1.

\left. \begin{array} { l } { x + 3 y = 6 } \\ { 2 x - 3 y = 12 } \end{array} \right.

Answer»

x + 3y = 6 .......(1)2x -3y = 12 .......(2)adding (1) and (2)3x = 18x = 6, y = (6-x )/3 = 0y = 0



Discussion

No Comment Found