Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Exercise 4.21. Triangle ABC is inscribed in a circle with centre O. If LAOB140° and<BOC = 100°, find <ABC.1402. In given figure, BC is a diamator of th

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2.

(1) 1402 Find the LCM and HCF of the following pairs of integers and verify that LCM HCFproduct of the two numbers.0 26 and 91(ii) 510 and 92(ii) 336 and 54

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3.

·Two numbers are in the ratio 2 : 5 . Their sum is 140. Find the number

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let the ratio be x so numbers are2x and 5xAccording to question,2x + 5x = 1407x = 140x = 140/7x = 20So numbers are 40 and 100

4.

2are girls. How many girls are3d.-There are 70 students in a class. Out of thesethere in the class?

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5.

What number must be subtracted frobecormes 7 15?m cach term of the ratio 1733 so that the ratio

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6.

10.The diameterofa semicircle is 140 mm. Find its circumference in cm.(n,2)

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since it is a semicircle answer will be 220

it is semicircle and u answered correctly but for a circle

7.

define administration?

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Administration is the range of activities connected with organizing and supervising the way that an organization or institution functions.

8.

(A)4 (B)28 (0)16 (D) 4036. When x200 + 1 is divided by x2 + 1, the remainde.is equal to -(A) x + 2 (B) 2x – 1 (C)2 D-1

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This Question's answer is D)-1

Thanks

9.

Kavita weigh?12. There are 42 students in a class andof the students are boys. How many girls are there inthe class?

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the number of boys in the class is equal to 5 by 7 of the total number of student

10.

EXERCISE 1.21. Express cach number as a proddet of its prime factors:140 A 160 (m) 3825) 5005

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11.

what is nayay panchayat? short answer

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Nyaya Panchayat is a system of dispute resolution at village level in India. Nyaya panchayats can be endowed with functions based on broad principles of natural justice and can tend to remain procedurally as simple as possible. They can be given civil and minor criminal jurisdiction.

12.

(e)ne Ul Ulese3. Find the length of the longest pole that canbe put in a room 10 m long, 9 m broad and7 m high.

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13.

non-ten as a non-terminoz 1.750atiNot0it isvernu13numbers on a number lineumbers. 2 is such

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Question you have submitted is incomplete. Please post a complete question.

this question is already complete

the question is not incomplete

14.

Checla whethe each of the point (20,3)(19,8) and (2,9) is equicistant fromthe point 13)

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All the points are equidistant from the point (7, 3) as:-

15.

Is 97S.3. The divisor of a certain number is 25 times the quotient and 15 times the remaindeFind the number when the remainder is 3753

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Dividend = (divisor × quotient) + remainder= (25×15) + 375 = 750 is your dividend.

16.

1. If '421314' stands for ‘CALM' and '82221' for 'GUT', what code will stand'VIOLENCE'?[2 Marks]a) 2390161351456b) 229151251435c) 2310161351546d) 2310151351646

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here all letters are arranged in form of no likeA = 1Z=21but in this situation letters are arranged like A=2 not 1B=3 not 2V=23 not 22

hence ans will be

(c) 2310161351546

(C).

a= 1 + 1= 2

c= 3+1 = 4

similarly d= 4+ 1 = 5

and so on

2310161361546 apka options wrong hai

kbvuvuvjbknlnlnlmonjvhvivuvubi

option c would be the answer

c is the answer of the following

17.

She iseick.ghe eeorks hard

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please post math question

18.

Q=nu

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please post complete question to solve it

19.

DolePoo2ろe nu

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thanks

20.

1. Express cach nu(i) 140

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140 = 2*2*5*5*7 is the answer

21.

actorise:(i) x3-2x2-x+2(iii) ㎡ +13x2+32x+20(ii) x3-3x-9x-5(iv) 2y+y-2y -1

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x3 + 13x2 + 32x + 20

please solve 2nd question

22.

rite the ne7,86,1438,11,868rite the nu

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1) seven lakh eighty six thousand one hundred forty three.2) eight lakh eleven thousand eight hundred sixty eight

23.

X2. 4 : 7X3. 5 12X4. 7 : 139.5 1500 के 60% का 350% = ?Ans3150X2. 2900X3. 28504. 2800१ 89 में एक वस्तु को बेचने पर 8% की हानि होती है। यदि इसे १78 में बेचा जाता है।AnsX1 40% लाभ

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3150 option 1 is the correct answer

1500*60*350/10000=15*6*35=3150

24.

P(x) = 5x3 + 4x2 + 7x + 2 어gel에 티è.

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P(x)=5x^3+4x^2+7x+2 bqhupadi no ghat=3

25.

onond isngCheck whethe 5X3 XIl+I and

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Composite (prime) number is number, which aredivisible onlyby 1 or by themselves.

5 * 3 * 11 + 11 = 11(5*3 + 1) this is not composite number, because ithas three differentdividers:1,11 and 16

5 * 7 + 7 * 3 + 3 = 35 + 21 + 3 = 5959 = 1 * 59 this is composit number it has only two dividers: 1, 59

26.

2) its and Rs.3x4 + 5x3-21x2-53x-30ελελ.

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27.

id the quotient and the remainde5x3 +x-3

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28.

tan 2x + Sintx=0the calm of þ"M.

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29.

32. The product of the ages of two sister is 104. The difference between their ages is 5. Find theirages.

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Let the age of the sisters be x and y

Given xy=104...(1)x-y=5...(2)From (1)y=104/x

Substitute in (2)

x-(104/x) =5x²-104=5xx²-5x-104=0sum=-5; product=-104numbers=-13,8x²+8x-13x-104=0x(x+8)-13(x+8)=0(x-13)(x+8)=0x=13,-8Thus age of 1st sister=13y=x-5=13-5=8

Thus age of 2nd sister=8

30.

The sum of the ages of keerthana and srilatha is 29 products of their ages is 210.Then find the ages of birth.

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After solving y = 14,15and x+y= 29if y= 14x= 15

31.

te the figure, APB and COD are semi-circles of diameter 7 cm each, while ARC and BSD aresemicircles of diameter 14 cm each. Find the perimeter of the shaded region! Useπ =-

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32.

of the rectangle? Also find which shape elciuFind the area of a square park whose perimeter is 48 m.CIcIo3C3 TE

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33.

2 A shoSdiior2100 Find the toss and loss perceles 15 kg of grain at the rate of f 18 per kg. He sells it at a profnt of5%. Find the selling price of the grain per kg.Ravi sells his motorcycle for 36 000 and incurs aloss of 10. Find the cost price and the

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the R's of 150kg grain at 18 = 150×18 =2700

we know that

S.P ={100+5/100}×2700

=102×27

=2835

Profit = S.P -C.P

=2835 - 2700

=135

34.

suld It forR 2100. Find the loss and loss percent.Aggkeeper procures 150 kg of grain at the rate of 18 per kg. He sells it at a proft o. Fad the selling price of the grain per kg.

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The R's of 150kg grain at 18 = 150×18 =2700

we know that

S.P ={100+5/100}×2700

=102×27=2835

Profit = S.P -C.P

=2835 - 2700=135

35.

Find the Perimeter of the rectangle whoSeMeaSures areLength6*1/2 cmBreadth5*3/4 Cm

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36.

i.Inantriangle, tne median and altitudes are given by the same nnIf the measures of two angles of a triangle are 52° and 78°, find the measure of the third angle.

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third angle = 180 - 52 - 78

= 50°

37.

म्नलिखित में से एकपदी, द्विपदी और त्रिपदी को छाँटिए :-2x-3 (ii) 3x2 (iii) 5x2 - &x + 1 (iv) (2xनलिखित बहुपदों में प्रत्येक की घात ज्ञात कीजिए :-3x+- +8(ii) y2-5y +7 (iii) 3x-x-2x2 + 5x(vi) 272-5y° +1 (vii) x'नलिखित प्रत्येक में दिये पद का गुणांक ज्ञात कीजिए :3x3 -5x2 - 5x + 6 में x का -(ii) 7x + 5x') 4x + 7 में : का(iv) 3x - 2x2नलिखित प्रत्येक का एक उदाहरण दीजिए :घात 19 का एकपदी (ii) घात 16 का द्विपदी (iii) घात 5 कनलिखित में से रैखिक, द्विघात और त्रिघात बहुपद को छाँटिए :3.2 3 () 2 +5 (iii).x-x (iv) 3x

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i) 2x-3; 2x=3; x=3/2; . ii) 3x^2; x^2=3; x=V3; iii) 5x^2-8x+1=0; a=5; b=-8; c=1; - b+-Vb^2-4ac/2a; -8V(-8)^2-4(5)(1)/2(5); -8+-V64-20/10; -8+-V44/10=-8+-2V11/10

38.

&. Construct an equilateral triangle each of whose altitudes measures5.4 cm. Measure each of its sides.

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Thank

very nice

39.

8. Construct an equilateral triangle each of whose altitudes measus5.4 cm. Measure each of its sides.

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tanks

40.

(i)2x2-3x + 5 = 0

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41.

32.2x2 + 3/5x + 5

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42.

(i)2x2-3x + 5-0

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43.

Three married couples are to be seated in a row having six seat in a cinema hall.if spouses are to be seated next to each other,in how many ways can they be seated? find also the number of ways of their seating if all the ladies sit together.

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44.

3. How many 3-ulgt ell ll1, 2, 3. 4, 6, 7, if no digit is repeated?Find the number of 4-digit numbers that can be formed using the digits 1. 2,3,45 if no digit is repeated. How many of these will be even?4.hou many ways can we choose a chairman

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45.

क+ 005 ए +cos _Sn =0हटना बे 13 13

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2cospi/13cos9pi/13+ cos3pi/13 + cos 5pi/13 = cos10pi/13+ cos3pi/13 + cos8pi/13+cos5pi/13 = 2cospi/2 cos7pi/26 + 2 cos pi/2 cos3pi/26=2(0) cos7pi/26 + 2(0) cos3pi/26=0

46.

अतः 80 % = 5 उत्तर= 5000 = 5|प्रश्नावली 251. निम्नलिखित को प्रतिशत में बदलिए-| 2. निम्नलिखित को साधारण भिन्नों में बदलिए-(क) 50% (ख) 220% (ग) 8%(ङ) 73% (च)) 40% (छ) 75%(घ) 6(ज) 2

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47.

upriarit 4.2(ii) 2x2 +x-6=0(iii)/./2x2+7x+s/2 = 0(v) 100 x2-20x+1 0(iv) 2x2-x+-=0

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48.

(6xs_ 4x4 + 8x3 + 2x2)รท 2x2

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49.

1^2x2^2x2^2= ?

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50.

(9) (6x5-4x4 + 8x' + 2x2)รท 2x2

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