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§in 75°+sin15°= 3 . |
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Answer» (Sin75+Sin15). We will expand it by using the Identity: Sina+Sinb=2 sin(a+b)/2•cos(a-b)/2. Hence, we get Sin75+Sin15 = 2•sin(75+15)/2•cos(75–15)/2 = 2•sin45•cos30 = 2×1/√2×√3/2 =√3/√2*√2/√2=√6/2 |
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