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Prove that in a paralleogram, the lines joining a pairof opposite vertices to the mid-points of a pair ofopposite sides trisect a diagonal. |
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Answer» hey mate! In ||gm ABCD, E is the mid-point of AB and F is the mid-point of DC. Also AB|| DC. AB = DC and AB || DC ∴ (1/2)AB = (1/2)DC and AE || DF (Since E and F mid point of AB and DC) ∴ AE = (1/2)AB and DF = (1/2)DC ∴ AE = DF and AE || DF ∴Quadrilateral AEFD is a parallelogram Similarly, Quadrilateral EBCF is a parallelogram. Now parallelogram AEFD and EBCF are on equal bases DF = FC and between two parallels AB and DC ∴ ar(||gm AEFD) = ar(||gm EBCF) |
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