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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
tShort Answer Type Questions (SLAB-I)1. Find the prime factorisation of the followingnumbers :(1) 96(ii) 408(ii) 2025. |
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Answer» (i) 96 = 2×2×2×2×2×3 = 2×5×3 Express 16380 prime factor |
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| 2. |
the triangle is right angled12. A △ABC is right angledat A. If ALL BC, prove thaZBAL-CACI.13. If each angle of a triaula le toe hsn |
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Answer» Like if you find it useful |
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| 3. |
l Surface area.r are in the ratio 4:7 and its volume is 251b cm.Find its10. (a) Arectangular paper of width 14 cm is rolled along its width and a cylinder of radiuspaper20cm is formed. Find the volume of the cylinder. I76ĆĄĆĄ cm(b) A recgular piece of paper 11 cm x 4 cm is folded without overlapping to make acylinder of height 4 cm. Find the volume of the cylinder. 3 g , 5 cm 3EL III |
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Answer» Given : A rectangular paper of width 14 cm is rolled along its width to form a cylinder . So Height of cylinder =h = 14 cm = width of the rectangular paper AndRadius of cylinder ( Given ) =r =20 cm Andwe know Volume of cylinder =πr2h, So Volume of our given cylinder =227×20×20×14=22×20×20×2=17600cm² Length of rectangle paper =11cmBreath of rectangular paper =4cm So circumference of circular part of cylinder =2 pi r So it is equal to length of paper (paper folded in shape of cylinder) 7=2 pi rr=7/2 piR=1.11cm Volume of cylinder = pi r² hH=4cmR=1.11cm Volume = 3.14x(1.11)²x4=15.48cm ?? |
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| 4. |
angit angle.A=900ABC is a right angled triange in whichand AB = AC,Find L B and7.C.8. Show that th |
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| 5. |
le cight triangle ABC, right angled at C. Misthe mid-point of hypotenuse ABto M and produced to a point D such thatDM CM. Point D is joined to point B(see Fig. 7.23). Show that:. C is joinedG) 4 DBC is a right angle |
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| 6. |
Triangle ABC is right angled at A. Also AB= AC and the bisector of angle C intersects the side ABat D. Prove that AC+AD=BC. |
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| 7. |
a rectangular piece of paper 11 cm (4)cm is folded without overlapping to make a cylinder of height 4cm. find the volume of the cylinder |
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Answer» thanks |
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| 8. |
Example 11: A rectangular piece of paper 11 cm x 4 cm is folded without overlappingto make a cylinder of height 4 cm. Find the volume of the cylinder, |
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Answer» Height of cylinder=11cmCircumference=4cm=2*3.14*rR=4/6.28=.63So,volume=3.14*.63*.63*11=13.70cm^3 |
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| 9. |
(1/9 %2B 1/8 %2B 1/7)^0/(-1/9)^(-2) |
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Answer» Any number raise to power 0 is 1hence1÷(-1/9)^-21÷(-9)^21/81 |
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| 10. |
20. A rectangular piece of paper 11 cm x 4cm is folded without overlapping tomake a cylinder of height 4 cm. Find thevolume of the cylinder. |
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Answer» Given length of the rectangle=11cmbreadth of the rectangle=4cmFormula used:circumference of cylinder=2 pi rvolume of cylinder=pi r^2 hSolution:Circumference of circular part of cylinder =2 pi r =length of paper7=2 pi rr=1.11 cmvolume of cylinder=pi r^2 h=3.14*1.11^2*4=15.48 cm cubetherefore volume of cylinder=15.48 cm cube |
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| 11. |
, 01 0522 011._ (9८ का * , |
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Answer» Lateral surface area of cube = 4 side² 4 × side² = 196 side² = 196/4 = 49 side = √49 = 7 m So, volume of cube = side³ = 7³ = 343 m³ |
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| 12. |
\left. \begin array l l \sqrt 10 & \text (B) \\ \sqrt 35 & \text (D) \sqrt 121 \end array \right. |
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Answer» D) √121 As 11² = 121 So, √121 = 11, which is a rational |
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| 13. |
\begin{array} { l } { \sin 30 ^ { \circ } \cos 30 ^ { \circ } } \\ { - \sin 60 ^ { \circ } \cos 60 ^ { \circ } } \\ { \text { (A) } 1 } & { \text { (B) } 0 } \end{array} \begin{array} { l } { \text { (C) } \frac { 3 } { 2 } \quad \text { (D) } \frac { 1 } { 2 } } \end{array} |
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| 14. |
What changes will be there if an equation is interchange that is left to right and rightto left?5. |
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Answer» The signs will get changedminus become plus and plus become minus |
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| 15. |
\left. \begin{array} { l } { \text { n the data } 30,34,35,36,37,38,39,40 \text { if } 35 \text { is remov } } \\ { 2 } & { ( c ) 1 } \end{array} \right. |
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Answer» Now median is (36 + 37)/2 = 36.5New median = 37Increase in median = 37 - 36.5 = 0.5 |
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| 16. |
\frac { 1 } { \operatorname { log } _ { 3 } x } = \frac { 1 } { 9 } \text { is } - a ) 3 ^ { 9 } , b ( 3 , c ) 9 ^ { 3 } , d ) \frac { 1 } { 3 } |
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| 17. |
17. The sum of two consecutive numbers is 23. Find the numbers. |
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Answer» Let the ist nmbr be=x2nd nmbr=x+1Sum of both nmbr=x+x+1=232x=23-1X=22/2So,x=11 iska answer 11 hoga ya 12 hoga Suppose,first number = x,then,second number = x + 1,according to the question,x + x + 1 = 23,Or,x = 11,x + 1 = 12,so,numbers are 11 and 12. answer for your question is 11 and 12. |
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| 18. |
2.The sum of two consecutive numbers is 153. Find the numbers. |
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| 19. |
The numerator of a fraction is 5 less than itsdenominator. If 3 is added to the numeratorand denominator both, the fraction becomes4Find the original fraction.5 |
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Answer» thanks |
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| 20. |
2 The sum of two consecutive numbers is -27. Find the numbers |
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| 21. |
The difference of cubes of two consecutivenumbers is 127. What are the numbers? |
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Answer» Lets look at the Cubes... For consecutive Cubes to have a difference of 127 the numbers(not Cube's) must be Small... but the cube of the greater number among the consecutive digits must also be greater than 127. now Keeping this in mind lets look at the cubes of some numbers which fall in this range... 5³=1256³=2167³=3438³=512 here when we check on 7³-6³ = 343-216 we get 127 as the answer... So to conclude: The required numbers are 7 and 6. |
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| 22. |
The difference between the squares of twoconsecutive numbers is 31. Find the numbers. |
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| 23. |
3 GTA 6.30130°110°ti |
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| 24. |
A 1-3v) Determine whether (x- 1) is a factor of x^4-x^3 + x^2 -1 |
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Answer» x^4-x^3+x^2-1if x-1 is factor then x=1 will make value 0(1)^4-(1)^3+(1)^2-1=1-1+1-1=0so yes |
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| 25. |
a) Reduce the following matrix in normal form and hence determine its rankA=\left[ \begin{array}{cccc}{1} & {2} & {-1} & {3} \\ {3} & {4} & {0} & {-1} \\ {-1} & {0} & {-2} & {7}\end{array}\right] |
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| 26. |
3. Writy commutative property of addition for the following point of retinalnom; and in and in and |
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Answer» According to commutative property of addition If a and b are two rational numbers Then,a + b = b + a (i) - 4/3 and 3/7-4/3 + 3/7 = (-28 + 9)/7 = - 19/73/7 + - 4/3= (9 - 28)/7 = - 19/7 (ii)-2/-5 and 1/32/5 + 1/3 = (6 + 5)/15 = 11/151/3 + 2/5 = (5 + 6)/15 = 11/15 (iii)9/11 and 2/139/11 + 2/13 = (117+22)/143= 139/1432/13 + 9/11 = (22 + 117)/143= 139/143 |
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| 27. |
Find the values of x if 2 35 30 |
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Answer» Middle column of the matrix is missing.. please click proper image of the question |
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| 28. |
23. In a quadrilateral ABCD, it is being given that MDis the midpoint of AC.Prove that ar( ABAD)-ar(□ DMBC). |
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| 29. |
\left. \begin array l l 35 \\ 30 & \text (d) 40 \end array \right. |
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| 30. |
Q) Diagonal PR and QR of quadrilateral PQRS intersect at A.Show that ar(psa) + ar(qar) =ar(paq) + ar(sar) |
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| 31. |
Diagonals AC and BD of a quadrilateral ABCD intersect each other at P. Show that ar( APB) xar( CPD)-ar( APD) x ar( BPC) |
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| 32. |
*. Add (-13) + 34 using the commutative property. |
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Answer» (-13) + 34 =-21 -21 is the correct answer to your question I hope that my answer helped u in doing ur work -21 is the correct answer -21 will be the answer uxuxhchxyckcydkvuxjcudjvi -13 + 34 = 21 21 is the correct answer please like my answer -13+24=2121 is the correct answer |
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| 33. |
131193. Verify commutative property of addition for the following pairs ofnumbers:0 -- and;(i) = andind i and |
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Answer» _4/3+3/7Take 3,7 ka LCM=21Then, -28+9=19 -4/3+3/7 Take 3,7 KA LCM=21THEN, _28+9=-19 |
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| 34. |
21. The denominator of a fraction is greater than its numerator by 11. If 8 isadded to both its numerator and denominator, it becomes 4 Find the3fraction |
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| 35. |
\left. \begin{array} { l } { x + 3 y = 6 } \\ { 2 x - 3 y = 12 } \end{array} \right. |
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Answer» x + 3y = 6 .......(1)2x -3y = 12 .......(2)adding (1) and (2)3x = 18x = 6, y = (6-x )/3 = 0y = 0 |
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| 36. |
\left. \begin{array} { l } { x - 3 y - 7 = 0 } \\ { 3 x - 3 y - 15 = 0 } \end{array} \right. |
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| 37. |
\begin{array} { l } { x - 3 y - 3 = 0 } \\ { 3 x - 9 y - 2 = 0 } \end{array} |
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| 38. |
x \text { if }[x-1] \left[ \begin{array}{rr}{1} & {0} \\ {-2} & {-3}\end{array}\right] \left[ \begin{array}{l}{x} \\ {3}\end{array}\right]=0 |
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| 39. |
Divideby the difference of ze and3530 |
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| 40. |
RP 402. ConstructAPOR ifPQ=5 cm, mZPQR-105° and m<OHint: Recall angle-sum property of a triangle). |
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| 41. |
If a number is increased by 12,it becomes 21.Find the number. |
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Answer» it is 8 |
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| 42. |
.8. Using the angle sum property of a triangle, find the sum of the angles of any quadrilateral.,HOTsar |
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| 43. |
ХУIf2 3 6 then prove that1-0 or ze xty |
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| 44. |
1.3.2 Commutative Property() AdditionConsider the sum of two rational numbers 3/7 and -1/4 |
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Answer» 3/7 + (-1/4) = 3/7 - 1/4 = 12-7/28 = 5/28 thanks |
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| 45. |
if a number is increased by 12,it becomes 21.find the number |
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| 46. |
Gta3+ 12 Find the value of 21 |
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| 47. |
\left. \begin{array} { l } { x ^ { 3 } - 2 x ^ { 2 } - x + 2 } \\ { x ^ { 3 } + 13 x ^ { 2 } + 32 x + 20 } \end{array} \right. |
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Answer» You are mad or so double mad yu can't know this questions answer |
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| 48. |
\left. \begin{array} { l } { x ^ { 3 } + x ^ { 2 } y + x y ^ { 2 } + y ^ { 3 } = 81 } \end{array} \right. |
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Answer» dy/dx x^3 + x^2y + xy^2 +y^3 =81 3x^2 + 2xy + y^2 = 0 |
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| 49. |
= - 2 , \text { determine the value of } \left| \begin{array} { c c c } { 0 } & { 2 \lambda } & { 1 } \\ { \lambda ^ { 2 } } & { 0 } & { 3 \lambda ^ { 2 } + 1 } \\ { - 1 } & { 6 \lambda - 1 } & { 0 } \end{array} \right| |
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Answer» thank you but answer is not zero |
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| 50. |
10. Determine:2(1)of 15 pens3 |
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