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Let us have a parallelogram ABCD , and E and F are mid points of AB and CD respectively .

Here Diagonals AC and BD and EF intersect at " O " .

We know diagonals of parallelogram bisect each other , So

AO = CO

In∆ABC , we have

AE = BE , as we assumed E is mid point of ABAndAO = CO , from property of parallelogram .SO,From conserve of mid point theorem , we get

EO | | BC , SO

EF | | BC ( As EO is part of line EF )

AndWe know BC | | DA , from property of parallelogram , So

We can say

BC | | DA | | EFSo,Joining the mid points of the opposite sides of a parallelogram are parallel to the other pairs of parallel sides. ( Hence proved )

Area which is enclosed in between these three circles

=required area = (area of an equilateral triangle of side 7 cm)- (3 * area of sector with à = 60 degrees and r = 3.5cm)

(√3/4*7*7)-(3*22/7*3.5*3.5*60/360)(√3/4*79)-(11*0.5*3.5)cm^21.967cm^2

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In ||gm ABCD, E is the mid-point of AB and F is the mid-point of DC. Also AB|| DC.

AB = DC and AB || DC

∴ (1/2)AB = (1/2)DC and AE || DF (Since E and F mid point of AB and DC)

∴ AE = (1/2)AB and DF = (1/2)DC

∴ AE = DF and AE || DF

∴Quadrilateral AEFD is a parallelogram Similarly, Quadrilateral EBCF is a parallelogram.

Now parallelogram AEFD and EBCF are on equal bases DF = FC and between two parallels AB and DC

∴ ar(||gm AEFD) = ar(||gm EBCF)

At x = 0, the value of the given function takes the form. 0/0

Now,

[(9/8) / (6/7) ] / (7/8)= (9/8) * (7/6) * (8/7)= 9/6= 3/2

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15.43 or 463(numerator) 30 (denominator)

n=2 yearsA=P(1+R/100)(1+R/100)4177.2=P(1+18/100)(1+18/100) =P(1.18)(1.18)So P=4177.2/1.3924=3000

1% = 1/100 = 0.01 16% of Rs 750 = 750×16/100 = 30×16/4 = 30×4 = 120 Rs.

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2+5= 71+5= 6thanks

(1) 6/5(2) 5/6(3) 25/6(3) 31/27.please like my answer

(1) 6/5 (2) 5/6. (3) 25/6 (4) 31/27

1.6/52.5/63.25/64.62/54

36 is the perfect square number between 30 and 40

5/4=20/16=25/20= -15/ -12-3/7= -6/14=9/ -21= -6/14

(x-5)/2 -1/2 = 5/3 - x/2 => x/2 -5/2 -1/2 = 5/3 -x/2=> x -3 = 5/3 => x = 5/3+3 => x = 14/3

6x will be length off it

time = (90*100)/(750*4) = 3yearsSum = (100*amount)/(100+rt) = (100*575)/(100 + 3*5) = ₹ 500

*There is a direct relationship between the principal and the amount and is given by SUM = (100*Amount)/(100+rt)*

We know,AM* GM = HM^212*3 = HM^2HM^2 = 36HM = 6

Therefore,HM is 6

The control offirebyearly humanswas a turning point in the cultural aspect ofhumanevolution.Fireprovided a source of warmth, protection, improvement on hunting and a method for cooking food.

The control offirebyearly humanswas a turning point in the cultural aspect ofhuman evolution.Fireprovided a source of warmth, protection, improvement on hunting and a method for cooking food.

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Volume of cube = (side)³ = 216m³

=> side = ³√216 = 6m

as left hand limit is not equal to right hand limit so this function is not differentiable at 3

<d=1/2 {<aoc}.. <d=70+40\2 =110/2<d=55....

LET THE BLUE BALL BE=X

TOTAL NO. OF BALLS = NO. OF BLUE BALLS + NO. OF RED BALLS

= X + 5

PROBABILITY OF GETTING BLUE BALL = X / X + 5

PROBABILITY OF GETTING RED BALL = 5/ X +5

ACCORDING TO THE QUESTION,

X / X + 5 = 2 * 5 / X + 5

CANCELLING X+5 FROM BOTH TERMS AS THEY ARE COMMON

X = 10

SO, THERE ARE 10 BLUE BALLS IN THE BAG

Solution :-

Let the cost price of saree be Rs. 'x' and the list price of sweater be Rs. y.

Therefore,

Situation 1 -

By selling a saree at 8 % profit and a sweater at 10 % discount, the shopkeeper gets Rs. 1008

⇒ 108x/100 + 90y/100 = 1008

⇒ 27x/25 + 9y/10 = 1008/1

Taking L.C.M. of the denominators and then solving it, we get.

54x + 45y = 50400 ............(1)

Situation 2 -

by selling a saree at 10 % profit and a sweater at 8 % discount, the shopkeeper gets Rs. 1028.

⇒ 110x/100 + 92y/100 = 1028

⇒ 11x/10 + 23y/25 = 1028/1

Taking L.C.M. of the denominators and then solving it, we get.

⇒ 55x + 46y = 51400 ...........(2)

Now, multiplying the equation (1) by 55 and (2) by 54, we get.

(54x + 45y = 50400)*55

= 2970x + 2475y = 2772000 ............(3)

(55x + 46y = 51400)*54

= 2970x + 2484y = 2775600 .............(4)

Now, subtracting (3) from (4), we get.

2970x + 2484y = 2775600 2970x + 2475y = 2772000 - - - ___________________________

9y = 3600___________________________

⇒ 9y = 3600

y = 3600/9

y = 400

Putting the value of y = 400 in (1), we get.

54x + 45y = 50400

54x + (45*400) = 50400

54x + 18000 = 50400

54x = 50400 - 18000

54x = 32400

x = 32400/54

x = 600

So, the cost price of a saree is Rs. 600 and the list price of a sweater is Rs. 400

11÷1008=0.0109126984

0.0109 is the correct answer of the given question

show that the equation to the pair of bisectors of angles between the pair of line ax+2hxy+by=0

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