g N o 'T"FQW‘W«” LD"‘WW’W‘_W“% ’—T%‘D—'WWW o WO T – InterviewSolution

1.

g N o 'T"FQW‘W«” LD"‘WW’W‘_W“% ’—T%‘D—'WWW o WO T oymvg“’frmw7 i mvzm‘;pﬁf

Answer»

Given, Distance between person and church = 80 mAngle of elevation = 45°Height of church H =?

We know,tan x = P/B

tan 45° = H/801 = H/80H = 80

Therefore, height of church is 80 m

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