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Dimension of wooden boxLength = 70-6= 64, Breadth = 60-6= 54Height = 40-6 = 34

Volume = length*breadth*height = 64*54*34 = 117504 cm^3

Weight of box = 117504*10/100 = 11750.4 gm

galat answer ha yeh right answer 117504cm3 , 1.34 kg

416 dag into millimeters

342=2x3x3x19 and 396=2x2x3x3x11. We get 2x3x3 as common in both factors, so 18 is highest common factor,Therefore number of pieces to be filled in a pack is 18 for which number of packs will be least.

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CosA-sinA+1/cosA+sinA-1=(cosA-sinA+1)(cosA+sinA+1)/(cosA+sinA-1)(cosA+sinA+1)=(cos²A-cosAsinA+cosA+cosAsinA-sin²A+sinA+cosA-sinA+1)/{(cosA+sinA)²-(1)²}=(cos²A-sin²A+2cosA+1)/(cos²A+2cosAsinA+sin²A-1)={cos²A+2cosA+(1-sin²A)}/(1+2cosAsinA-1) [∵, sin²A+cos²A=1]=(cos²A+2cosA+cos²A)/2cosAsinA=(2cos²A+2cosA)/2cosAsinA=2cosA(cosA+1)/2cosAsinA=(cosA+1)/sinA=cosA/sinA+1/sinA=cotA+cosecA=cosecA+cotA (Proved)

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As PQ||RS,

Slope of RS = slope of PQ

k-1/5-3 = 6-4/3-2

k-1/2 = 2/1

k-1 = 4

k = 5

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Please specify the question

The common difference should be equal if the terms are in AP.

As given (x+1) is factor of polynomial 2x^3 - ax^2 - (2a - 3)x + 2

Then,For x = - 1 given polynomial will be equal to 0

So,2(-1)^3 - a(-1)^2 - (2a - 3)(-1) + 2 = 02*-1 - a*1 - (-2a + 3) + 2 = 0-2 - a + 2a - 3 + 2 = 0a - 3 = 0a = 3

Therefore,Value of a = 3

Given , sinA/sinB=p and cosA/cosB=q

So sinA= psinB and cosA=qcosB............(1)

Now dividing above two equation we get,

tan A= p/q* tanBor tan B= q/p*tanA ........(2)

Now multiplying both equation in (1) we get,

sinAcosA= pqsinBcosB

Now dividing by cos2^Acos^2B we get,

sinAcosA/cos^2Acos^2B=pqsinBcosB/cos^2Acos^2B

sec^2B*tanA = pq se^c2AtanB(1+tan2B)tanA=pq (1+tan2A) tanB

Now from equation (2) we get,

(1+(q/ptanA)^2)tanA=pq (1+tan^2A) q/p*tanA

1+q^2/p^2*tan^2A=q^2+q^2tan^2A1−q^2=(q^2−q^2/p^2)tan^2A

So,tan^2A= p^2(1−q^2)/q^2(p^2−1)

tan A=p/q sqrt[(1−q^2)/(p^2−1)]

tan 15 = tan(45-30) =

Tan(45-30)= tan45-tan30/1+tan45.tan30

tan15= (1-1/√3)/(1+1/√3) = (√3-1)/(√3+1)

or. Rationalising

= (√3-1)^2/2= (4-2√3)/2= 2-√3

For AP 5, 2, - 1.........nth termtn = a + (n - 1)d

a = 5, d = 2-5 = - 3

Let mth term of AP is - 49

Then,-49 = 5 + (m - 1)*-3-49 = 5 - 3m + 3-49 - 8 = - 3m3m = 57m = 57/3 = 19

Therefore, 19th term of given AP is - 49

let the number be x(x-1/2)×4=5(2x-1/2)×4=5(2x-1)×2=54x-2=54x=5+24x=7x=7/4

x minus one third and then multiplied by 4 the answer is 5

X= 7/4 is the correct answer of the given question

Let 50 paise coins be x 5 rupees coins will be (150-x) as there are q50 coins in the bag 50 paise = 100/50=1/2 rupees 1/2(x)+5(150-x)= 300 rupees x/2+750-5x = 300 rs-9x/2+750= 300750-300 = 9x/2 450= 9x/2 => 9x = 900 => x=900/9 = 100 (50-paise coins )5rupees coins => 150-x => 150-100=> 50 coins

In this additionBlue color = 1Grey color = 8Red color = 5

Then, 1 8 5 1 8 5+1 8 5------------ 5 5 5

good

x/y=42/24=21/12=7/4now when y=8 x=14now when y=16 x=28now when x=98 y=56

it would be - 750 ok so after solving we will get 30 and -25 so we will reject -25 and answer will be 30

120/2=60/2=30/2=15/3=5, 90/2=45/3=15/5=3; (ii)90/2=45/3=15/3=5, 60/2=30/2=15/3=5; 49/7=7; 37×1=37

blue = 1grey = 8red = 5

sin²28+cos²(90-62)+tan²38-tan²(90-52)+(1/4)sec²30=sin²28+cos²28+tan²38-tan²38+(1/4)sec²30=1+0+(1/4)*(4/3)=1+3=4

5/6 is right answer Clancy

5/6 is the correct answer

5\6 is the right answer

5/6 is the correct answer of the given question

5/6 is A correct answer

5/6 is a correct answer

2÷6=1/3;3÷6=1/2;1/3+1/2=3+2/6=5/6

5/6 is the correct answer

5/6 is the correct answer

5/6 is the correct answer of the given question

5/6 is right answer.

5/6 is right the right answer

Hepresides overtheSenateonlyonceremonial occasions or when a tie-breaking vote may be needed. When the vice president is absent, the presidentpro tempore presides overtheSenate.

Juniorsenatorsfillinas presiding officer when neither the vice president nor presidentpro temporeisontheSenateFloor.

1,8a+4b-6c2,8x²-5xy+8y²3,12y²-3y+134,2x³-7x²-10x+14

1,3a-4b+c+5a+8b-7c8a+4b-6c

2,8x²-5xy+8y²3,12y²-3y+134,2x³-7x²-10x+14 answer

1)8a+4b-6c is the right answer

1)120/2=60/2=30/2=15/3=5; 90/2=45/3=15/3=5; 2) 50/2=25/5=5; 60/2=30/2=15/3=5; 3) 37/1=37; 49/7=7

50= 2×5×5=2×5^260=2×2×3×5= 2^2×3×5HCF= 2×5=10LCM= 2^2×5^2×3 = 4×25×3=300

hcf= 10 LCM= 300 is the correct answer of the given question

Hch=10 lcm=300 is the correct answer

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1. 1314

2. 1151

3. 1603

(cos A- sin A + 1)/(cos A + sin A - 1). Divide both numerator and the denominator by sinA.the sum becomes

(cot A - 1 + cosec A)/(cot A + 1 -cosec A)

=(cosec A + cot A - 1)/(cotA - cosec A +1)

={cosecA+cotA-(cosec^2 A- cot^2 A)}/Dr where Dr=cotA-cosecA+1

={(cosecA+cotA)-(cosecA+cotA)(cosecA-cotA)}/ Dr.

=[(cosecA+cotA){1-(cosecA-cotA)}]/Dr

={(cosecA+cotA)(1-cosecA+cotA)}/Dr

=(cosecA+cotA)(cotA-cosecA+1)/Dr

=(cosecA+cotA).Dr/Dr

=cosecA+cotA.