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Logic gatesperformbasic logicalfunctions and are the fundamental building blocks of digital integratedcircuits.

Mostlogic gatestake an input of two binary values, and output a single value of a 1 or 0.

These gates are the AND, OR, NOT,NAND, NOR, EXOR and EXNOR gates

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Thank you so much but the question is "At what distances from the two gates should the pole be erected? "One is 5 m but what will be the other distance??

Subhash can copy 50 pages in 10 hours.That means in 40 hours he can copy 50×4=200 pages.

Subhash and prakash together can copy 300pages in 40 hours.

That means prakash alone can copy 300-200=100 pages in 40 hours.

So to copy 30 pages prakash will take 40/100 ×30 = 12 hours.

As AB || FE, FA becomes the tranversal line cutting parallel lines. So angle A + angle F = 180°.

sum of other four angles = 720° - 180°= 540°.So 6 x + 4 x + 2 x + 3 x = 15 x = 540°.x = 36°.

Angles B C D E are: 216°, 144°, 72°, 108°

As AB || FE, FA becomes the tranversal line cutting parallel lines. So angle A + angle F = 180°.

sum of other four angles = 720° - 180°= 540°.So 6 x + 4 x + 2 x + 3 x = 15 x = 540°.x = 36°.

Angles B C D E are: 216°, 144°, 72°, 108°

29 + 21 = 50

50 ......................

x^3 + 3x^2 + 6x + 18= x^2(x + 3) + 6(x + 3)= (x^2 + 6)(x + 3

it's matrices

Using pythagoras theorem

(AB)²=(BC)²+(AC)²(25)²=(BC)²+(7)²625=(BC)²+49(BC) ²=625-49(BC)²=576BC=24

C is a right angleso AB^2=AC^2+BC^2BC^2=625-49=576so BC=24 cm

Marked Price = selling price/(1- (discount)/100)MP = 5225/(. 95)=5500

Answer:a)120°

Sum of all angles of regular polygon is 360Measure of each exterior angle =360/12 =30

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Radius, r = 14 cmCircumference of semi circle = πr= (22/7) x 14 = 44 cmThis becomes circumference of base of cone2πR = 44R = 44 x (7/44)R = 7 cmThe radius of semi circular sheet = slant height of conical cupThat is l = 7 cmWe know that r2+ h2= l2142+ h2= 72196 – 49 = h2h2= 147Therefore, h = 7√3 cmThat is depth of the conical cup is 7Ö3 cmCapacity of cup = (1/3)πr2h = (1/3) x (22/7) x 72x 7√3 = 622.37 cu cm

diameter =d = 28 cmRadius= r = 14 cmCircumference of semi circle = πr= (22/7) x 14 = 44 cm

so the circumference of base of cone2πR = 44R = 44 x (7/44)R = 7 cm

The radius of semi circular sheet = slant height of conical cupwhich isl = 7 cmAs,r2+ h2= l2

142+ h2= 72

196 – 49 = h2

h2= 147

hence; h = 7√3 cm

depth of the conical cup= 7√3 cm

Capacity of cup = (1/3)πr2h

= (1/3) x (22/7) x 72x 7√3

= 622.37 cu cm approx

Slant height of the conical cup, 'l' = radius of the semi-circular sheet, R = 14 cmLet radius and height of the conical cup be 'r' and 'h' respectively.Circumference of the base of the cone = Length of arc of the semi-circleOr, 2πr = (1/2)2πROr, 2πr = (1/2)(2π)(14)Or, r = 7 cmNow, we know that l² = h² + r²(14)² = (h)² + (7)²h² = 196 - 49h =√147Height or depth of the conical cup = 12.124 cmNow, capacity of the conical cup = 1/3πr²h= 1/3*22/7*7*7*12.124= 13069.672/21Capacity of the conical cup = 622.365 cu cm

Firstprovethat ABM ≡ CDMusingthe SAS congruencetest. (alternateanglesare equal): Hence ABCD is aparallelogram, because one pair ofoppositesides are equal and parallel. ... Hence ABCD isrectangle, because it is aparallelogram withone rightangle.

x=30°(alternate angle)

i) x^2-1; x=1, -1; (1)^2-1=1-1=0, (-1)^2-1=-1=1; (ii)2x-1; x=-1/2; 2(1/2)-1=1-1=0, (iii)4x+5; x=-5/4; 4(-5/4)+5=-5=5=0; (iv)3x^2; x=0; 3(0)^2=3(0)=0; (v)=( x-3)( x+5); x=3, -5; (3-3)(3+5)=0(8)=0; x=-5; (x-3)(x+5)=(-5-3)(-5+5)=('8)(0)=0;(vi)ax+b; x=-b/a; a(-b/a)+b=a(1/a)=0;

(vii); 3x^2-1; x=-1/V3; 1/V3; 3(-1/V3)^2-1=3(1/3)-1=0; 3(1/V3)^2-1=3(1/3)-1=0; p(x)=3x+2; x=-3/2; =3(-3/2)+2=0

3p(- p - a - r ) - (-3p²+3pq+3px)-3p² -3pa -3pr + 3p² -3pq -3px-3pa-3pr-3pq-3px-3p(a+r+q+x)

thank you

5k+4k+6k=180;15k=180k=12Then the angles are x=5(k)=5(12°)=60° and y=4(k)=4(12°)=48° and z=6(k)=6(12)=72°

I

2p+1/p=42p+1=4p2p=1∴p=1/2

p3+1/8p3=(1/2)^3+1/8(1/2)^3=1/8+1/ 8(1/8) =1/8+1=9/8

Bhai Apne to Google Ka ans paste kardiya

-67 should be subtracted to make the polynomial have a factor (x+2)

Let cost price be CP

If article sold at loss of 12 1/2 %SP1 = CP(1 - 25/200)SP1 = 7CP/8

If article sold for Rs 92.50 more

7CP/8 + 92.50 = CP(1 + 6/100)53CP/50 - 7CP/8 = 92.50(212 - 175)CP/200 = 92.5037CP = 18500CP = 185000/37 = 500

(B) is correct option

and

cost of 6 eggs=30cost of 1 egg=30/6=5cost of 10 eggs=5×10=50

Angle COD= 180°- 1/2angle C-1/2 angle D=180°-1/2(angle C+D)----------(1)

Angle (A+B+C+D)=360°

AngleC+D= 360°- AngleA- angle B--------------(2)

Substituting (2) in (1)

Angle COD= 180°-1/2(360°- angle A- Angle B)

Angle COD= 180°-180°+1/2 Angle A + 1/2 Angle B= 1/2(Angle A+ Angle B)

thanks

1

Solution :

Let set A is seven basic sounds

of a sargam .

List form of set A :

i ) In Carnatic music :

A = { Sa , Ri , Ga,Ma,Pa,Dha,Ni }

ii ) In Hindustani classical :

A = { Sa, Re, Ga, Ma, Pa, Dha, Ni }

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thankhs

but ext angle ABD +angle B=180

1st

2nd

option A ,

Representing the symbol statement given we have:- 4/3 is an element of set Q.

Statement :4/3 belongs to set of rational number

Statement :

4/3 belongs to set of rational numbers