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Given, Distance between person and church = 80 mAngle of elevation = 45°Height of church H =?

We know,tan x = P/B

tan 45° = H/801 = H/80H = 80

Therefore, height of church is 80 m

8x³ + √64y³= 8x³ + 8y³= (2x)³ + (2y)³= 2³ ( x³ + y³)= 8 ( x+y)(x²+y²-xy)

x-y = -1 and 2x-y =0y = x+1 putting the value of y in 2nd equation2x - x -1 =0 , x - 1 = 0, x=1and y = 1+1 = 2

2x + z = 5and 3z + w = 13 2[1] + z =5, z = 5 -2 =3 3[3] + w =13 , w = 13 - 9 = 4

ifa + b + c = 0then

a x (a+b+c) = a x a + a x b + a x c = a x 0 = 0a x b + a x c = 0a x b - c x a = 0soa x b = c x a

b x (a+b+c) = b x a + b x b + b x c = b x 0 = 0b x c = a x b

c x (a+b+c) = c x a + c x b + c x c = c x 0 = 0c x a = b x c

putting it all together, a x b = b x c = c x a

ax(b-c)=1/2*(-3/4-(-2/3)=1/2*(-3/4+2/3)=-1/2*(1/12)=-1/24anda*b-a*c=1/2*-3/4-1/2*-2/3=-3/8+1/3=-1/24hence proved

(AI-IB=[1,2,3,4,5,6,7]; (AI-I)×c=[1,2,3,4,5,6,7]x(2)=(2,4,6,8,10,12,14); (AxB)=(2,3,4,6,8,9,10,12 ,14 16,18,20,21,24,25,26,28,30)(Axc)=(2,4,6,8,10,12,14); (AI-IB)-(BI-IC)=(3,15, 16 18,20,21 ,24,26,28,30)

2) AX(B-C)=(AxB)-(AxC); Ax(3,5,7)=(1,2,3,4,5,6,7)×(3,5,7)=(3,6,9,12,15,18,21,5,10,20,30,35,14,28,35,42,49);

Seperate2/cos^2x-3sinx/cos^2x=integral(sec^2x)-integral(3secx*tanx)dxnow1/2log(secx+tanx)-3secx+C

17x17= 17^(x/5)17^2= 17^(x/5)( आधार समान है इसलिए घाते भी समान होगी2= x/5x= 10please like the solution 👍 ✔️

and check previous Answer as well

javab

AxB =ABsin theta.So whenAxB=0 then theta is also 0° as

AxB= 0

=> ABsin theta =0

=> Sin theta = 0

=> theta = 0°now A.B = 0cos theeta = 0sin 90= 1so answer 1

second part

B is correct answer

1 is the right answer

(b) is a good answer

sum of zeroes= 5+2√3+5-2√3 = 10product of zeroes=(5+2√3)(5-2√3){since (a+b)(a-b)=a^2 - b^2) = (5)^2-(2√3)^2 = 25-4×3 = 25-12 = 13polynomial=x^2-x(sum of zeroes)+(product of zeroes)x^2-x(10)+(13)x^2-10x+13

Increasing 213 by 623 means (213+623)=836

option: C (a×b) hcf×lcf=product of the numbershcf(a, b) ×lcf(a,b) =ab

option c a×b hcf×lcf=product of the Number hcf(a,b)×lcf(a,b)=ab

2 sin^2 (x) - 3 sinx + 2.

Let y = 2 sin^2 (x) - 3 sinx + 2

For y to be minimum or maximum,dy/dx = 0

Or, 4 sinx cosx - 3 cosx = 0Or, cosx (4 sinx - 3) = 0

cosx = 0, sinx = 3/4x = 90°, 48.59°.

d^2 y / dx^2= 4 (cos^2 (x) - sin^2 (x)) + 3 sinx= 4 cos (2x) + 3 sinx

When x = 90°, d^2 y / dx^2 = -1 < 0So, y is maximum when x = 90°

When x = 48.59°, d^2 y / dx^2 = 1.75 > 0So, y is minimum when x = 48.59°

y (max) = 2 sin^2 (90°) - 3 sin (90°) + 2= 1

Using the binomial theorem,(a+b)^3=a^3+3a^2b+3ab^2+b^3

⇒a^3+b^3=(a+b)^3−3a^2b−3ab^2=(a+b)^3−3(a+b)ab

Substitutinga=sin^2(x)aandb=cos^2(x), we have:

sin^6(x)+cos^6(x)=(sin^2(x)+cos^2(x))3−3(sin^2(x)+cos^2(x))sin^2(x)cos^2(x)

Using the trigonometric identitycos^2(x)+sin^2(x)=1 our expression simplifies to:

sin^6(x)+cos^6(x) =1−3sin^2(x)cos^2(x)

(a+b)²=a²+2ab+b²

(17x+18y)²=(17x)²+2*17x*18y+(18y)²=289x²+612xy+324y²

Your correct answer is 76/5

The correct answer is 76/5

2/3, 7/19, 5,0, 1, 1/9, 7/5 is the correct answer of the given question

give me answer

x^2 + 20x + 75 = 0x^2 + 15x + 5x + 75 = 0x(x + 15) + 5(x + 15) = 0(x + 5)(x + 15) = 0x = - 5, - 15

7sin square theta +3cos square theta =4

4 sin square theta + 3sin square theta + 3cos square theta =4

4 sin square theta+3(sin square theta +cos square theta)=4

4sin squre theta=1

sin theta=1/2cos theta= √3/2

tan theta =1/√3sec theta = 2/√3

sec theta + cosec theta = 2 + 2/√3

tan75°=tan(30°+45°)

=(tan30°+tan45°)/(1-tan30°tan45°)

={(1/√3)+1}/{1-(1/√3)(1)}

=(√3+1)/(√3-1)

So,cot75°=1/tan75°

=(√3-1)/(√3+1)

Then,tan75°+cot75°={(√3+1)2+(√3-1)2}/{(√3)2-(1)2}

=(3+1+2√3+3+1-2√3)/(3-1)

=4.

Thanks

5p^2+3q^2-pq-(4pq-5q^2-3p^2)8p^2+8q^2-5pq

square root is 1/2 power(3^2)^1/2*(4^4)^1/2*(5^2)^1/2=3*4^2*5=15*16=240

Heat energyis the result of the movement of tiny particles called atoms, molecules or ions in solids, liquids and gases.Heat energycan be transferred from one object to another. Thetransferor flow due to the difference in temperature between the two objects is calledheat

40 + 4x+ 3x = 1807x + 40. = 180 7x. = 180-40 7x. = 140 x = 140/7 x = 20

40+4x+3x=1807x=180-40x=140/7x=20

7x+40°=180x=140/7x=20°

40+4x+3x=180°7x=180-407x=140X=20° answer

X=20° is the right answer

28w + 7x + 14y - 5w + 5x - 15y23w + 12x - y

So herex^2-3x-4= x^2+x-4x-4= 0x(x+1)-4(x+1)= 0(x-4)(x+1)nowit will be changed tolim x tends to 4 (1/(x+1)that will be 1/(4+1)= 1/5

4x+6>20x-511>16xso x<11/16

Give full answer

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All the world's a stage" is the phrase that begins a monologue from William Shakespeare's pastoral comedy As You Like It, spoken by the melancholy Jaques in Act II Scene VII Line 138.