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2 p + \frac { 1 } { p } = y \quad p ^ { 3 } + \frac { 1 } { \gamma p ^ { 3 } } = ? |
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Answer» 2p+1/p=42p+1=4p2p=1∴p=1/2 p3+1/8p3=(1/2)^3+1/8(1/2)^3=1/8+1/ 8(1/8) =1/8+1=9/8 Bhai Apne to Google Ka ans paste kardiya |
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