--ind the perimeter and area of a rectangle whose sides are 30 mand 20

1.	--ind the perimeter and area of a rectangle whose sides are 30 mand 20Arrange the following
Answer» L=30mW=25mP=2(l+w)==2(30+25)2(55)=110m A=w×l=25×30=750m^2 perimeter=2(l+b)=2×(30+25)=2×55=110 Given Length = 30m breadth =25mperimeter of rectangle = 2 (length + breadth)= 2 (30+25)=2× 55=110 marea of the rectangle = length × breadth = 30 × 25=750 m^2

--ind the perimeter and area of a rectangle whose sides are 30 mand 20Arrange the following

Answer»

L=30mW=25mP=2(l+w)==2(30+25)2(55)=110m

A=w×l=25×30=750m^2

perimeter=2(l+b)=2×(30+25)=2×55=110

Given Length = 30m breadth =25mperimeter of rectangle = 2 (length + breadth)= 2 (30+25)=2× 55=110 marea of the rectangle = length × breadth = 30 × 25=750 m^2

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--ind the perimeter and area of a rectangle whose sides are 30 mand 20Arrange the following

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