(Short and Long Answer Type Quei) 2

1.	(Short and Long Answer Type Quei) 2
Answer» The given equation is 2x⁴ -5x²+3 =0 let x² = t so the equation becomes 2t²-5t+3 = 0=> 2t²-3t-2t+3 =0 => t(2t-3) -1(2t-3) = 0=> (t-1)(2t-3) = 0 so the value of t = 1, or t = 3/2but t = x² = 1, 3/2 so x can be = ±1 , ±√3/√2 2) 2x-3/x = 1 => 2x²-x-3 = 0 => 2x²-3x+2x-3 = 0 => x(2x-3)+1(2x-3) = 0 => (2x-3)(x+1) = 0 so ,x = 3/2, -1.

Answer»

The given equation is 2x⁴ -5x²+3 =0 let x² = t

so the equation becomes 2t²-5t+3 = 0=> 2t²-3t-2t+3 =0 => t(2t-3) -1(2t-3) = 0=> (t-1)(2t-3) = 0

so the value of t = 1, or t = 3/2but t = x² = 1, 3/2 so x can be = ±1 , ±√3/√2

2) 2x-3/x = 1 => 2x²-x-3 = 0 => 2x²-3x+2x-3 = 0 => x(2x-3)+1(2x-3) = 0 => (2x-3)(x+1) = 0 so ,x = 3/2, -1.

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