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find the values of tan 15° and tan 30° by takingLONG ANSWER TYPE PROBLEMStan A-tan B16. Given that tan(A - B) =1+tan A tan Bsuitable values of A and B.[HL]nin 759 and cin 90° by taking |
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Answer» tan 15 = tan(45-30) = Tan(45-30)= tan45-tan30/1+tan45.tan30 tan15= (1-1/√3)/(1+1/√3) = (√3-1)/(√3+1) or. Rationalising = (√3-1)^2/2= (4-2√3)/2= 2-√3 |
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