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Statement4/3 belongs to set of rational number

4x+5y+13=02x-2y-2=0... multiply with 2

4x+5y+13=04x-4y-4=0

Subtract

9y+17=0y=-17/9

2x-2y=2x-y=1x=1/y=1-17/9=9-17/9=-8/9

4x+5y= -13 (equation 1)

2x-2y= 2 ( equation 2)

Multiply equation 2 by 2

4x-4y= 44x+5y= -13Solve both the equationy= -9substitute value of y in equation 22x-2(-9) = 22x +18 = 22x = -16x= -8

can't understand the question

1.{2,4,6,8,10...........}2.{2}3.{-1,-2,-3,-4...................}4.{sa,re,ga,ma,pa,dha,ni,sa}

i) 2, 4, 6, 8, 10, 12,,,,, ii)2 iii)-1, -2, -3, -4, -5

1) {2,4,6,8,10,12,...........}2) {2}3) {-1, -2, -3,-4, -5,..........}4) {sa, re, ga, ma, pa, dha, ni, sa}

or gate and gate is the right answer

switch are parrallel......

or gate and gate is the correct answer

OR gate and AND gate is the right answer

right answer is 156kg

156 Kg is the correct answer

1. 234/152. =15.63. 15.6 * 10=156 is the final answer

firstly 234/15=15.615.6*10= and the and is 156

Right answer is 156kg

-3x²=(2-x)(3x-1/2)-3x²=6x-1-3x²+x/26x+x/2-1=013x/2=1x=2/13

0 is the correct answer of this question

the answer is not defined as there is 0 in denominator

the answer is not defined as denominator has zero in it

0 is the correct answer

0 is the correct answer

zero is the right answer

0 is the beat answer

(10-10)÷(100-100)=(0)÷(0-0) = cannot define bcz infinity number

(10-10)÷(100-100)=(0)÷(0)=can't define bcz denominators zero

0 is the best answer

10-10/100-100=0/0=0 it can,t be said

0 is correct answer.

1/20 or not defined is the correct answer

ax²+bx+c is standard quadratic equationproduct of zeroes is equal to c/a

it's wrong answer will be 1,5,-1,-5

C.P= Rs.540Sales tax=8%Money paid by him (inclusive of tax)=540+540×8/100 =540+43.2 =583.2

540 × 8/100

= 43.2

The total amount = 540 + 43.2

= 583.2 rps

it will be100/110*1650= 1500 rupeesas we have to deduct the sales taxlist price + 10 percentage sales tax = 1650

The signs have not been placed at the correct place. The correct equations would be 4x + ky+ 2z = 0;kx + 4y + z = 0;2x + 2y + z = 0.Now, for the system of equations to possess a non -zero solution, the value of the determinant should be zero.Hence, D = 0 gives, [4(4-2) – k(k-2) + 2(2k-8)]Hence, we have (16 – 8 – k2 + 2k + 4k – 16) = 0This gives -k2 + 6k -8 = 0Hence, k = 4, 2.The given system has a non-zero solution for two values of k.

x^2+2x-5=0

The form for a perfect square isa^2+2ab+b^2=(a+b)^2.

x^2+2x−5=0.

Add5to both sides of the equation.

x^2+2x=5

Divide the coefficient of thexvalue by2, then square the result.

2/2=1;1^2=1

Add the result to both sides.

x^2+2x+1=5+1=

x^2+2x+1=6

The left side is now a perfect square trinomial.

x^2+2x+1=(x+1)^2

(x+1)^2=6

Take the square root on both sides.

x+1=±√6

Subtract1from both sides.

x=√6−1

x=−√6−1

Given :

Selling price of wrist watch = ₹ 990

Gaining 1/8 of its cost price.

To find :- (i) Cost Price of wrist watch. (ii) Profit percent of wrist watch.

Let the cost price of wrist watch be x

A/q

=> x + 1/8 of x = 990=> x + 0.125 × x = 990=> 1.125x = 990=> x = 990/1.125 = 880

Therefore, Cost price of watch = ₹ 880And Profit = 1/8 of x = 1/8 × 880 = ₹ 110

Now,

Find the profit percent of wrist watch :-

Profit % = (profit × 100)/C.P %= (110 × 100)/880 %= 11000/880 %= 12.5 %

Hence,(i) The cost price of wrist watch is ₹ 880.(ii) Profit percent of wrist watch is 12.5 %.

-3/2 is the correct answer of the given question

-6/a=4; a=-6/4; a=3/2

ax^2-6x-6=ax^2-3x+2x-6=x(ax-3)+2(x-3)=(x-3)(ax+3); x=3 ; -6/a=4; a=-6/4=-3/2

Let the cost of a notebook = Rs xThe cost of a pen = yAccording to the condition, we have[Cost of a notebook] = 2 × [Cost of a pen]i.e.[x] = 2 × [Y]orx = 2yorx – 2y = 0Thus, the required linear equation is × – 2y = 0.

thank frnd

The capacity of required container will be obtained by finding the HCF of the capacity of tankers -

850 = 2×5×5×17

680 = 2×2×2×5×17

Common factors of 850 and 680 = {2,5,17}

HCF = 2×5×17= 170

Answer:- The container which can measure petrol of either tank exactly must be of 170 litres.

a = -1 , b = 3, y = 1 and z = 0

2ab - xyz

2 × (-1) × (3) - 6 × 1 × 0

-6

d) option is correct.

Please hit like if find useful.

The capacity of required container will be obtained by finding the HCF of the capacity of tankers -

850 = 2×5×5×17

680 = 2×2×2×5×17

Common factors of 850 and 680 = {2,5,17}

HCF = 2×5×17= 170

Answer) The container which can measure petrol of either tank exactly must be of 170 litres.



Secondary School

Math

30 points

Two tankers contain 850 litres and 680 litres of petrol respectively. Find the max. capacity of a container, which can measure the petrol of either tanker in exact number of litres

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byAyushKhurana26.05.2017

Answers

zerodown1024

The capacity of required container will be obtained by finding the HCF of the capacity of tankers -

850 = 2×5×5×17

680 = 2×2×2×5×17

Common factors of 850 and 680 = {2,5,17}

HCF = 2×5×17= 170

Answer) The container which can measure petrol of either tank exactly must be of 170 litres

Solution :-here, given

Capacity of the 1st tank = 850 litres.

Capacity of the 2nd tank = 680 litres.

Therefore, the max. capacity of a container, which can measure the petrol of either tanker in exact number of litres = HCF OF 850 and 680.

HCF of 850 and 680 is

850 = 2x5x5x17

680 = 2x2x2x5x17

Therefore,HCF = 2x5x17 = 170

So, The maximum capacity of the container is 170 litres.

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1

2

3

³√0.012167× ³√1/1000= 23/100 × 1/10= 23/1000= 0.023

how AP = PB = BC????

In triangle ABR, P is the mid point of AB and DP is parallel to BR (by question).Thus D is the mid point of AR.

So we have AR = 2 AD = 2 BC ( since in parallelogram ABCD opp. sides AD = BC) (1)

Again in triangle ABR, since BR is parallel to DP (or, since Trangles ABR and ADP are similar)

we have BR /DP = AB/DP = 2 ( since P is the mid pt. of AB)

Therefore BR = 2 DP = 2 BQ ( since PBQR is a parallelogram. Fot DQ is parralel to AB and BQ is drawn parallel to PD)

Option (3) is correct.