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2x² - 8x + 62x² -2x -6x + 62x(x-1) -6(x-1)(2x-6)(x-1)

very good friend

option b is the right answer

3 is the best answer

-b/a = 8/2= 4Thanks

here a=2,b=-8,c=6sum of zeroes=-b/a=-(-8)/2=8/2=4

sum of zeros are -b/a so that answer is 4

Option (d) is the right answer

Given ratio of sum of n terms of two AP’s = (7n+1):(4n+27)

Let’s consider the ratio these two AP’s mth terms as am : a’m →(2)

Recall the nth term of AP formula, an = a + (n – 1)d

Hence equation (2) becomes,am : a’m = a + (m – 1)d : a’ + (m – 1)d’

On multiplying by 2, we getam : a’m = [2a + 2(m – 1)d] : [2a’ + 2(m – 1)d’]

= [2a + {(2m – 1) – 1}d] : [2a’ + {(2m – 1) – 1}d’]

= S2m – 1 : S’2m – 1

= [7(2m – 1) + 1] : [4(2m – 1) +27] [from (1)]

= [14m – 7 +1] : [8m – 4 + 27]

= [14m – 6] : [8m + 23]

Thus the ratio of mth terms of two AP’s is [14m – 6] : [8m + 23].

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Here sum of Observations = x1+ x2 + ....... + xnNo. of observations = n

Mean = x bar , As the bar can't be represented here I am taking it as i.e. x bar = b, for better understanding,

Now,b = (x1+ x2 + ......+ xn)/n=> bn = x1 + x2 + x3 + ..... + xnMultiple both the sides with a=> abn = ax1 + ax2 + ax3 + ..... + axn

Now we got the value of ax1 + ax2 + ... + axn

Now new mean or Required mean is,

New mean = (ax1+ ax2 + ... + axn )/n=> New mean = abn/n=> New mean = ab

Here b = x bar, As I said above , So the new mean = a * x bar

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thanks

Given that, mth term=1/n and nth term=1/m.

then ,let a and d be the first term and the common difference of the A.P.

so a+(m-1)d=1/n...........(1) and a+(n-1)d=1/m...........(2).

subtracting equation (1) by (2) we get,

md-d-nd+d=1/n-1/m=>d(m-n)=m-n/mn=>d=1/mn.

again if we put this value in equation (1) or (2) we get, a=1/mn.

then, let A be the mnth term of the AP

a+(mn-1)d=1/mn+1+(-1/mn)=1 hence proved.

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Given,A+B = 90°=> A = 90 - B tan A = cot B=> tanA = tan(90-B)=> tanA = cotB [∵ tan(90 - θ) = cot θ]

a1 = 2+1=3

a2 = 4+1= 5

a3 = 6+1 = 7

The common dicfrence d = 2

Given terms is AP are(x + b), (x + 3b), (x + 5b)....

Then,a1 = (x + b)common difference d= (x + 3b) - (x + b) = 2b

General term of an APan = a1 + (n - 1)*(2b) = (x + b) + 2bn - 2b = x + (2n - 1)b

General term will be

rth term = 10Cr (2x²)^(10-r) × (1/3x³)^r

For an APGeneral term or nth termTn = a + (n-1)d

Where,a ( first term) = 5d (common difference) = 8-5 = 3

Therefore, General term = 5 + (n - 1)3 = 2 + 3n

Distance Travelled= 280 m

Speed of the train = 42km/h= 700/60m/s

Using the formula Time = Distance/Time

= 280÷700/60

= 280×60/700

= 16800/700

= 24s

5will be the ans.......

please send solved answer

Distance covered = length of tunnel + length of train= 500m.Time = 30secSpeed = distance/ time= 500/30.= 50/3 m per sec

this answer is correct , thank you to solve it

where is the answere

∵ Speed of the train = 60 x (5/18) m/sec = 50/3 m/sec∴ Time taken by the train to cross the platform= Time taken by it to cover (280 + 220) m= (500 x 3/50) sec = 30 sec

Total distance to cover = 280 + 220 =500 m= 0.5 km

Time = distance /speed = 0.5 (km) /60 (km/hr) = 0.0083333333. Hour

In minute, = 0.008333*60 Time = 0.5 minutes

In seconds, Time=30 seconds.

280+220=500 is the total distancespeed=60 km/htime=distance/speedtime=.500/60=.00833h =.5 min =30 sec

Since the length of the tree is negligible, so distance in first case is taken as the length of the train.

Speed = Distance / Time= 120/5= 24 m/s

Now ,

Distance = ( 120 + 180 ) = 300 mSpeed = 24 m/s

Time = Distance / Speed= 300 / 24= 25/2= 12.5 seconds

length of train is 250mlength of platform is 350mso to cover platform fully train has to travel 250+350=600mtrain is covering this in 50sso speed of train is 600/60=10 m/s

now length of platform is 230mso to cover platform fully train has to travel 250+230=480mand speed is 10m/sso time required is 480/10=48s

no it's wrong answer dear

Wall Built = 448m; Time Taken =27 days; Men working = 56 men

Wall builtby 56 men in 1 day = 448/27mWall built by 1 man in 1 day = 448/(27x56) = 56/189m

Now,Wall left to be built = 552m; Time left = 23 days;Total men required to complete the rest of work = x

Wall built by x no. of men in 1 day = 56x/189mWall built by x no. of men in 23 days =(56*23)x/189 = 1288x/189Thus,1288x/189 = 552 (As x no. of men have to build 552m of wall)1288x = 104328x = 104328/1288x= 81menTherefore, extra men required = 81-56 = 25 men

Wall Built = 448m; Time Taken =27 days; Men working = 56 men

Wall builtby 56 men in 1 day = 448/27mWall built by 1 man in 1 day = 448/(27x56) = 56/189m

Now,Wall left to be built = 552m; Time left = 23 days;Total men required to complete the rest of work = x

Wall built by x no. of men in 1 day = 56x/189mWall built by x no. of men in 23 days =(56*23)x/189 = 1288x/189Thus,1288x/189 = 552 (As x no. of men have to build 552m of wall)1288x = 104328x = 104328/1288x= 81menTherefore, extra men required = 81-56 = 25 men

25/13 was the correct answer

It will be 25/13as 25/13*13/25= 1thanks

5-5x+3+3x=81-2x8-2x=81-2x-2x=8-81-2xX=8-8×1-2/-2X= 8-(4)^2×1-2/-2X= 8+4/-2X= 12/-2X= -6

Given A=45 degre To find:Cos^2 ASolution:cos 45degree=1/ root 2Now cos ^2 A=cos ^2 45 degree= 1/ root 2 * 1/ root 2=1/2

Let n a.m, between a,b are a1,a2,a3,............ana,a1,a2,a3,.............an,bsum of n a.m.Sn = n[2a1 + (n-1)d]/2 ----------(1)a.m. of a,b is (a+b)/2b = a+(n+1)da.m. = [2a+(n+1)d]/2 -------------(2)a1 = a+d put in (1)Sn = n[2a + 2d + (n-1)d]/2 = n[2a+(n+1)d]/2 ------------(3)from equation (2) & (3)Sn = n*a.m.where d = common difference of a.p.

correct answer is x = 3, y = 2, z = 3

9000/2=4500/2=2250/5=450/5=90/5=18/3=6/3=2 ; 2^3 x 3^2 × 5^3 ; X=3; Y=2: Z=3

2 + 10d = 11

10d = 11-2

d = 9/10

So, second am = 2+9/10 = 29/10

third am = 29/10 + 9/10 = 38/10, and so on

wroung

answer 2,3,4,5,6,7,8,9,10

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