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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
\frac { \sqrt [ 3 ] { 490 } \times \sqrt [ 3 ] { 700 } } { \sqrt [ 3 ] { 343 } } |
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Answer» ye thousand kaise aaya upar se 7³/7³ will cancel off thnq |
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| 2. |
It is 260 km from Patna to Ranchi by air and 320 kmby road. An aeroplane takes 30 minutes to go from Patnato Ranchi whereas a delux bus tokes 8 hours. (a) Findthe average speed of the plane h) Find the averagespeed of the bus. ic) Find the wvernge velocity of theplane. (d) Find the avernge selecity of the bus |
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| 3. |
1.Find each of the following products:(a)3 x (-1)(b |
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Answer» a) 3×(-1) = -3 as value is 3 but sign will be - |
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| 4. |
LITO - DO7. 2225+ [ 721 — {922 + 152 - (81 of 17 - 21 x 17 + 1)}] |
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Answer» 2225 + [721-[922+152-(81×17-21×17++1)]]= 2225 +[721-[922+152-(1377-357+1)]]= 2225 +[721-[922+152-1019]] = 2225 +[721-25]= 2225+696= 2921 2921 is the correct answer of the given question 2921 is the right answer of the given question. plz like my answer the correct answer is 1523 |
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| 5. |
Our plane was scheduled toleave at 8:50 a.m., but it wasdelayed for 25 minutes due tobad weather.What time did it leave? |
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Answer» actual time : 8 hours 50 minutesdelayed by : 25 mintutes delayed delarture time : 9 hours 15 mini.e, 9:15 a.m |
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| 6. |
15cn ice-cream vendor buys 250 ice-cream cups at the rate of 7 per cup. Due to bad weather, 1api get spoiled. At what price per cup should he sell the remainder so as to sain 2090gain 20%? |
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| 7. |
22. In a fight o 00kom,.an a reref was slowed down due to bad weather Theaverage speed for the trip was reduced by 400 kmph and the time of flightincreased by 30 minutes. Find the Original duration of the flight. (Ans:2.5hr) |
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| 8. |
2545 +2614 506 + 4812 |
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Answer» 2545+2614-506+48125159-506+48125159+4812-5069971-5069465 |
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| 9. |
(-18)*(-8) %2B (-18)*(-28) |
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Answer» slaps small TV wall Pacem tea else lakdikapul 648 is the answer of the question |
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| 10. |
\left(\frac{-6}{7} \times \frac{-28}{18}\right)+\left(\frac{-11}{13} \times \frac{65}{22}\right) |
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| 11. |
7.P and Q are two railway stations, 300 km apart. Usually the train starts from Pat 5 am and reaches Q at 10 am. One day, due to bad weather the train had toreduce its speed by 10kmph. When will the train reach Q? |
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Answer» Let actual speed is vv=300/5v=60 Now speed is 60-10=50km/hr Speed=Distance/time50=300/timetime=300/50=6 hours It will reach Q at 11am |
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| 12. |
Find the H.C.F. of: (i) 108, 288 and 420 |
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Answer» please answer my other question |
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| 13. |
t answer from the alternatives given against each of the following 1-61. 0.4% of 100 is(A) 0.42. What percent of 1 day (24 hours) is 72 mirnutes?(B) 4IC) 40D) 400 |
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Answer» 0.4% of 1000.4/100× 1000.4 |
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| 14. |
\frac { 5 - 3 \sqrt { 14 } } { 7 + 2 \sqrt { 14 } } |
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| 15. |
455. 3 1434393 |
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| 16. |
1) x+y=4;2x-5y=1. 2) 2x+y=5;3x-y=5 |
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Answer» 1) x+y=42x-5y=1Multiply equation 1 with 22x+2y=82x-5y=1Subtract both equations7y=7; y=1x=4-yx=32)2x+y=53x-y=5Add both equations5x=10x=2y=3x-5=3(2)-5=6-5=1 |
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| 17. |
5y = -1 |
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Answer» ' 5y=-1y=-1/5 |
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| 18. |
Find each of the following products1. (5x + 7)(3x + 4)4. (5y-1)(3y - 8) |
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| 19. |
x+y=4;2x-5y=1 |
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Answer» x+y=42x-5y=1Multiply equation 1 with 22x+2y=82x-5y=1Subtract equations7y=7y=1x=4-y=4-1=3 |
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| 20. |
1. If the lines given by 3x +2ky 2 and 2x+5y 1 are parallel, then find the value of k. |
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| 21. |
-5x + 3 = 28 |
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Answer» 5x + 3 = 285x = 28 - 3 = 25x = 25/5x = 5 ans 5x + 3 = 28subtract 3 on both sides5x = 28 - 3 = 255x = 25divide 5 on both sides5x/5 = 25/5x = 5 |
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| 22. |
28. 0.18(5x-4)= 0.5x + 0.8 |
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Answer» 0.18(5x-4) = 0.5x+0.8 0.9x-0.72=0.5x+0.80.4x= 1.52 x=0.38 But answer is x=3.8 Yes, it is correct. x=15.2/4 =3.8 |
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| 23. |
3x^ 2-5x-28=0 |
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| 24. |
1. Solve each of the following.a. 5x + 28 18 |
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Answer» Ans :- 5x + 28 =18 5x = 18 - 28 x = - 10/5 x = -2 |
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| 25. |
(i) Find the number which when increased by 30% becomes 39.(ii) Find the number which when decreased by 8% becomes 506 |
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| 26. |
The side of a right angle triangle is 17 cm less than the other side. If length of hypotenuse is25 cm, find the length of sides |
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| 27. |
A spherical ball can hold 288T cm of air. Find the radius of ball. |
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Answer» 4/3πr^3= volume of balloon= 288πnow4/3r^3= 288r^3= 288*3/4r^3= 216r= 6 cm |
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| 28. |
A hall measures 16 m by 12 m. How many square tiles ofside 25 cm will be required to pave its floor? |
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| 29. |
The diameter of spherical ball is 4.2 cm. What is the mass of the ball if the density is 8.9gm/cm3 |
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| 30. |
40. A cylindrical tub of radius 12 cm contains water to a depth of 20 cm. A spherical ballis dropped into the tub and the level of the water is raised by 6.75 cm. Find the raditsof the ball. |
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| 31. |
is nerfor7. ABC is a right angled triangle in which ZA-90°and AB = AC. FindB andC. |
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| 32. |
4 Suppose m and n are any two numbers. If m2 n,2mn and m2 + n are the three sides of a triangle,then show that it is a right angled triangle andhence write any two pairs of Pythagorean triplet. |
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| 33. |
nuelght.14 The area of a right angled triangle is 480 cm². If thebase of the triangle is 8 cm more than twice theheight (altitude) of the triangle, then find the sidesof the triangleCBSE 2013 |
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Answer» 1/2× base x height=area; 480=1/2×8×height=height=480=x^2+4x-480=x^2+24x-20 x-480= x( x+24)-20(x+24)=(x+24)(x-20); x=-24 & 20 |
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| 34. |
Do HISSolve each pair of equatio3x-5y =-11) |
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Answer» 3x - 5y = -1 ....................... (eq. 1) x - y = -1 ⇒ y = x + 1 ........................(eq 2) Substituting the value of y in eq. 1 ⇒ 3x - 5(x + 1) = -1 ⇒ 3x - 5x - 5 = -1 ⇒ -2x = 4 ⇒ x = -2 ⇒ y = x + 1 = -2 + 1 = -1 Like my answer if you find it useful! |
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| 35. |
In the given figure, ABC is a triangle, right angled at B, If BCDE is a square on side BC anon AC, prove that AD FBd ACFG is a squaren tho same side |
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| 36. |
हक1007.10 Find Z oPR, / PQR={||| |
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| 37. |
4.The numerator of a rational number is less than its denominator by 4. If the numeratoris increased by 2 and the denominator is increased by 4, the number becomesFind15the number. |
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Answer» I can't see it fulll |
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| 38. |
thanThe denominator of a rational number is less than its numerator than 5. If 5 is added to the numereFind the original rational number.4.ew number becomes |
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Answer» thanks |
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| 39. |
The numerator of a rational number is less than its denominator by 3. If 5 isadded to both i.e., its numerator and its denominator then it becomesFind the numbers. |
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| 40. |
ajo3. in Fig. 10.37, POR=100° P, Q and R arepoints on a circle with centre O. Find OPR., Where |
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| 41. |
4) Fill in the blanks and complete it frem2y2 -5y + 10 0Comparing with ay, by + c0, Ń 102425-'. b2 -4ac.. The roots of equation are |
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| 42. |
cinle Find the angle subtended by the chord atint on the minor are and also at a point on themajor arelo fig 10.37, 4 POR 10, where P. Q and R arepants on a circle with centre O. Find 2 OPRtorFig. 10.374 In Fig 10.38, ABC 6, ACB 31", find |
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| 43. |
in Fig. 10.37, PQR = 100, where P, Q and R are points on a circle with centre O. Find angle OPR. |
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| 44. |
DIP,lace A and Bin 80kmapart frem each other on ahr a Car start from A and another farm B atths ame tine f they tmove in a same direction theg(meet in &hour and alf the move toward, each the Îłt Cans |
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Answer» Let speed of A be a km/hr and speed of B be b km/hrdistance = 80kmATQ80=(a-b)*8 and 80 =(a+b)*(4/3)a-b =10 and a+b=60a= 35 , b= 25 |
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| 45. |
i3U at a point on theIn Fig. 10.37, 4 POR 100°, where P, O and R arepoints on a circle with centre O. Find OPR. |
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| 46. |
(11) A train starting frem tationsry posities sttainsvelocityof 12 km/h is 5minste. The train perferms form accelrrated motionCaleulate (i) acceleration of trais() distance travelled by train in 5 minute |
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| 47. |
3. In Fig. 10.37, Z PQR 100, where P, Q and R arepoints on a circle with centre O. Find Z OPR |
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Answer» thank u |
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| 48. |
A godown measures 40 m x 25 m x 10 m. Find the maximum number of woodencratseach measuring 1.5 m x 1.25 m x 0.5 m that can be stored in thc godown. |
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| 49. |
1. Solve the following equation1. 5x- 2=18 |
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Answer» 5x - 2 = 18 5x = 20 x = 4 15a3;-45a2;150a |
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| 50. |
The sum of the digits of a two digit number is 12. If the new number formed by reversing thedigits is greater than the original number by 18, find the original number. Check your solu-tion. |
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