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In the cylinderof radius R, the sphere just fits. So its radius is R.

Volume of of cylinder up to the height 2R in the cylinder =πR² * 2R = 2π R³Volume of sphere = 4πR³/3

Volume of water in the gap between cylinder and sphere = 2πR³-4πR³/3 = 2πR³ /3

2) Depth of water in the can before sphere is put inside it = volume of water/area of cross section of can = (2π R³ / 3 )/π R² = 2 R/3 = 2 * 3.5 /3 = 7/3 cm

1) Surface area surface area of can in contact with water = flat surface + curved surface =πR² + 2π R * 2 R = 5π R² = 5 * 22/7 * 3.5² cm² = 110 /7 * (7/2)² cm² = 385 / 2 cm²

D) is right correct answer

thanks sir

(i) 2724Here, 2 + 7 + * + 4 = 13 + * should be a multiple of 3.To be divisible by 3, the least value of * should be 2, i.e., 13 + 2 = 15, which is a multiple of 3.∴ * = 2

(ii) 53046Here,5 + 3 + * + 4 + 6 = 18 + * should be a multiple of 3.As 18 is divisible by 3, the least value of * should be 0, i.e., 18 + 0 = 18.∴ * = 0

(iii) 81711Here, 8+ * + 7 + 1 + 1 = 17 + * should be a multiple of 3.To be divisible by 3, the least value of * should be 1, i.e., 17 + 1 = 18 , which is a multiple of 3.∴ * = 1

(iv) 62235Here, 6 + 2 + * + 3 + 5 = 16 + * should be a multiple of 3.To be divisible by 3, the least value of * should be 2, i.e., 16 + 2 = 18, which is a multiple of 3.∴ * = 2(v) 234117Here, 2+ 3 +4 + * + 1 + 7 = 17 + * should be a multiple of 3.To be divisible by 3, the least value of * should be 1, i.e., 17 + 1 = 18, which is a multiple of 3.∴ * =1

(vi) 621054Here, 6 + * +1 + 0 + 5 + 4 = 16 + * should be a multiple of 3.To be divisible by 3, the least value of * should be 2, i.e., 16 + 2 = 18, which is a multiple of 3.∴ * =2

this is wrong

nice answer..................

Volume of cylinder=πr^2hr=hV=πr^2×rV=πr^3

15th termt15 =-54nth termtn=20-5n

perimeter of trapezium=sum of parallel sides + sum of non parallel sides52=10+10+sum of parallel sidessum of parallel sides=32cmarea=sum of parallel sides×altitude ×1/2a=32×8/2=128

initial perimeter is 10+8=18now after increasing x perimeter doubledso 10+x+8+x=36so 2x=18so x=9so area of new rectangle 19*17=323 cm^2

1 kg = 1000 gSo, 1 g = 1/1000 g = 0.001 gSo, 450 g = 450/1000 g = 0.45 g So,12 kg 450 g = 12.45 kg

x-2=7x=7+2x=9

Thats right

the answer of your question is x=7-2=5 x=5

2x=12-182x=-6x=-6÷2x=-3

2x + 18 = 12

2x = -6

x = (-6)/2

x = -3

Admitted on 15th May 2011 and discharged on 15th June 2011 so number of days = 17 days of May + 15 days of June = 32 days

1 inch=

2,54 centimetres

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6400 = 80²So,√6400 = 80

please post a complete question for proper answer

Area = 2a*3a

= 6a² units

A tangent to a circle intersecting it in one point

put x=0 and y = 2 in 2x +ky = 102×0+k×2 = 10k = 5

Thnk u

intersect it in one point

All the angle made at O is equal.

Sum of all the angles=360°total no of angles made=4Hence each angle=360/4=90°

L=30mW=25mP=2(l+w)==2(30+25)2(55)=110m

A=w×l=25×30=750m^2

perimeter=2(l+b)=2×(30+25)=2×55=110

Given Length = 30m breadth =25mperimeter of rectangle = 2 (length + breadth)= 2 (30+25)=2× 55=110 marea of the rectangle = length × breadth = 30 × 25=750 m^2

i) A tangent to a circle intersect it in a one point.

The sides of rectangle are 4 cm and 3 cm, hence the diagonal is (3^2 + 4^2)^1/2 = (9 + 16)^1/2 = 25^1/2 = 5This will become the diameter of the circle hence area of circle = 22/7 x 2.5 x 2.5 = 3.14 x 6.25 = 19.625Area of rectangle = 4 x 3 = 12 sq cmHence area enclosed between circle and rectangle = 19.625 - 12 = 7.625 sq cm

sin inverse y=cos inverse x +C

it will be 40° only because it will be same as it corresponding angle

For this add both the amountshence20l 450ml+28l 800ml=48l +(450+800)ml=48l+1250mlas 1250ml=1litre 250mlhence49litre 250ml

Lace needed for 2 dresses = 18mLace needed for 1 dress = 18/2= 9mLace needed for 16 dresses = 9*16 = 144m

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