Saved Bookmarks
This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
One third of a number is 10 less than the original number. What is the number? |
|
Answer» Let the number be x 1/3 of x =x-10 X/3= x-10 Cross multiply X=3x-30 Collect like terms X-3x=-30 -2x=-30 Divide both side by -2 X=15 The number is 15 |
|
| 2. |
2. Find the roots of the quadraticequations given in Q.1 above byapplying the quadratic formula.) 2x2-7x +3 0 |
| Answer» | |
| 3. |
(c) Determine the value of k for which the given quadratic equations have equal roots: (4(2p+1) x2-(7p + 2) x + (7p3) =0. |
|
Answer» (2p + 1)x²+ (7p+2)x + (7p-3) = 0If they have equal roots,b²-4ac=0Let,a=2p+1b=7p+2c=7p-3Now,(7p+2)²- 4(2p + 1) (7p-3)=049p²+4+ 28p – 4(14p²+p-3)=0After simplification,7p²-24p+16=0The roots are,4 and -4/7. |
|
| 4. |
g quauratic equations. If the real(i) 3x2 -43x+4 ong quadratic equations so that the |
| Answer» | |
| 5. |
ध्यु 2 2-0: ४X U1 -y um |
| Answer» | |
| 6. |
(¥E303 + X6W09) 4 (15800 + £/ 900) |,X9 U= g e + X6, U1%) + (Y5 Wis 7 ¥/ ugs) |
|
Answer» LHS = [(sin7x + sin5x) + (sin9x + sin3x)]/[(cos7x + cos5x) + (cos9x + cos3x)] use the formula, sinC + sinD = 2sin(C+D)/2.cos(C-D)/2cosC + cosD = 2cos(C+D)/2.cos(C-D)/2 = {2sin6x.cosx +2sin6x.cos3x}/{2cos6x.cosx + 2cos6x.cos3x} = 2sin6x.(cosx + cos3x)/2cos6x(cosx+cos3x) = sin6x/cos6x = tan6x = RHS |
|
| 7. |
the following quadratic eqtuationo(iii) 4m22-8m + 5 = 0.9, lf a = 1, b-8, c#15, find the value of b2-4o, Form quadratic equations from the informagiven below:() The sum of seven times a natural nu(x) and its square is 60.(ii) The sum of a natural (m) and its recip10isIf one root of the quadratic equx2-7x+k=0is2, find the value of k.If x4 is one of the roots of the quaequation kx +5x-12-0, find the valueSolve the quadratic equation 9y- 100ctorization method |
|
Answer» Please post complete question.. part of the questions are missing.. |
|
| 8. |
Solve the quadratic equations. |
| Answer» | |
| 9. |
SX(3111.+x-coscos14-N2sin xउत्तर प्रदेश मद्गण वर्ष 2019-20 |
|
Answer» -√2 sin x is the right answer of the following =-root 2sinx is the correct answer -√ 2 sinx is the correct answer -√2 sin x is the right answer of the following |
|
| 10. |
ଏ ସମୀକରଣର କୟ x ୨B ହେଲେ +| ର ମୂଲ୍ୟ କେତେ ?() 4x2x ।। (୩) .. (b) । (e) , (d) ।(vi) 4x + 3x + 7 = 0 SPYEYE 661 60%, 4 3 3 696% . . © 29 666(vi) ଗୋଟିଏ ଦିଘାତ ସମୀକରଣରେ ମକଦୟର ସମ ଓ ଗୁଣଫଳ ପଥାକୁ । ଏ ହେଲେ ସମୀକରଣଟନିମ୍ନଲିତ ମଧ୍ୟରୁ କେଉଁଟି ? |(b) 2x - &x + S= ()(a) 2x3 + Sx + 3 = ) ।(e) 21 + 8x 5 = (0)(d) 2x - $x - 5 = (). ନିମ୍ନଲିତ ଦ୍ବିଘାତ ସମୀକରଣମାନଙ୍କୁ ପୂର୍ଣ୍ଣ ବର୍ଗରେ ପରିଣତ କରି ସମାଧାନ କର ।(i) x + x 6 0(ii) 2x? ୨x + 4 0(iii) 14x7 + X 3 = () (iv) 3x2 – 32x + 12 = () ।(v) x + 2px 3qx 6pg = ) (v) v3 x + 10 + ୫ v3 = ()(vii) 25x? + 30x +7= ) (viii) 3ax + ୫abx + b = () (a # (0)(ix) x* + ax + b = () । (x) x' + bx = arab ।5, ଦ୍ଵିଘାତ ସୂତ୍ର ପ୍ରୟୋଗ କରି ନିମ୍ନଲିଖୁତ ସମୀକରଣମାନଙ୍କର ବୀଜ ବା ମୂଳ ନିରୂପଣ କର ।(i) 4x7 - 1lx + 6 = ) (ii) (2x – 1) ( x– 2) = ()(iii) x - (1+ V2 )x + 2 = () (iv) a(x++1) = x ( a + 1), a * 0(v) 6x3 +1lx+ 3 = (0) (vi) 2x + 41x -- 115 = () ।(vii) 12x• + x 6= (0) (viii) (6x +5) (x –2) = ()(ix) 15xx 28 = 0 (x) (x + 5) (x –5) == 396. ଯହି 4x13x+ka ) ସମୀକରଣର ଗୋଟିଏ ମୂଳ ଅପରଟିର 12 ଗୁଣ ହେଲେ k ର ମୂଲ୍ୟ ନିରୂପଣ କର ।।7. x 5x + p= 0 ସମୀକରଣର ଗୋଟିଏ ମୂଳ ଅପରଟି ଅପେକ୍ଷା 3 ଅଧ୍ୟକ ହେଲେ p ର ମୂଲ୍ୟ ନିରୂପଣ କର ।।୫. ଯଦି 2x-5x +3 =ସମୀକରଣର ମୂଳୟ ୯ ଓ } ହୁଏ ତେବେ ଏ+ab ର ମୂଲ୍ୟ ନିରୂପଣ କର ।[32] |
|
Answer» what is your question 2x^2-5x+3; 2x^2-3x-2x+3=0;. X(2x-3)-1( 2x-3)=0; ( 2x-3)(x-1)=0; 2x=3; X=3/2; X=1 2x-1/x=02x^2-1/x=02x^2+0x+1=0A+B= 0/2=06)4x^2+3x+7=0A+B= -3/4AB= 7/41/A+1/B= B+A/AB= -3/4/7/4=-3/7 |
|
| 11. |
2Using AP, find the sum of all 3-digit natural numbers which are the multiples of 7. |
|
Answer» The first three digit number which is divisible by 7 is 105 and last three digit number which is divisible by 7 is 994. This is an A.P. in whicha= 105, d = 7 and l = 994. Let the number of terms be n . Thentn= 994. nthterm of A.P = tn= a + (n - 1)d. ⇒ 994 = 105 + (n -1)7. ⇒ 889 = 7(n-1) ⇒ n -1 = 127 ∴ n = 128. ∴ There are128 three digit numbers which are divisible by 7. |
|
| 12. |
22Using AP, find the sum of all 3-digit natural numbers which are the multiples of 7. |
|
Answer» Smallest three digit number divisible by 7 = 105 and the largest = 994An = 994A = 105D = 7n= ?An = A + [ n - 1] Dthus994 = 105 + [ n - 1 ] 7thus by solving furthern = 128 now,Sn = n/2 [ A + An] Sn = 128/2 [ 105 + 994]thus,Sn = 70336.Thus the sum of all the three digit numbers divisible by 7 is 70336. |
|
| 13. |
on Y95ual camera10 5 |
| Answer» | |
| 14. |
6.(3x2-4x3-3x3+2x2) को हल करें। |
|
Answer» 6-12-9+4=6-21+4=-21+10=-11 is the right answer -11 is the right answer. -11 is the right answer of the following (3×2-4×3-3×3+2×2)=-11 -11 is the correct answer -11 is the right answer of the following |
|
| 15. |
(3) (3x+ 2x2 + 4x3) รท (x-4) |
|
Answer» hit like if you find it useful |
|
| 16. |
c-9. Solve the equation x* + 4x3 + 5x2+2x 2 0, one root being-11. (15JM110374) |
| Answer» | |
| 17. |
II + XT-X-X1 + xG-XI-X SX+S-XI-X |
|
Answer» 9(x-3)-2(x-1)=5(x-3)(x-1)/ x+1=9x-27-2x+2=5(x+3); 7x-27=5x+15; 2x-8; 2x=8; x=8/2=4 8/x+5 -3/x-1 +1/ x-5=8(x-1)(x-5)+3(x+5)(x-5)-1(x+5)( x-1)=8(x^2-6x+5)-3( x^2-25)+1(x^2+4x-5)=8x^2-48x+40-3x^2+75+x^2+4x-5=6x^2-44x+40(75)(5)=6x^2-44×+24 x/1-x + 1-x/x=13/6; x^2+(1-x)^2/x(1-x)=x^2+1-x^2/x-x^2=1/x-x^2=13/6; 6(1)=13(x-x^2); 13x-13x^2-6=0; |
|
| 18. |
hedtulndheight202. Find the lateral surface area and total surface area of a cube ofedge 10 |
| Answer» | |
| 19. |
464+513+646-661 |
|
Answer» 962 is the right answer 962 is the correct answer of the given question this correct answer is 962 962 is the right answer the 464+513+646-661=962 is right answer 1623-661:962 Accept as best 926 is right answer........ the right answer is 962 962 is the correct answer 962 is the correct answer of the given question 962 464+513+646-6611623-661=962 answer of your question is 962 464 + 513 + 646 - 661(464+513) + (646 - 66) ( 977 ) + ( 15 ) { 962 } 962 962 is the correct answer this correct answer is 962 962 is a right answer 464+513+646_661=977+646_661=1623_661=962 962 is the correct answer your question please like 962. is right answer 962 is the correct answer h 962 is correct answer 464+513+646-661977+646-6611623-661962 464+513+646-661=1623-661=962 464+513+646=16231623-661=962 664+513+646-661=1823-661=1162...(Ans) |
|
| 20. |
py and completBase 6Height 10Area?nd the area, in |
|
Answer» base=6 height=10area=1/2*base*height=1/2*6*10=30 |
|
| 21. |
fows through a cylindrical pipe of internal diameter 7 cm at 36 km/h. Calculiase fe time mit would take to fill a cylindrical tank, the radius of whose base is 35 cm nd height I mPWater |
|
Answer» than thnx |
|
| 22. |
sa parallelogram (Fig 1123) QM is the height firomQs2Pnd QN is the height from Q to PS. If SR16cm. Find-12 cm and |
| Answer» | |
| 23. |
elndnce over, to level a playground. Find the area of the playgrotltt ind the volume of the earth dug out from a circular well of 24.5 m deep and 3 m radius.it height is 4 m. How many7 Fi |
| Answer» | |
| 24. |
poles of height a metresand b metres areP metres apart. Prove that the height h of thepoint of intersection N of the lines joining thetop of each pole to the foot of the opposite poleaba + bIS metres. |
|
Answer» Let the height of the two trees AB and CD be b and a respectively.Distance between the trees BC = pLet EF = h be the height of point of intersection of the lines joining the top of each tree to the foot of the opposite trees.Let CF = x then BF = (p – x)In Δ’s ABC and EFC,∠ABC = ∠EFC = 90°∠C = ∠C (common angle)∴ ΔABC ~ ΔEFC (By AA similarity theorem)b/p= h/xbx= ph |
|
| 25. |
(iv) sce?27° — cot? 63° I मवलऊभ गाल 1.e B RS हि पर 39, |
| Answer» | |
| 26. |
what value of log5 513 |
|
Answer» tq |
|
| 27. |
12. Two poles of height a metres and b metresare p metres apart. Prove that the heightof the point of intersection of the linesjoining the top of each pole to the foot ofthe opposite pole is given by o metresaba + b |
| Answer» | |
| 28. |
37. Two poles of height a metres and b metres are p metres apart. Prove that theheight of the point of intersection of the lines joining the top of each pole to theaba +bfoot of the opposite pole is gives bymetres |
|
Answer» clear writing bhejo achi handwriting nhi hai kharab hai |
|
| 29. |
तब-bcosCXasini+1=-,तब x=a तथा y= 0 है अत: 1-7 पर अर्थात (a.oy पर दिए गए वक्र कीy-0 = 0 (x-a) अर्थात् = 0 है।समीकरणप्रश्नावली 63क्रy= 3x4-4x के x = 4 पर स्पर्श रेखा की प्रवणता ज्ञात कीजिए।कy_2Sx#2 के x = 10 पर स्पर्श रेखा की प्रवणता ज्ञात कीजिr-1 |
|
Answer» वक्र का समीकरण y = x³ - 3x .......(1) इसमें x = 2 रखने पर y = 2³ - 6 y = 2 •°• वक्र पर वह बिंदु P(2,2) वक्र का समीकरण y = x³ - x x के सापेक्ष अवकलन स्पर्शी का प्��वणता = 11 स्पर्शी का झुकाव प्रवणता m = tan = (dy/dx)_x1,y1 tan = 11 = tan^-1(11) बिंदु (x1,y1) पर स्पर्श रेखा समीकरण- स्रपशं रेखा की पृवणता=746 |
|
| 30. |
9. Two poles of height a metres and b metres are p metres apart. Prove thatthe height of the point of intersection of the lines joining the top of eachpole to the foot of the opposite pole is given by a+o metres.a t b |
|
Answer» धन्यवाद |
|
| 31. |
\begin{array}{l}{\text { Find the integral of the following: }} \\ {\text { (i) } \int\left(4 x^{3}+\frac{1}{\sqrt{x}}-3\right) d x} \\ {\text { (ii) } \int 4\left(e^{2 x}+x\right)\left(e^{2 x}+x^{2}\right)^{2} d x}\end{array} |
| Answer» | |
| 32. |
ve that the function x)-Sx-3 is continuous atx-o,atx-3 and atx s |
| Answer» | |
| 33. |
Fill in the blanks:(1) 32Ă34Ă33(2) 55(3) 92918(4) (-4)104(-4)633(5) (55 x 5558 |
| Answer» | |
| 34. |
0. The smallest number which when divided by4, 6, 10, 15 gives the same remainder 3 is(1) 75 (2) 123 (3) 63 (4) 39 |
|
Answer» 123 answer for the question is:123 The smallest number has been asked in the question. The answer is 63. Thanks mates for ur ans But 63 is the correct ans😀 |
|
| 35. |
In an examination, 65% of the total students passed. If the number of failure is 420 find the toalnumber of students.7. |
|
Answer» suppose total.number of students = xnow number of pass students = 0.65xso fail students = 0.35xnow fail students are 420so 0.35x=420so x=420*100/35=1200so number of students are 1200 |
|
| 36. |
ITryLlletoalmarksA number consists of two digits whose sum is 8. I 18 is added to the number itsreversed. Find the number |
| Answer» | |
| 37. |
A survey shows that in a city that 63% of the citizens like tea where as 76% like coffee. If x% likeboth tea and coffee, then(a) x= 63(b) x =39(c) 50<= x <= 63 (d) 39 <= x <= 63 |
|
Answer» thankss |
|
| 38. |
8. If (39 x 3-5* 27, then x-?434 |
| Answer» | |
| 39. |
If the weight of an object is 50 N. Then what will be its mass[g=10m/s^2] |
|
Answer» weight = mass * g50 = m*10m= 5kg |
|
| 40. |
2 If a sprinter runs a distance of 100 metres in 9.83 seconds, calculate his average speed in km/h. |
| Answer» | |
| 41. |
Curved surface area of a right circular cylinder is 4.4 m! If the radios of the base of thecylinder is 0.7 m, find its height. |
| Answer» | |
| 42. |
12) A ship going on a long journey had 35 daysof food for 600 passengers. If the foodlasted for only 30 days, how manypassengers were there on the ship? |
|
Answer» let the |
|
| 43. |
The toal surface area of a cylinder is 6512 cm2and the circumference of its base is 88 cm.Find:(i) its radius (ii) its volume1. |
| Answer» | |
| 44. |
Find value of 768*73+768*27 |
|
Answer» 76800 is the answer of the following =768*73+768*27=56064+20736=76800 =768*73+768*27=56064+20736=76800 |
|
| 45. |
Knowing Our NumbersEXERCISE 1 (A). Answer the following questions:8.Write the predece1 The counting numbers are also called hQ30(i) The largest digit used in the Hindu-Arabic(i1) 13586wna(i) 80number system is(il) In the number 6743,4 stands for 4 ones. True Multiple Choiceor Fätse.9. The number "fifeighty six" in nu(iv) Thepredecessor of a number is obtained by(a) 59896(V) The successor of 9999 is 1000. True or Enlse2. Write the following numbers in words: HU() 2050iv) 80203Write the following numbers in numerals u(i) Four thousand four hundred forty four.10. Which of theranged in asce(a) 10006, 1(b) 10600, 1(c) 10006,(n) 40023 (iii) 29001(v) 73506 |
|
Answer» 2.(i) Two thousand and fifty(ii) Forty thousand and twenty three(iii) Twenty nine thousand and one(iv) Eighty thousand two hundred and three(vi) Seventy three thousand five hundred and six |
|
| 46. |
12. On selling a calculator for1325, a man gains 6%. For how much should he sell it togain 12%? |
| Answer» | |
| 47. |
A shaopkepper sell two radios for Rs. 1540each. On one of then he gains 12% and theother he loses 12%. His total gain or loss is- |
|
Answer» he neither gained or neither lose. He sold what he buyed |
|
| 48. |
The measurements of some squares are given in the table below. However, they areincomplete. Find the missing information.Side of a square2.AreaPerimeter15 cm225 cm288 cm |
|
Answer» 1. Side = 15cm Area= 225 sq.cm Perimeter of square=4×side So, 4×15=60cm 2. Perimeter=4×side 88=4×side Side=88÷4 =22cm Area=side×side =22×22 =484 sq.cm |
|
| 49. |
11) In a cowshed there is enough food for 20cows for 15 days. However, some cows weresold and the food lasted for 25 days. Howmany cows were sold? |
|
Answer» number of cow they had food for 15 days= 20number of cows they had food for a day= 20x15number of cows if the food lasted for 25 days= 20x15/25= 12 cows were sold |
|
| 50. |
cos 60° = (cos? 30° — sin? 30°). |
| Answer» | |