Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Find the value of x.irFind the value of x. if2*Find the value of xt (2x+7)

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2.

umbers bertween 20 and 302What are a

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23 and 29

hit like if you find it useful

3.

Espress 121 as the sof 11 odd umbers

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Therefore, 121 is the sum of first 11 odd natural numbers.

121 = 1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19 + 21

4.

umbers are there in all in the number system?bal

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Last four digit number is 9999

So there are 9999 numbers till last 4 digit number.

Now we want just four digit numbers so we can get them by subtracting numbers other than 4 digit number from 9999

i.e. from 1 to 999

So, 9999–999= 9000 numbers

5.

Sum of tuwo umbers 72 TheisLeM lo. Find the two numbers

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sorry it's wrong 4+5 is not 72

Sorry, it was calculation error.

Apologising for the error in the solution. This is the correct solution.

6.

ths of the parallel sides of a trapezium are in the ratio 3:5 and the distancIf the area of trapezium is 120 cm2, find the lengths of its parallel sidese between them ishe leng0 cm.

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7.

Ed, the dle team of thsthe middlleo bart The suunSung8

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can u solve my another sum of trigonomerty

8.

ing., PQ | | RS, LQPR = 70°, LROT = 20°, find the value of x.70°20

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9.

In the given figure, if ZAOC- (2x-10)° and<BOC = (3x + 20)" ,find ZAOC and ZBOC.. Find the value of x. AlsoCr(3r+ 20)

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10.

In the given figure, if LAOC (2x-10)° andBOC = (3x + 20 )。. Find the value ofx. Also,find ZAOC and ZBOC.(2-10 (3+20)ngles. the

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2x-10+3x+20=1805x+10=1805x=170x=34°AOC=2×34-10=58°BOC=3×34+20=122°

11.

Yuvraj hitted 3 times centuries in 10 innings. Find the probability that didnot hit centuries ?

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3 times hitting centuries so 7 times not hittingso probability=7/10=0.7

12.

What percent is 16 hours of 2days

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1 days = 24hours2 days = 2 * 24 = 48 hourspercentage = (16/48)*100 = 33.3%

13.

what fractions of a day is 16 hours

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fraction =16/24please like my answer

fraction =16/25please like my answer

16/24please like my answer

16 hours is 16/24= 2/3 fraction of a day

16/24=2/3 fraction of a day

fraction= 16/24 = 2/3

14.

12) Sachin Ramesh Tendulkar scored 51 centuries and 68 half- centuries in his Test career of 329innings. In what per cent of innings did he score more than 50 runs?

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Half centuries means >= 50 runs Centuries means >= 100 runs

total 329 innings 51 centuries and 68 half centuries total 119 innings of more than 50 runs per cent = 119*100/329 = 36.17%

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thanks

15.

Divya waited for a bus from quarter to five until ten past five. How long did she wait for the bus?

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4:45 to 5;10( she waited for )25 minutes

16.

Insert x arithmetic means between x^2 and 1

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thankuu

17.

ं) ॥त the quadratic polynomial whose zeroes are 2 and -4.Find ration between the coefficients and zeroes of polynomial

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18.

If α and β are zeroes of the polynomial t-1-4, form a quadratic polynomialwhose zeroes areand0t

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Here

19.

67Between 1 and 31, m arithmetic means have been insertel in sach wat the ratio of the 7th and (m-Dh means is 5:9. Find the value of mia

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20.

5. Find the quadratic polynomial whose zeroes are square of the zeroes of the polynomialx2-x-1

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First find roots of x^2-x-1hencex=-b+-√b^2-4ac/2ax=1+-√1+4/2x=1+√5/2 ,1-√5/2hence square will be y=(1+√5/2)^2,y=(1-√5/2)^2y=1+5+2√5/4,y=1+5-2√5/4y=6+2√5/4,y=6-2√5/4hencethe quadratic equation y^2-(sum of roots)y+(product of roots)hencey^2-(12/4)y+(36-10/16)y^2-3y+13/8

21.

21. Ifya_ ax + by? + cd, then find lim x→ 0

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22.

find the range of the function y=x²-1/x-1

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as at x= 1 system will become undefinedso range is R-{1}

23.

14. Quadratic polynomial 2x 31 has zeroes as a and B.Now form a quadratic polynomial whose zeroes are 3o and38.

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24.

30.tif cosec θ + cot θp, then prove that cos θP2-1

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25.

1. Find the ratio of(i) 16 hours to 1 day

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26.

x² + a-6 = 0Find the valueofa5 +8+3=?

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3 and -2 and 16 is the correct answe

27.

Find the value of tif r = 2, y = 1 is a solution of equation 2x + 3y=k.27

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if value of 2 is 2 and value of y is 1 then 2*2=4 and 3*1=3 then 4+3=7

given,×=2,y=1 is a Solution of 2x×3y=k2×2+3×1=k4+3=k7=kso,k=7

2*2+3*1=k 4+3=7is the right answer

28.

The measures of the angles in a linear pair are x° and(x 30°) Find the measure of each of them

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x+(x+30°)=180° (linear pair)2x+30°=180°;2x=150°;x=75°then the angles are 75° and 105°

29.

if X=52 then find x√4

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x√4 = 52√4 = 52×2 = 104

30.

\sqrt{5}=2.236 \quad \sqrt{125}-\frac{1}{5} \sqrt{500}=?

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root(5)=2.236so root(125)=5root(5)root(500)=10root(5)so 5root(5)-10root(5)/5=5root(5)-2root(5)=3root(5)=3*2.236=6.708

31.

)Write two equivalent fractions for each/using division\frac{100}{125} \quad(i i) \frac{124}{144} \quad\left(\text { iii) } \frac{200}{300}\right.

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i) 100*2/125*2 = 200/250

100*3/125*3 = 300/375

wrong

32.

-+4+20का मान है।X4+20

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1/2+4+20/1/2*4+20=1/2+24/2+20=1+48/2/22=49/44

33.

( i v ) \quad \sqrt [ 3 ] { ( 16 ) ^ { - 3 / 4 } \times ( 125 ) ^ { - 2 } }

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34.

1 \quad 1 \quad b ) - 1 \quad c ) 0 \quad d ) 2

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35.

2v3 9(3) В2 3 /3

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36.

: ( 4 + 3 \sqrt { - 20 } ) ^ { \frac { 1 } { 2 } } + ( 4 - 3 \sqrt { - 20 } ) ^ { \frac { 1 } { 2 } }

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37.

Q2.Solve for 4v3x2 + 5x -2V3 0

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38.

1. Prove that 5-2V3 is an irrational number

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thank you so much

Hii friend!!assume that 5 - 2√3 is rational5- 2√3 = a/b , where a and b are integers .-2 √3 = a/b - 52√3 = 5 - a/b2√3 = (5b - a)/b√3 = )5b - a)/ 2bwe know that a, b , 2 and 5 are integers and they are also rationaltherefore √3 will be rationalbut we know that root 3 is irrationalthere is a contradictionso, 5 - 2√3 is an irrational number

39.

If14]X"に4 2 1.find x.8 44)4) If | 1 | X1 2 11, find X.-3 6 3

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40.

A student rank 19th in the class of 50.What is his rank from the last?

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According to question a student is ranked 19th in the class of 50, that means there are 50 - 19 = 31 students behind him.which implies that the student is 32nd from the last

41.

s. Find x, y,x,tif 2 []+36-1323135. Find x, y, x,t if 214 61Lyt+370-

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what is tha solution

42.

\frac 5 \operatorname cos ^ 2 60 %2B 4 \operatorname sec ^ 2 30 - \operatorname tan ^ 2 45 \operatorname sin ^ 2 30 %2B \operatorname cos ^ 2 30

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43.

2^x+2^x+2^x=192. Find x.

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44.

(X + 1/X)^3 = 33 find X+1/X

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45.

\frac { 5 \operatorname { cos } ^ { 2 } 60 ^ { \circ } + 4 \operatorname { sec } ^ { 2 } 30 ^ { \circ } - \operatorname { tan } ^ { 2 } 45 ^ { \circ } } { \operatorname { sin } ^ { 2 } 30 ^ { \circ } + \operatorname { cos } ^ { 2 } 30 ^ { \circ } }

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46.

If x²+1/x²=34 find x³+1/x³-9

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X^² + 1/x^² = 34

x + 1/x =√ (34 + 2) = 6

x^³ + 1/x^³ = (x + 1/x)^3 - 3 x/x (x + 1/x) = 6^3 - 3 * 6 = 198

47.

Find XFind x.126234

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x+52+74=180; x= 180 - 126 = 54

52°+74°+x= 180°by angle sum property 126+x=180x=180-126x=54 °

48.

if x-1/x=5 find x^2+1/x^2

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49.

wing complenO namber

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answer is zero because in last step is coming (-1+1)power 3 ao answer us o..

50.

Arithmetic mean of 7 observations was found to be 32. If one more observation48 was to be added to the data what would be the new mean of the data?

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Mean= sum of observations/total observations32= sum/7224=sum of observationsIf 48 is added to the data, then sum will be224+48= 272new sum=272new mean=new sum/total observations=272/8=34New mean=34