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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Direction (0.96-97): Choose the odd numeral group or odd letter group.নির্দেশনা (৯৬-৯৭ নং প্রশ্ন) ও নিমিলা সংখ্যাৰ জোট বা বৰ্ণৰ জোটটো বাছনি কৰা96. [A] 924 [B]97–3[C]64–2[D]50–5 |
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Answer» Opti on Bas other are divisible by same number inas 92/4 is divisiblebut 97/3 is not so B(97-3) is odd.thanks |
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| 2. |
In which quadrant does the point (2V3,-V2) lie?(A) |st quadrant(C) 3rd quadrant(B) 2nd quadrant(D) 4th quadrant |
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Answer» Option DAs x axis is positive and y axis is negative. |
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| 3. |
Point (-3, 5) lies in the(A) First quadrant (B) Second quadrant(c) Third quadrant (D) Fourth quadrant |
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Answer» second quadrant is the right answer 2 quadrant is correct |
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| 4. |
10. Coordinate axis XOY is known as :(A) first quadrant(C) third quadrant(B) second quadrant(D) fourth quadrant |
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Answer» It is known as first quadrant |
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| 5. |
के 3 हट 97 |
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Answer» 5*4*2 + 4 - 2 = 40 + 4 - 2 = 42. |
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| 6. |
97+537 |
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Answer» 436 is the answer ok.... 634 is the your calculation answer 634 the correct answer of the given question 634 is correct answer of following question 634 is the correct answer of your given question 634 is the correct answer 634 is the right answer 634 is right answer.... 634 is the right answer |
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| 7. |
Find the length of a side of a square whose perimeter is(a) 12 cm(b) 10.4 cm |
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Answer» Given:Perimeter of square = 4 X side =12=side = 12/4= side = 3 Therefore, the length side of a square is 3cm. |
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| 8. |
_(2%+ 30 - 97 |
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Answer» a^2 - b^2=(a+b)(a-b)=(2x+3y+3z)(2x+3y-3z) |
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| 9. |
10. Show that the rank of a skew-symmetric matrix cannot be unity |
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Answer» Thanks bhai |
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| 10. |
4 ^ { - 3 } \quad \text { (ii) } ( - 2 ) ^ { 7 } \quad \text { (iii) } ( \frac { 3 } { 4 } ) ^ { - 3 } \quad \text { (iv) } ( - 3 ) ^ { - 4 } |
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Answer» 4^(-3)=1/64(-2)^7=-128(3/4)^(-3)=64/27(-3)^(-4)=1/81 |
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| 11. |
To get 35% of a number,the number should be multiplied by(a) \frac { 7 } { 20 } \quad ( b ) 3.5 \quad ( c ) \frac { 7 } { 50 } \quad ( d )0.035 |
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Answer» (35/100)=(7/20)Ans:(a) PLZZ solve this question. |
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| 12. |
\left. \begin{array} { l } { ( - 4 ) + \frac { 2 } { 3 } } \\ { \frac { - 1 } { 8 } + \frac { 3 } { 4 } } \\ { \frac { - 1 } { 8 } + \frac { 3 } { 4 } } \\ { \frac { 3 } { 13 } + ( \frac { - 4 } { 65 } ) } \end{array} \right. |
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Answer» i) -6ii) -3/10iii) 4/15iv) -3/2v) -14/13vi) 91/24vii) -15/4 |
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| 13. |
find other trigonometry ratioIf sin e -&of angle A. |
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Answer» This question is not right. Because sinA=8/7 it is wrong it should be sinA=7/8 |
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| 14. |
( \frac { 2 } { 4 } - \frac { 1 } { 5 } ) ( 1 \frac { 3 } { 4 } + \frac { 4 } { 3 } ) \div ( \frac { 1 } { 5 } + \frac { 4 } { 15 } - \frac { 2 } { 5 } ) |
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Answer» firstly solve the brackets2/4 - 1/5 = 6/20 = 3/107/4 + 4/3 = 37/121/5 + 4/15 - 2/5 = 1/15put the values 3/10 * 37/12 * 15/1111/8 |
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| 15. |
1 \frac { 3 } { 7 } \text { of } 5 \div \frac { 3 } { 4 } + \frac { 2 } { 3 } \times \frac { 3 } { 4 } - \frac { 2 } { 3 } |
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Answer» but the answer is 131/14 |
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| 16. |
In the figure, Q is the centre of the circleand PM and PN are tangents to the circle.If < MPN = 40°, find <MQN. |
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| 17. |
The floor of arectangulan nooro 4.8 mint3.6 m is to be pared wit squareside 12 cm. Find the cost of AE LEo pertiles ttile |
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Answer» Area of room= 4.8*3.6= 17.28m= 1728 cmnumber of tiles= 1728/12= 144tilescost= 144*1.50216 ruppesthanksplease like the solution 👍 ✔️ Thanks |
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| 18. |
A-. Standard Car develop 40-hpFind the maximum Speed, the Car can attain the resistant of 20 kg weight due to air and friction. Given the efficiency of engine is 25%. |
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| 19. |
findllreal.skew-symmetric matrix cannot be unitythe rank of a skew-shat condition, the rank of the following m0thatnt |
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| 20. |
Note: Attempt questions from LIITSECTION - AAnswer any two questions from this section.Q1. (a) Find the rank of this matrix:11 0.21A-10 2 4 20 2 2 1(b) What is the idea of redundant or superfluous endoes the concept of rank help you determine if a ssuperfluous equation in it?will use the concent of rank of a matri |
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Answer» A=2375 & 5432 & 5432 rank will be 3 eliminate the column 1 2 1 then find det here det not equal to zero ie rank =3 |
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| 21. |
In a class of 45 students, a boy is ranked20th When two boys joined, his rank wasdropped by one. What is his new rankfrom the end?(a) 25th(b) 26th(c) 27th(d) 28th |
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Answer» After 2 boys joined, total strength of class = 45 + 2 = 47 As rank was dropped by one from 20th rank, new rank is 21st. Rank of the boy from the beginning = 21 Number of students below his rank = 47 - 21 = 26 Rank from the end = (47 - 21) + 1 = 27 |
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| 22. |
In a class of 46 students, Shweta's rank is 31st from the beginning while Pawan's rank is 27th from thelast. How many people are there between Shweta and Pawan?(a) 13(c) 11(b) 12(d) 10 |
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Answer» 27th from the last means:46 - 27 + 1 = 20th from the beginning thus as Shweta is 31st person and Pawan is 20thPeople between them are from 21st to 30thtotal 10 people between them. |
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| 23. |
x² + 3x-518.1f3x-5find xx+2x–72x - 7(2) -1(5) 2(1)-2(3) 3 |
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Answer» tq |
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| 24. |
express the trigonometry ratio s sin A sec A and tan A in terms of cot A |
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| 25. |
7. Find the derivative of the function tan- (log x). |
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| 26. |
RANKDATEPAGE |
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Answer» answer is 40 we know that all alternate angles are same then x=40 |
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| 27. |
(iv) 0.2x+03y=13बी . भर |
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| 28. |
5. Find x such thatx-2 |
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Answer» 122344566780 3 4 5 6 7 8 9 10 12 12 I want to know the answers for these questions if you have brain I want the answers for this questions if you have brain fastly give the answers upto 1 clock [7\4] answer is this www h h h a a t t t what what what |
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| 29. |
Find the mode of the data given below:Class20-29 30-39 40 49 50-59 60-69Frequency 1520503010 |
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| 30. |
(iv) 0.2x+03y=1.30.4x+0.5y=23 |
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Answer» Please like the solution 👍 ✔️👍 |
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| 31. |
1. In the figure, Q is the centreof the circle and PM and PNare tangent segments to thecircle. If/ MPN = 400.find L MQNanr |
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Answer» Q is the center.PM and PN are tangents.MPN=40.MPN + MQN=180MQN=180 - 40MQN = 140. |
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| 32. |
is asolivion ofVerifi whether Xz3Leo Pation 28-3=0 |
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Answer» Given: eq:2x-3=0solution x=3Now substituting x=3 in the equation2(3)-3=06-3=03=0Thus x=3 is not a solution for the above equation |
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| 33. |
s. the thickness of a metallic tube is 1 cm k ter iner diameter of the tues 12em. Fin thewightof 1 m long tube if the density of the metal be8 gm/cm |
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| 34. |
दर कटे 2:-! =Nad . ....... ? Rएक थेले सें 3. लालऔर 5 कॉली गेंद हैं । इस थैले में से एक गेंदयादूच्छया निकाली जाती है इसकी कया प्रायिकता है कि गेंद (1)लाल हों? (2) लाल नहीं हो, |
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Answer» (1)3/(3+5)=3/8(2)5/(3+5)=5/8 |
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| 35. |
746 liter +246 l 60 ml +615 l 45 ml |
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| 36. |
2. Find value of other five trigonometry functiontan = =,x lies in third quadrant |
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Answer» Hi Khushpreet, This question is wrong as X lies in third quadrant. we know that tan and cot are positive in third quadrant. But in the question it is given negative so the question is wrong or there's a printing mistake in the question. |
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| 37. |
8. Mala gave Kamala half the number of sweetsshe had. She then had 7 sweets left. How manysweets did Kamala have? |
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Answer» Mala gave half the number of sweetsnow if 7 sweets are left.then before she had 14 ,it's double therefore Kamala have 7 sweets. ssgvvvguuj yhgahy ujdu6d ddgi gshhz yyhf ahha yhjs uiis hjjjw jjddf hjjjd jjjka jajkskd ndnnd bjnnd jjdb |
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| 38. |
17.If VO.04x 0.4x a = 0.004 Ă 4 Ă Vb , then find the value ofa. |
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Answer» take square in both the sides(0.04×0.4)×a=(0.004×4)^2bso a/b=(0.004×4)^2/(0.04×0.4)=0.016 |
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| 39. |
Mala gave Kamala half the number of sweetsshe had. She then had 7 sweets left. How manysweets did Kamala have? |
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Answer» Let Mala have x chocolates. x - (x/2) = 7 2x - x = 14 x = 14∴ Mala had 14 sweets. Kamala had 7 sweets. |
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| 40. |
04x+ 03y 1707x-02y 08 |
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Answer» 4x+3y=177x-2y=8 8x+6y+21x-6y=34+2429x=58so x=28+3y=17so.3y=9so y=3 |
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| 41. |
/ प्रश्नावली उ (8).के प्रयोग से निम्नलिखित आद्यूहों के व्युत्क्रम (7ERT) e b (NCERT]ERT) | IJ ) RT) e NCERo T |
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Answer» Like if you find it useful |
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| 42. |
(iv) 0.2x+03y=1304x+0.5y=23 |
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Answer» .2x +.3y = 1.3...... (1).4x +.5y = 2.3.......(2) Mutiply eq(1) by 2 .4x +.6y = 2.6.4x +.5y = 2.3 Subtract these equations.1y =. 3y = 3 Put value of y in eq(1) .2x +.9 = 1.3.2x = 1.3-9 =.4x = 2 Hence, x = 2, y = 3 |
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| 43. |
ea of a triange whose perimeter is 40 cm, one side is 1Find the area of a te of other two sides is 7cmand the difference of other twnose perim |
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| 44. |
3) Point (-3, 5) lies in the) First quadrant (B) Second quadrant) Third quadrant (D) Fourth quadrant |
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Answer» (B) Second quadrant. As x = -3 , so it is at left from origin on x-axisand y= 5 , it is above from the origin on y-axis. (B) second quadrant -3 is in negitive x axis and 5 is in positive y axis so it is in second quadrants (B) |
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| 45. |
16y2) + 4xy(3x + 4y)he ErT |
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| 46. |
, x lies in third quadrant2x |
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Answer» Post complete question |
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| 47. |
Date:Page no:Dinide the polynomialProc Nad - 30c2 tsa-3g glaz 22-2 |
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| 48. |
\frac { ( 3 x + 1 ) } { 16 } + \frac { ( 2 x - 3 ) } { 7 } = \frac { ( x + 3 ) } { 8 } + \frac { ( 3 x - 1 ) } { 14 } |
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Answer» 3x/16 +1/16 + 2(2x)/14 -2*3/14 = 2x/16 +6/16 +3x/14 -1/14 => x/16 +x/14 = 5/16 +5/14=> x(1/16+1/14) = 5(1/16+1/14)=> x = 5 |
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| 49. |
\frac { x + 7 } { 3 } - \frac { 3 x } { 5 } = x - 2 - \frac { 3 x - 11 } { 2 } |
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| 50. |
1. Find the value ofx if (t)2x=21665(5)(6/125-2162. Find the value of(81)0.16x(81).092. Find the value of(81)0.16 Ă (81)0.09 |
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