Explore topic-wise InterviewSolutions in Current Affairs.

Post one at a time tysm

2³ × 3⁴ × 4----------------- 3 × 32

2³ × 3⁴ × 2²------------------ 3 × 2^5

2^5 × 3⁴-------------- 3 × 2^5

3³ = 27

=2×2×2×3×3×3×3×4/3×32=8×27×4/32=27.

=2×2×2×3×3×3×3×4/3×32=8×27×4/32=27.

27 is the correct answer

8×81×43×32=1×27×4 41×27=27

nahi pata haiiiiiiiìiiiiiiiiiiiii

27 is the correct answer.

27 is a right answer

Let a be the positive odd integer which when divided by 6 gives q as quotient and r as remainder.

according to Euclid's division lemmaa=bq+r

a=6q+r

where , a=0,1,2,3,4,5then,a=6qora=6q+1ora=6q+2ora=6q+3ora=6q+4ora=6q+5

but here,a=6q+1 & a=6q+3 & a=6q+5 are odd.

Let a be an arbitrary positive integer.Then, by Euclid ’s divisions Algorithm, corresponding to the positive integers a and 5, there exist non-negative integers m and r such thata = 5m + r, where 0 ≤ r < 5⇒ a2= (5m + r2) = 25mr + r2+ 10mr [∵(a+b)2= a2+ 2ab + b2]⇒ a2= 5(5m2+ 2mr) + r2...(i)where, 0 ≤ r < 5

Case I When r = 0, then putting r = 0 in Eq.(i), we geta2= 5(5m2) = 5qwhere, q = 5m2is an integer.

Case II When r = 1, then putting r = 1 is Eq.(i), we geta2= 5(5m2+ 2m) + 1⇒ q = 5q + 1where,q = (5m2+ 2m) is an integer.

Case III When r = 2,then putting r = 2 in eq.(i),we geta2= 5(5m2+ 4m) + 4 = 5q + 4where, q = (5m2+ 4m) is an integer.

Case IV When r = 3, then putting r = 3 in Eq.(i), we geta2= 5(5m2+ 6m) + 9 = 5 (5m2+ 6m) + 5 + 4= 5(5m2+ 6m + 1) + 4 = 5q + 4where, q = (5m2+ 8m + 3) is an integer.

Case V When r = 4, then putting r = 4 in Eq.(i), we geta2= 5(5m2+ 8m) + 16 = 5 (5m2+ 8m) + 15 + 1⇒ a2= 5(5m2+ 8m + 3) + 1 = 5q + 1where, q = (5m2+ 8m + 3) is an integer.

Hence, the square of any positive integer cannot be of the form 5q + 2 or 5q + 3 for any integer q.

Like my answer if you find it useful!

4003×77 = 308231 308231 - 21015 = 287216 ? = 287216/116 = 2476

3x + 2y = 20

Xy = 14/9

27x^3 + 8y^3 =?

Let us cube the first equation on both sides!.

(3x + 2y)^3 = (20)^3

27x^3 + 8y^3 +{ 3(3x)(2y)}(3x + 2y)!.

Formula =

(a + b) ^3 = a^3 + b^3 + 3ab(a + b)

27x^3 + 8y^3 + 18xy(3x + 2y)

27x^3 + 8y^3 + 18(14/9)(20)

27x^3 + 8y^3 + 28(20)

27x^3 + 8y^3 + 560 = 800

27x^3 + 8y^3 = 800 - 560

27x^3 + 8y^3 = 240!.

a(n) = 2n + 1

a(1) = 2×1 + 1 = 3

a(2) = 2×2 + 1 = 5

a(3) = 2×3 + 1 = 7

so sum of first three terms is

3+5+7 = 15

thankyou soo much

your question is incomplete

Sum of angles of quadrilateral is 360.Let fourth angle be n

Then, 45 + 75 + 140 + n = 360n = 360 - 260 = 100

Fourth angle of quadrilateral = 100 degree

The following steps are carried out to construct 75 degree-angle.Step 1: Draw a ray with end point A and BStep 2: With A as center and any radius, draw an arc cutting the ray at point C using a compassStep 3: With C as center and the same radius, draw an arc cutting the arc drawn at D.Step 4: With D as center and the same radius, draw an arc again intersecting the previously drawn arc at E.Step 5: Now, take any radius and draw two arcs with D and E as centers. Let these two arcs intersect at a point F.Step 6: Join AF ∠FAB obtained is the angle of measure of 90 degree.Step 7:The line AF intersect the arc at the point named as GStep 8: With G and D as center draw an arc with radius more than half of the measurement (GD).The arc intersect at the point P.Step 9: Join the point P and A.∠PAB obtained is the angle of measurement 75 degree.

Since a=90Thus ab=ac givenCancelling a we get b=cThus b+b=90 Thus b and c both are same The solving above equation we get b and c =45°

75 degrees=

1.309 radians

75Deg× π/180 = 1.309Rad

Please hit like if you find my solution useful

wrong answer

30 is the correct answer

30 is the answer of the following

30 is the right answer.

30 is the correct answer of the given question

30 is the right answer

LSA = 4 × side² = 4 × 10² = 400 cm²

TSA = 6 × side² = 6 × 10² cm² = 600 cm²

The given equation is 2x⁴ -5x²+3 =0 let x² = t

so the equation becomes 2t²-5t+3 = 0=> 2t²-3t-2t+3 =0 => t(2t-3) -1(2t-3) = 0=> (t-1)(2t-3) = 0

so the value of t = 1, or t = 3/2but t = x² = 1, 3/2 so x can be = ±1 , ±√3/√2

2) 2x-3/x = 1 => 2x²-x-3 = 0 => 2x²-3x+2x-3 = 0 => x(2x-3)+1(2x-3) = 0 => (2x-3)(x+1) = 0 so ,x = 3/2, -1.

It is a GP with common ratio, r= -1/3a=3

Sum upto infinity of a GP= a/(1-r)= 3/(-(-1/3))=3/(1/3)=9

234 is your right answer

234 is the right answer

234is your answer of questions

(-2,4) lies in 2 quadrant (1,2) lies in 1 quadrant

2x - 3/4------------- = 1/49x + 4/7

8x - 3 = 9x + 4/7

-3 - 4/7 = x

x = (-21 - 4)/7

x = -25/7

90/120×1003/4×1003×2575℅ answer

Total voters = 120Yes voters = 90% of yes votes = (90/120) × 100(3/4)×1003×2575℅ voters voted yes

distance = speed×time 54 is given km and time is given in second then convert to hour 54× 30 ×5/18= 450 is correct ans hope you like this

distance= speedx time,84×30×5/18=2520×5/18=700

90/120*10075 Percentage voted yes

If you find this solution helpful, Please give it a 👍

1 afjbvvcfyjjbvgkmetujnbvfgh

Total surface area of cube=6a^21350=6a^2a^2=225a=15m

Volume of cube=a^3=15^3=3375m^3

dx/dtheta=1-costhetaand dy/dtheta=sintheta(differentiating the expression with respect to theta)hence dy/dx=sintheta/1-costhetady/dx at π/2put theta=π/2hence dy/dx=sinπ/2/1-cosπ/2dy/dx=1/1-0=1

196 = 2 x 2 x 7 x 738220 = 2 x 2 x 3 x 5 x 7 x 7 x 13.So HCF = 2 x 2 x 7 x7 = 196.

First 10 natural numbers are 1, 2, 3, 4, 5, 6, 7, 8, 9, 10

Mean of first 10 natural numbers= (1+2+3+4+5+6+7+8+9+10)/ 10= 55/10= 5.5

the answer of the question is answer 5.5