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45\ sister age = 5\445*4\5= sister age36 year

let the ratio be xso, 5x=45therefore, x=9so, his sister's age is 4x= 36(answer)

Using fundamental theroem of calculus that is we get thatf'(x) = x sinx

thank you so much

1/3÷1/2=2/32)8/3÷1 1/28/3÷3/216/9

1)2/3 2)16/9 is a is the correct answer of the given question

Sum of all angles of quadrilateral=360so,let unknown no be 'a'120+80+60+a=360260+a=360a=360-260a=100

x=180-120=60

y=180-80=100

z=180-60=120

w=180-a=180-100=80

now,x + Y + Z + w = 80+120+100+60360°

thanks

400×28=9200ml1L=1000ml9200ml=9.2L15-9.2=5.8L:soup left is equal to 5.8L

correct answer is 5.8 L

the answer to how much soup is left is equal to 5.8Liters

1) 4 3/5 + 5 1/5 + 2 1/2 = 23/5 + 26/5 + 5/2 = (46 + 52 + 25)/10 = 123/10 = 12.3

2) 3/8 + 5/9 + 1/6 = (27 + 40 + 12)/72 = 79/72

what is the answer of this question

yes they are verfy your answer is LHS =RHS

-3/4=-3/4so, it is verified that LHS=RHS

thanx.

Given:

∠AOB = 60°

∠BOC= 30°

Here,∠AOC = ∠AOB + ∠BOC

∠AOC = 60°+30°

∠AOC = 90°

Since Arc ABC makes an angle of 90° at the centre of the circle.

∠ADC= 1/2∠AOC

[SINCE THE ANGLE SUBTENDED BY AN ARC AT THE CENTRE IS DOUBLE THE ANGLE SUBTENDED BY IT AT ANY POINT ON THE REMAINING PART OF THE CIRCLE]

∠ADC= 1/2(90°)

∠ADC= 45°

Hence, ∠ADC= 45°

∠AOB = 60°

∠BOC= 30°

Here,∠AOC = ∠AOB + ∠BOC

∠AOC = 60°+30°

∠AOC = 90°

Since Arc ABC makes an angle of 90° at the centre of the circle.

∠ADC= 1/2∠AOC

[SINCE THE ANGLE SUBTENDED BY AN ARC AT THE CENTRE IS DOUBLE THE ANGLE SUBTENDED BY IT AT ANY POINT ON THE REMAINING PART OF THE CIRCLE]

∠ADC= 1/2(90°)

∠ADC= 45°

Hence, ∠ADC= 45°

thank a lot

To prove:3 × 12 × 101 + 4 is a prime or composite numberSolution:3 × 12 × 101 + 4 = 3 ×( 3 × 4) × 101 + 4

= 4 [ 3 × 3 × 101 + 1 ]

= 4 × k [ where k = 3 × 3 × 101 + 1] ,

= 4 × k × 1

is a composite number as it has 3 factors

Therefore ,

3 × 12 × 101 + 4 is a composite number

Answer: 3 × 12 × 101 + 4 is a composite number

explain whether 3*12*101+4 is a prime or composite number

3×12×101+43×12×101+2×2Take 2 common2(3×6×101+2)This shows number is divisible by 2 which explains that it is a composite number

Ifthey havesamealtitude, they will liebetween the same parallels. Hence the area of thetrianglewill be equal to half that of theparallelogram

Area of traingle abc=1/2Area of parallelogramArea of parallelogram=2×Area of triangle abcHence area of parallelogram=2×10=20cm^2

​This is the solution to the given problem.

NOTE:- All those terms with S1 or P1 become zero, because the value of P1=S1=0.

This method is way easier than using traditional methods.

It will be 8Answer 8

Please let me know if you have understood this or not

(a+b+c)÷1/ab+1/bc+1ca (a+b+c)÷(a+b+c)/abc1÷1/abcabc

1/a + 1/b + 1/c = 1/a+b+c

(ab+bc+ca)/abc = 1/(a+b+c)

=>abc = a^2b+ab^2+ac^2+a^2c+b^2c+bc^2+3abc

=>a^2b+ab^2+ac^2+a^2c+b^2c+bc^2+2ab = 0

(a+b)(b+c)(c+a) = (ab+ac+b^2+bc)(c+a)

= abc+ac^2+b^2c+bc^2+a^2c+a^2b+b^2a+abc

= 0

Thanks

angle B+C = 180-A=> (B+C)/2 = 90-A/2

so, (B+C)/2 + BOC = 180=> BOC = 180-(B+C)/2 = 180-90+A/2 = 90+A/2 option A

thanks

Sample space : 1, 2, 3, 4, 5, 6

Total possibilities = 6

i) A=getting an even number={2,4,6}

P(A) = 3/6 = 1/2

ii) B = getting an odd number = {1, 3, 5}

P(B) = 3/6 = 1/2

iii) C = not an even number = { 1, 3, 5} P(C) = 3/6 = 1/2

Answer:

28

Step-by-step explanation:

Let the number be 'x'

49th even number after 1575 will be same as 49th even number after 1574

= 1574 + 2* 49 = 1574 + 98

= 1672

70 th even number before 1028 will be =

1028 - 70*2

= 1028 - 140

= 888,

Given x² = 1672 - 888

⇒ x² = 784

⇒ x = 28 .

hit like if you find it useful

yes

s={1,2,3,4,5,6} n(s)=6A={2,4,6} n(A)=3B={2,3,5} n(B)=3

The only prime number that is even is 2.

yes

aapka answer galat hai

thnx

ABC~DEFso areaABC/areaDEF=BC/EF144/areaDEF=3/4so areaDEF=(144×4)/3=48×4=192cm*cm

(a + b + c) ( a + b - c)

( a + b)² - c²

a² + b² + 2ab - c²

1

2