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(c) Determine the value of k for which the given quadratic equations have equal roots: (4(2p+1) x2-(7p + 2) x + (7p3) =0. |
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Answer» (2p + 1)x²+ (7p+2)x + (7p-3) = 0If they have equal roots,b²-4ac=0Let,a=2p+1b=7p+2c=7p-3Now,(7p+2)²- 4(2p + 1) (7p-3)=049p²+4+ 28p – 4(14p²+p-3)=0After simplification,7p²-24p+16=0The roots are,4 and -4/7. |
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