(iv) 0.2x+03y=1304x+0.5y=23 – InterviewSolution

1.

(iv) 0.2x+03y=1304x+0.5y=23

Answer»

.2x +.3y = 1.3...... (1).4x +.5y = 2.3.......(2)

Mutiply eq(1) by 2

.4x +.6y = 2.6.4x +.5y = 2.3

Subtract these equations.1y =. 3y = 3

Put value of y in eq(1)

.2x +.9 = 1.3.2x = 1.3-9 =.4x = 2

Hence, x = 2, y = 3

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