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89.8

Given:Radius of the hemispherical bowl, r = 3.5 cm

Formula:Volume of a hemisphere = 2/3 π r3 = 2/3 * 22/7 * (3.5)3 = 89.83 cm3Volume of water in bowl = 89.83 cm .cube

In 5 days bug eats 135 fliesIn 1 day bug will eat 135/5 fliesIn 3 days bug will eat 135/5*3Thus after 3 days bug will eat 81 flies

In 5 days bug eats 135 fliesIn 1 day bug will eat 135/5 fliesIn 4 days bug will eat 135/5*5 fliesThus after 4 days bug will eat 108 flies

RAVI septa route to a party

36 .24is it clearthanks

36.24 is the correct answer of the given

The answer in words will be 36.24.

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thirty six point two four= 36.24

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36.24 hope this answer will help you. Thank you.

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36.24 is the mathematical number of the written

Thirty six point two four=36.24

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Since m and n are odd positive integers, so let m = 2q + 1 and n = 2p + 1 ,

•°• m² + n² = ( 2q + 1 )² + ( 2p + 1 )² .

= 4( q² + p² ) + 4( q + p ) + 2 .

= 4{( q² + p² + q + p )} + 2 .

= 4y + 2 , where y = q² + p² + q + p is an integer .

•°• q² + p² is even and leaves remainder 2, when divided by 4 that is not divisible by 4.

Let the geometric series be 1,a,b,c,d,e,27Let the common ratio be rThen r^6=27=3^3= root 3 ^6Thus r= root 3Therefore the geometric mean between 1 and 27 is root 3, 3, 3 root 3,9, 9 root 3

To find the GM between 2 & 32, first find the common ratio

nth = ar^n-1 / a = first term, n = # of terms, r = common ratio

32 = 2r^4 / n = 5, the nth = 32

r^4 = 32/2 = 16 r^4 = 2^4 thus r = 2

The GS is 2, 4, 8, 16, 32

The 3rd GM = 16

If g1,g2,g3 are the three geometric means between m and n then, m , g1, g2, g3 & n are in geometric progression.

g1/m = g2/g1 = g3/g2 = n/g3 --- (1)

∴ g1/m = n/g3

∴ g1g3 = mn ---(2)

g2/g1 = g3/g2

∴ g1g3 = g2^2 ---(3)

From (2) & (3),

g1g3 = g2^2 = mn

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Total volume =150 cm^3

23% of 150 is = ( 150 / 100) * 23. = 34.5

Remaining volume of ice is 150 - 34.5 = 115.5 cubic centimeter

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Volume of cube = ( side) ^3= 7 ^ 3 = 343.Volume of cuboid = 4 x 343 = 1372

Total volume =150 cm^3

23% of 150 is = ( 150 / 100) * 23. = 34.5

Remaining volume of ice is 150 - 34.5 = 115.5 cubic centimeter

10 millimeters are in a centimeter

100 centimeters are in a meter

1.1cm=10mm2.1m=100cm3.5m=500cm

10 mm are in a centimeter

10 millimetre are in 1 centimeter

1meter = 100 centimeter

1m = 💯 cm 5m = 5×100 cm = 500 cm

10 millimeters are in centimetre

1. 6+9 = 15

2 10+9 = 19

3. 10-6 = 4

4. 10-9 = 1

1/(a^2-bc ) + 1/(c^2-ab) + 1/(a^2-bc)Put -ac = ab + bc ; -ab = ac+ bc and -bc =ab + acyou get :=(1/(a^2+ab+ac))+(1/(c^2+ac+bc))+(1/(a^2+ab+ac))=(1/a(a+b+c))+(1/b(a+b+c))+(1/c(a+b+c))By taking LCM we get=(ab + bc + ca)/[(a+b+c)(abc)]put, ab+bc+cavalue = 0/[(a+b+c)(abc)] = 0

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11 ek abhajya sankhya hai kyoki unke factor 11 aur 2 hai

B) sahi uttar hai

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2(i)180-105=752(iii)180-154=26

3(iii)112+68=180Supplementary

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answer is 2x+3y-9=0

answer is 2x+3y-9=0

m = - 1, p = 2

p*p*p*p*m*m= 2*2*2*2*-1*-1= 16*1= 16

(B) is correct option

(1) 2(x+4) = 12 2x + 8 = 12 2x = 4 x = 4/2 = 2

(2) 3(n-5) = 21 3n - 15 = 21 3n = 36 n = 36/3 = 12

(3) - 4(2+x) = 8 - 8 - 4x = 8 -4x = 16 x = - 16/4 = - 4

(4) 4(2-x) = 8 8 - 4x = 8 4x = 8-8 4x = 0 x = 0

let no. be x2x+36+4=1002x+40=1002x=60x=30

total weight of the tablets=2,00,000 x 20mg = 40,00,000 mg -----11 gm = 1000mg

thus from 140,00,000/1000= 40,000gm

1 kg = 1000gmthus :40,000/1000= 40kg

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2x= 60X= 30Thanks

x=1000-4-36÷2x=1000-40÷2x=960÷2x=480

30 is the answer because 36 + 4=40 and remaining is 60/2=30

Century = 100Need 4 to reach century = 96

Let the no. be xTwo times over = 2x

2x + 36 + 4 = 1002x + 40 = 1002x = 100 - 402x = 60 x = 60/2 x = 30

correct answer is x= 30

2x+36+4= 1002x= 60X= 30

2x+36+4=1002x+40=1002x=100-402x=60x=30

30 is ur answer .......

2x + 36+4=1002x=60x=30

Use the formula cosC = (a²+b²-c²)/2ab.

=>cos(π/3) = (2²+(1+√3)²-c²)/2*2*(1+√3)=> 2+2√3 = 4+1+3+2√3 -c²=> c² = 6=> c = √6

area of circle = πr^2radius = 14 so area = 22*14*2= 22*28=616 units

Let a-d,a , a+d are in AP

ACCORDING to sum

a-d+a+a+d=153a=15a=5the terms will be 5-d,5,5+dwhen 1,4,19 are added to the terms they are in GP5-d+1,5+4,5+d+19 are in GPcommon ratio must be equalthe terms are 6-d,9,24+d9/(6-d)=(24+d)/9cross multiplying we get(6-d)(24+d)=9*9

(6*24+6d-24d-d^2)=81

(144-18d-d^2)=81

d^2+18d=144+81

=225

d^2+18d-225=0

by solving this we get d=8,-26

the numbers may be -3,5,3 or 31,5,-21

given that the sum is 15

so the numbers may not be -3,5,3

so the numbers are 31,5,-21

45°+angle BAC=130°(exterior angle)angle BAC=130-45=85°

Let number of five rupee and two rupee coins be x each

Then number of one rupee coins = 40 - 2x

As per given condition5*x + 2*x + 1*(40-2x) = 1205x + 2x + 40 - 2x = 1205x = 120 - 40x = 80/5 = 16

Therefore, Number of 5 rupees and 2 rupees coins are 16 of each type