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if the following figure is rectangle then the area of the rectangle will be 2×(l+b) =2×(10+14) =2×24 =48mm

fínd thє αrєα σf f kα fígurє

thanks

From the figure (see the attached file kindly),OB/BC=tanAor, (22-1.5)/20.5=tanAor, tanA=20.5/20.5or, tanA=1or, tanA=tan45°or, A=45°∴, the angle of elevation is 45°.

As AC = CD soangle A = angle Dangle D = 25°x = angle A + angle D ( exterior angle theroem)x = 50°

greater numbers are:-a)3^4b)3^5d)2^100e)2^10

greater number; 1 ) 3^4; b)3^6; d)2^100; e)2^10

greater number;1(3^4; b)3^6 d)2^100; e)2^10

13x+30+5x+6 = 18018x+36 = 18018x = 180-36 => 144x = 144/18 = 8°

not sure answer

No. Obtuse angle is always greater than 90º. It can be observed that two angles,even of 91º, will always add up to more than 180º. Therefore, two obtuse angles cannotbe in a supplementary angle pair.

(iii) right is the correct answer

two right angles can be supplmentary. so answer is (iii)

3 right angles Is answer to your question

125%=125/100=1.2545%=45/100=0.4525%=25/100=0.251/4%=0.25%=0.25/100=0.00256 1/4%=25/4%=6.25%=6.25/100=0.0625

We apply Pythagoras theorem.ΔABC: AC² = AB² + BC² 5² = (2 BE)² + BC² 25 = 4BE² + BC² -- (1)Also, BE² + BC² = CE² ----(2)ΔABD, AD² = AB² + BD² = 4 BE² + BC²/4=> 4 (3√5/2)² = 45 =16 BE² + BC² -- (3)Solve the equations (1) and (2). 55 = 3 BC² => BC =√(55/3)=> BE² = (AC² - BC²)/4 =(5² - 55/3)/4 = 5/3

By (2), CE² = 5/3 + 55/3 = 20/3=> CE = 2√(5/3)

please post clear question.

tan30=1/√3hence2tan30/1+tan^2302*1/√3/1+1/36/√3*43/√3*2√3/2

(100*230)/480=23000/480=457/12=47.916

6.25 is the right answer.

answer this question is 47.916666667

47.91 is the correct answer

47.91 is the right answer

hello ur answer is (47.916)

45.8333333333333333333

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47.916 is the right answer

(100 × 230 )/480 = 23000/480 = 47.91

100*230/48023000/480=47.91

47.91 is the right answer

1. true all the triangle haa 3 sides and 3 angles2.False. A triangle with all three equal sides is calledequilateral3. False. Anobtuse triangleis onewithoneobtuse angle(greater than 90°) andtwoacuteangles. Sincea triangle's anglesmust sum to 180°, notriangle can havemore than oneobtuse angle4. True If two of its sides are equal, a triangle is calledisosceles.5. False In anobtuse triangle, oneangleis greater than aright angle—it is more than 90 degrees. Anobtuse trianglemay beisoscelesor scalene. In anacute triangle, allanglesare less thanright angles—each one is less than 90 degrees. Anacute trianglemay beequilateral,isosceles, or scalene

Youare right - anequilateral trianglecannothave an obtuseangle. In fact, the angles are all "fixed" - they are each 60 degrees. Try this: take three equal length pencils and form atriangle. Now take three more pencils and try to form atrianglethat has angles different from the first.

option d is the correct answer of the given question

Checking out the possibilities of the third side will give the answer.

xy = 4xy could be 2 *2 or 4 * 1221222 These are the possible triangles.223441

22x will be a triangle if x is 1, 2 or 3 (trial and error).44x is a triangle only if x is 1.1. 221 is acute. 12+ 22> 222. 222 is equilateral. So acute.3. 223 is obtuse. 22+ 22< 324. 144 is acute. 12+ 42> 42

The question is" x, y, z are integer that are side of an obtuse-angled triangle. If xy = 4, find z."And so, the third side has to be 3

Hence, the answer is 3.

Choice B is the correct answer.

B is the correct answer

b is the correct answer

Given,SP = 468, CP = 400

Profit % = [ (SP - CP) /CP] ×100 =[(468 - 400)/400]×100 = 68/4 = 17%

thanks

sin^6x+cos^6x+3sin^2xcos^2x

=sin^6x+3sin^2xcos^2x(1)+cos^6x

=sin^6x+3sin^2xcos^2x(sin^2x+cos^2x)+cos^6x

=sin^6x+3sin^4xcos^2x+3sin^2xcos^4x+cos^6x=(sin^2x+cos^2x)^3=1^3=1

24

Given,10^x = 64

Value of 10^(x/2 + 1)= 10^x/2 * 10^1= (10^x)^1/2 + 10= (64)^1/2 + 10= 8 + 10= 18

90

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