0 = s - x z %2B _ z x ( z ) – InterviewSolution

1.	0 = s - x z %2B _ z x ( z )
Answer» x^2+2x-5=0 The form for a perfect square isa^2+2ab+b^2=(a+b)^2. x^2+2x−5=0. Add5to both sides of the equation. x^2+2x=5 Divide the coefficient of thexvalue by2, then square the result. 2/2=1;1^2=1 Add the result to both sides. x^2+2x+1=5+1= x^2+2x+1=6 The left side is now a perfect square trinomial. x^2+2x+1=(x+1)^2 (x+1)^2=6 Take the square root on both sides. x+1=±√6 Subtract1from both sides. x=√6−1 x=−√6−1

0 = s - x z %2B _ z x ( z )

Answer»

x^2+2x-5=0

The form for a perfect square isa^2+2ab+b^2=(a+b)^2.

x^2+2x−5=0.

Add5to both sides of the equation.

x^2+2x=5

Divide the coefficient of thexvalue by2, then square the result.

2/2=1;1^2=1

Add the result to both sides.

x^2+2x+1=5+1=

x^2+2x+1=6

The left side is now a perfect square trinomial.

x^2+2x+1=(x+1)^2

(x+1)^2=6

Take the square root on both sides.

x+1=±√6

Subtract1from both sides.

x=√6−1

x=−√6−1