This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Find the value of x.irFind the value of x. if2*Find the value of xt (2x+7) |
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| 2. |
umbers bertween 20 and 302What are a |
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Answer» 23 and 29 hit like if you find it useful |
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| 3. |
Espress 121 as the sof 11 odd umbers |
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Answer» Therefore, 121 is the sum of first 11 odd natural numbers. 121 = 1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19 + 21 |
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| 4. |
umbers are there in all in the number system?bal |
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Answer» Last four digit number is 9999 So there are 9999 numbers till last 4 digit number. Now we want just four digit numbers so we can get them by subtracting numbers other than 4 digit number from 9999 i.e. from 1 to 999 So, 9999–999= 9000 numbers |
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| 5. |
Sum of tuwo umbers 72 TheisLeM lo. Find the two numbers |
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Answer» sorry it's wrong 4+5 is not 72 Sorry, it was calculation error. Apologising for the error in the solution. This is the correct solution. |
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| 6. |
ths of the parallel sides of a trapezium are in the ratio 3:5 and the distancIf the area of trapezium is 120 cm2, find the lengths of its parallel sidese between them ishe leng0 cm. |
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| 7. |
Ed, the dle team of thsthe middlleo bart The suunSung8 |
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Answer» can u solve my another sum of trigonomerty |
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| 8. |
ing., PQ | | RS, LQPR = 70°, LROT = 20°, find the value of x.70°20 |
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| 9. |
In the given figure, if ZAOC- (2x-10)° and<BOC = (3x + 20)" ,find ZAOC and ZBOC.. Find the value of x. AlsoCr(3r+ 20) |
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| 10. |
In the given figure, if LAOC (2x-10)° andBOC = (3x + 20 )。. Find the value ofx. Also,find ZAOC and ZBOC.(2-10 (3+20)ngles. the |
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Answer» 2x-10+3x+20=1805x+10=1805x=170x=34°AOC=2×34-10=58°BOC=3×34+20=122° |
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| 11. |
Yuvraj hitted 3 times centuries in 10 innings. Find the probability that didnot hit centuries ? |
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Answer» 3 times hitting centuries so 7 times not hittingso probability=7/10=0.7 |
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| 12. |
What percent is 16 hours of 2days |
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Answer» 1 days = 24hours2 days = 2 * 24 = 48 hourspercentage = (16/48)*100 = 33.3% |
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| 13. |
what fractions of a day is 16 hours |
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Answer» fraction =16/24please like my answer fraction =16/25please like my answer 16/24please like my answer 16 hours is 16/24= 2/3 fraction of a day 16/24=2/3 fraction of a day fraction= 16/24 = 2/3 |
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| 14. |
12) Sachin Ramesh Tendulkar scored 51 centuries and 68 half- centuries in his Test career of 329innings. In what per cent of innings did he score more than 50 runs? |
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Answer» Half centuries means >= 50 runs Centuries means >= 100 runs total 329 innings 51 centuries and 68 half centuries total 119 innings of more than 50 runs per cent = 119*100/329 = 36.17% If you find this answer helpful then like it. thanks |
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| 15. |
Divya waited for a bus from quarter to five until ten past five. How long did she wait for the bus? |
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Answer» 4:45 to 5;10( she waited for )25 minutes |
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| 16. |
Insert x arithmetic means between x^2 and 1 |
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Answer» thankuu |
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| 17. |
ं) ॥त the quadratic polynomial whose zeroes are 2 and -4.Find ration between the coefficients and zeroes of polynomial |
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| 18. |
If α and β are zeroes of the polynomial t-1-4, form a quadratic polynomialwhose zeroes areand0t |
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Answer» Here |
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| 19. |
67Between 1 and 31, m arithmetic means have been insertel in sach wat the ratio of the 7th and (m-Dh means is 5:9. Find the value of mia |
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| 20. |
5. Find the quadratic polynomial whose zeroes are square of the zeroes of the polynomialx2-x-1 |
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Answer» First find roots of x^2-x-1hencex=-b+-√b^2-4ac/2ax=1+-√1+4/2x=1+√5/2 ,1-√5/2hence square will be y=(1+√5/2)^2,y=(1-√5/2)^2y=1+5+2√5/4,y=1+5-2√5/4y=6+2√5/4,y=6-2√5/4hencethe quadratic equation y^2-(sum of roots)y+(product of roots)hencey^2-(12/4)y+(36-10/16)y^2-3y+13/8 |
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| 21. |
21. Ifya_ ax + by? + cd, then find lim xâ 0 |
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| 22. |
find the range of the function y=x²-1/x-1 |
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Answer» as at x= 1 system will become undefinedso range is R-{1} |
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| 23. |
14. Quadratic polynomial 2x 31 has zeroes as a and B.Now form a quadratic polynomial whose zeroes are 3o and38. |
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| 24. |
30.tif cosec θ + cot θp, then prove that cos θP2-1 |
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| 25. |
1. Find the ratio of(i) 16 hours to 1 day |
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| 26. |
x² + a-6 = 0Find the valueofa5 +8+3=? |
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Answer» 3 and -2 and 16 is the correct answe |
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| 27. |
Find the value of tif r = 2, y = 1 is a solution of equation 2x + 3y=k.27 |
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Answer» if value of 2 is 2 and value of y is 1 then 2*2=4 and 3*1=3 then 4+3=7 given,×=2,y=1 is a Solution of 2x×3y=k2×2+3×1=k4+3=k7=kso,k=7 2*2+3*1=k 4+3=7is the right answer |
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| 28. |
The measures of the angles in a linear pair are x° and(x 30°) Find the measure of each of them |
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Answer» x+(x+30°)=180° (linear pair)2x+30°=180°;2x=150°;x=75°then the angles are 75° and 105° |
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| 29. |
if X=52 then find x√4 |
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Answer» x√4 = 52√4 = 52×2 = 104 |
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| 30. |
\sqrt{5}=2.236 \quad \sqrt{125}-\frac{1}{5} \sqrt{500}=? |
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Answer» root(5)=2.236so root(125)=5root(5)root(500)=10root(5)so 5root(5)-10root(5)/5=5root(5)-2root(5)=3root(5)=3*2.236=6.708 |
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| 31. |
)Write two equivalent fractions for each/using division\frac{100}{125} \quad(i i) \frac{124}{144} \quad\left(\text { iii) } \frac{200}{300}\right. |
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Answer» i) 100*2/125*2 = 200/250 100*3/125*3 = 300/375 wrong |
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| 32. |
-+4+20का मान है।X4+20 |
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Answer» 1/2+4+20/1/2*4+20=1/2+24/2+20=1+48/2/22=49/44 |
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| 33. |
( i v ) \quad \sqrt [ 3 ] { ( 16 ) ^ { - 3 / 4 } \times ( 125 ) ^ { - 2 } } |
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| 34. |
1 \quad 1 \quad b ) - 1 \quad c ) 0 \quad d ) 2 |
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| 35. |
2v3 9(3) Đ2 3 /3 |
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| 36. |
: ( 4 + 3 \sqrt { - 20 } ) ^ { \frac { 1 } { 2 } } + ( 4 - 3 \sqrt { - 20 } ) ^ { \frac { 1 } { 2 } } |
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| 37. |
Q2.Solve for 4v3x2 + 5x -2V3 0 |
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| 38. |
1. Prove that 5-2V3 is an irrational number |
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Answer» thank you so much Hii friend!!assume that 5 - 2√3 is rational5- 2√3 = a/b , where a and b are integers .-2 √3 = a/b - 52√3 = 5 - a/b2√3 = (5b - a)/b√3 = )5b - a)/ 2bwe know that a, b , 2 and 5 are integers and they are also rationaltherefore √3 will be rationalbut we know that root 3 is irrationalthere is a contradictionso, 5 - 2√3 is an irrational number |
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| 39. |
If14]X"に4 2 1.find x.8 44)4) If | 1 | X1 2 11, find X.-3 6 3 |
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| 40. |
A student rank 19th in the class of 50.What is his rank from the last? |
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Answer» According to question a student is ranked 19th in the class of 50, that means there are 50 - 19 = 31 students behind him.which implies that the student is 32nd from the last |
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| 41. |
s. Find x, y,x,tif 2 []+36-1323135. Find x, y, x,t if 214 61Lyt+370- |
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Answer» what is tha solution |
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| 42. |
\frac 5 \operatorname cos ^ 2 60 %2B 4 \operatorname sec ^ 2 30 - \operatorname tan ^ 2 45 \operatorname sin ^ 2 30 %2B \operatorname cos ^ 2 30 |
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| 43. |
2^x+2^x+2^x=192. Find x. |
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| 44. |
(X + 1/X)^3 = 33 find X+1/X |
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| 45. |
\frac { 5 \operatorname { cos } ^ { 2 } 60 ^ { \circ } + 4 \operatorname { sec } ^ { 2 } 30 ^ { \circ } - \operatorname { tan } ^ { 2 } 45 ^ { \circ } } { \operatorname { sin } ^ { 2 } 30 ^ { \circ } + \operatorname { cos } ^ { 2 } 30 ^ { \circ } } |
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| 46. |
If x²+1/x²=34 find x³+1/x³-9 |
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Answer» X^² + 1/x^² = 34 x + 1/x =√ (34 + 2) = 6 x^³ + 1/x^³ = (x + 1/x)^3 - 3 x/x (x + 1/x) = 6^3 - 3 * 6 = 198 |
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| 47. |
Find XFind x.126234 |
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Answer» x+52+74=180; x= 180 - 126 = 54 52°+74°+x= 180°by angle sum property 126+x=180x=180-126x=54 ° |
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| 48. |
if x-1/x=5 find x^2+1/x^2 |
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| 49. |
wing complenO namber |
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Answer» answer is zero because in last step is coming (-1+1)power 3 ao answer us o.. |
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| 50. |
Arithmetic mean of 7 observations was found to be 32. If one more observation48 was to be added to the data what would be the new mean of the data? |
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Answer» Mean= sum of observations/total observations32= sum/7224=sum of observationsIf 48 is added to the data, then sum will be224+48= 272new sum=272new mean=new sum/total observations=272/8=34New mean=34 |
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