 3 is the right answer of this problem

In second quadrant X is negative and y is positive.

Angle BPC = 180 - 50 - 55 = 75.So angle DPA = 180 - 75 = 105.Angle ADC = 105 + 30 =135 external angle property

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angle adc નો સમજાયુ

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i) 32% of 42532/100 × 425 = 136

In ∆ABD and ∆ BDCAD = DC (given)AD = BC ( given)BD = BD (common)by SSS rule ∆ABD is congurent ∆DCBso angle ABD = angle CDBso alternative angle are equal so AB||DC

Major problems faced by the Indian cotton weavers:1.Their export market collapsed.2.The local market shrunk.3.Increase in price of raw cotton.

The third term of a GP = square of its firsttermar^2 = (a)^2r^2 = a^2÷ar^2 = a .......(1)now it is given that 5th term is 64 so ar^4 = 64a(r^2)^2 = 64from eq (1)a(a)^2 = 64a^3 = 64a = 4now from eq (1) r^2 = a r = a^(1/2)r. = 4^(1/2)r. = 2now we have a and r so we can calculate the first six terms of the GP.The first six terms if the GP are

a, ar, ar^2, ar^3, ar^4, ar^5now putting the value if a and r we have first six terms of the GPSo the terms are

4, 8, 16, 32, 64, 128