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II IIIa b catbtcthenP.T. (a+b)(b + c) (+a)=0. |
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Answer» 1/a + 1/b + 1/c = 1/a+b+c (ab+bc+ca)/abc = 1/(a+b+c) =>abc = a^2b+ab^2+ac^2+a^2c+b^2c+bc^2+3abc =>a^2b+ab^2+ac^2+a^2c+b^2c+bc^2+2ab = 0 (a+b)(b+c)(c+a) = (ab+ac+b^2+bc)(c+a) = abc+ac^2+b^2c+bc^2+a^2c+a^2b+b^2a+abc = 0 |
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