1.

If three geometric means be inserted betweeu2 and 32, then the third geometric mean will be(A) 8 (B)4 (C) 16 (D) 12

Answer»

To find the GM between 2 & 32, first find the common ratio

nth = ar^n-1 / a = first term, n = # of terms, r = common ratio

32 = 2r^4 / n = 5, the nth = 32

r^4 = 32/2 = 16 r^4 = 2^4 thus r = 2

The GS is 2, 4, 8, 16, 32

The 3rd GM = 16



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