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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
24. In the given figure, ABC is a triangle in which ZA : ZB: ZC 3:2:1and AC LCD. Find the measure of LECD |
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| 2. |
Fig. 1036, ZA = ZB + ZC. Find the measure of ZA.coFig. 10.36Is Properties |
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Answer» a= b-c is the answer in a traingle total angle is 180 ieangle A +angle B + angle C =180A+B+C =+80given A=B+CsubstituteA+A=1802A=180A=90 angle A is 90 degrees is answer a=b-c is the correct answer angle A + angle B + angle C = 180given A=B+Cso B+C=AA+A=180 2A=180 A=180/2 A=90°measure of angle A is 90°. angle A is 90 degrees is the correct answer A 90 degree is the correct answer to your question I hope that my answer helped u in doing ur work A=90° is the correct answer |
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| 3. |
Multiply:a. 2/6 X 54b. 27/40 X 20/21 |
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Answer» 18 |
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| 4. |
a+b=54 a-b=34give value a and b |
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Answer» adding both the equations we will get2a=88hence a=44put in equation 144+b=54b=54-44=10 |
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(38 + 20) - (38 न 20) न 2(1) 54870 + 160(2) 10880 + 160(39) 108a’b - 160(4) 54ab> — 16D’ |
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Answer» Ans=108a^2b+16b^3. |
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| 6. |
Сл32. निम्नलिखित बारंबारता बंटन का माध्य ज्ञात कीजिए :वर्ग अन्तराल 100-120 120-140 140-160 160-180 180-200वारंवारता 12 148| 10Find the mean of the following frequencydistribution:classIntervat 100-120 120-140 140-160 160-180|180-200||Frequencu12 148 6 10 । |
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| 7. |
4. "If α, β, γ are zeroes of polynomial 2r3-4x2 + 6c-9-n, lhen find the value of α, |
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Answer» Like if you find it useful |
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| 8. |
2. A shopkeeper bought a bicycle for3000 and sold the same for 3400.How much was his profit? |
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Answer» ₹3400-₹3000=₹400so, his profit was ₹400 CP=3000SP=3400Profit=SP-CP =3400-3000 =400 400 rupya profitcorrect answer for this question 3400-3000400So,his profit =400 rupees 3000 - rupees 3400 equal— to rupees 400 CP=₹3000SP=₹3400Profit=?According To The Formula...Profit=SP-CP =3400-3000 =₹400 is the best answer Rs 3400- Rs 3000 =so profit was Rs 400 Bought price =₹3000Sold price=₹3400Profit=sold price - bought price=₹3400-₹3000=₹400 RS 3400-Rs3000=so profit was RS 400 ₹3400-₹3000=₹400answer. 3400-3000400 so, his profit =400 he had got 400 profit CP=3000SP=3400profit=SP-CP =3400-3000 =400 is the answer for this question
400 is the correct answer Selling price - Cost price= 3400-3000=400profit =400rs 400 RS.is correct answer . He is having profit of 400 Rs |
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| 9. |
| 140-145'145-150150155. 155-160160-165 |
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| 10. |
\frac{\tan 160^{\circ}-\tan 110^{\circ}}{1+\tan 160^{\circ} \cdot \tan 110^{\circ}}=\frac{1-\lambda^{2}}{2 \lambda} |
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Answer» reply please! reply please! The above solution is correct. |
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| 11. |
6LA = 3 LB = LC,finoIn a Δ4BC, ifZA, LB and ZC. |
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Answer» in triangle ABC,angle A + angle B + angle C = 180 C/6+ C/3+ C = 1809C/6 = 180C = (180× 6)/9C= 20× 6C = 120so angles are 120, 40, 20 |
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| 12. |
In adABC if2LA = 32B-62C, finaZA, 2B and 26,Ans. ZA 90°, B 60°, C-30 |
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| 13. |
21. If the points A(k + 1, 2k), B(3k, 2k + 3) and C(5k - 1, 5k) are collinear, thenfind the value of k |
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Answer» Given: If A (x1, y1) , B(x2, y2), C(x2,y2) To find: the value of k If three points are collinear then area of triangleABC = 0 1/2 { (x1[ y2-y1] +x2[y3-y1]+x3[y1-y2] } =0 given A(k+1,2k) ,B(3k,2k+3) ,C(5k-1,5k) therefore 1/2l(k+1)[2k+3-5k]+3k[5k-2k]+(5k-1)[2k-(2k+3)]l=0 (k+1)[3-3k]+3k*3k+(5k-1)(-3)=03k-3k²+3-3k+9k²-15k+3=06k²-15k+6=0 divide each term with 2 2k²-5k+2=02k²-4k-k+2=02k(k-2)-(k-2)=0(k-2)(2k-1)=0k-2 =- or 2k-1 =0 k=2 or k= 1/2 Like if you find it useful |
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| 14. |
5. If P (9a -2,- b) divides the line segment joining A (3a + 1, -3) and B (82,5) in the ra7.3:1, find the values of a and b.ÎNCERT EXEMPLAs. |
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| 15. |
017. Factorization of 36a -(x-y)3P-56 |
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Answer» We can use formula of a^2-b^2 here(6a)^2-(x-y)^2(6a+x-y)(6a-x+y)a^2-b^2= (a+b)(a-b) |
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| 16. |
2.) Find the factors of the tollowsa) 9a -54b) 6 |
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Answer» 9a-54= 9(a- 6) so 9 and (a-6) are factor |
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| 17. |
13. In a ABC,if 24A-34B-64C, calculate the measure of 4B. |
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| 18. |
Write the simplest form of 0.54 |
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| 19. |
(ii) 643+100 = 0, , Flo |
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Answer» 643 ÷ 100 भा. = 6 शेष = 43 If you find this answer helpful then like it. |
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| 20. |
x^2-25x+100=0, x=? |
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Answer» x = 20 Or, 5 is the answer of the question 20 ,5 is the correct answer of the given question |
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| 21. |
9. Write in simplest form:57624 |
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Answer» 576/(-24)=(24×24)/(-24)=(-24)/1 the answer is 576/(-24)= (24×24)/ (-24)= (-24) / 1 |
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| 22. |
a school, there are 3400 studens, Ithem are boys, hnd the number of girls, 65%er |
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Answer» In the school, there are 3400 students.Percentage of boys=65%Percentage of girls=35%∴Number of girls=35% of 3400=(35/100)×3400=1190 |
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| 23. |
-8.Write in the simplest form.10 |
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| 24. |
In a AABC, if32A42B 6C, calculate the angles. |
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Answer» 3A = 4B = 6C B = 3A/4 C = A/2 A + B + C = 180 A + 3A/4 + A/2 = 180 (4A+3A+2A) = 180×4 9A = 180×4 A = 80 B = 3×80/4 = 60 C = 80/2 = 40 If you find this answer helpful then like it. |
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| 25. |
204, Hnd the numbers. T O2. Find two numbers such that their sum is 27056 anddifference 846. |
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Answer» Let the two numbers be X and y hence X+y=27056and x-y=846add both 2x=27902X=13951hencey=27056-13951=13105 |
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| 26. |
Q1. Write -8/6 in the simplest form. |
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Answer» -8/6 in the simplest formhencedivide by 2-4/3 is the simplest form |
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| 27. |
Write the ratio 30 to 65 as a fraction in simplest form. |
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Answer» Ratio 30:65 as fraction can be written as = 30/65 Now in simplest form30/65 = 6/13 |
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| 28. |
(e) चतुर्थ ।।14. बिन्दु (-5, 10) की कोटि है ? (What is the ordinate ories010(d) प्रथमः।(b)15. विन्द 10.5) की भजा है...(d)4 |
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Answer» -5 is the correct answer 10 is the correct answer... -5 is a correct answer -4. C) 10 is the ordinate of( -5, 10) -5 is a correct answer 10 is perfect answer 10 Is the best answer 10 is the correct answer 10 is the best answer and correct answer -5 is the right answer 10 or -5 is correct answer 10 ............... . . |
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| 29. |
6cQ45-4 then 4-2- |
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Answer» 4b-5=6c/3+84b-5=2c+84b-2c=8+54b-2c=13 thnks didi |
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| 30. |
13) Multiply:a?b2, 12a2b and 6c. |
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Answer» (5/8)a^3b^2*12a^2b*6c45a^5b^3c |
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| 31. |
6. A is a point on the r-axis with abscissa-8 and B is a point on the y-axis withordinate 15. Find the distance AB. |
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| 32. |
5 a^2 - 15 a - 6c + 2 ac |
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Answer» 5a*a-15a-6c+2ac = 5a(a-3)+2c(a-3) = (5a+2c)(a-3) Thanks |
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| 33. |
+10p+25-16q25m1219a 36a b+36b-81.32b32b |
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| 34. |
Find the distance between the point -8/2,2 and 2/5,2 |
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| 35. |
2. Find the distance between the origin and thepoint:(8, -15) |
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| 36. |
Find the value of k, if the point (-8, 6) lies on thelocus+k.22 |
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Answer» [ x^2 / 4 ] + [ y^2 / 3 ] = kPutting the value of x and y as (-8) and (6) respectively, we get:64/4 + 36/3 = k=> k = 16 + 12 => k = 28. PLEASE HIT THE LIKE BUTTON nice |
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| 37. |
The number of tangents that can be drawn from the point (8, 6) to the circle x^{2}+y^{2}-100=0 is |
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Answer» as this point lie on circle therefore one tangent 8² + 6² - 100 = 64 + 36 - 100 = 0. So this point is on the circle. Hence there is exactly one tangent to the circle containing that point |
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| 38. |
Q15. If a B y are zeroes of the polynomial 6x +32? +5 ct)then find value of 21+ pt tyt |
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| 39. |
2. A is a point on x-axis with abscissa - 8 and B is a point on y-axis withordinate 15. Find the distance AB. |
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| 40. |
Hnd123 m |
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| 41. |
T. U.Ahe number line are such that, TRName the rational numbers represented by ,USR TAPQ1of the tairs represent the same rational number-16 20(i 20 -25and(iii) and912nd220, 8 and 14and 15.(vi) andand-9-95vrite the following rational numbers in the simplest form:45(is72the boxes with the correct symbol out of >, <, and =.2(iii)1(vi)4 |
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Answer» 1 by -3 is the best Answer so that these is the answer |
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| 42. |
Write simplest form of 45/60 |
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Answer» 45/60 = 3/4 ( reduced form) |
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| 43. |
o34 7 er= निकी ही75 - 7203 el |
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Answer» please like my answer if you find it useful |
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| 44. |
In the figure, prove that Za Lb + Lc360° |
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| 45. |
A is a point on the x-axis with abscissa -8 and B is a point on the y-axis withordinate 15. Find the distance AB. |
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Answer» that forms a right angled traingle.hence AB = √(-8)^2+(15^2)}√289= 17 |
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| 46. |
7. In Fig. 14.34, ABCD is a parallelogram in which ZA 60°. If the bisectors ofZA and LB meet at P, prove that AD DP, PC BC and DC 2AD |
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| 47. |
8. In A4BC, if2ZA 34B 6C, calculate ZA, LB and C. |
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Answer» angle A + angle B + angle C = 180°3×angle C + 2× angle C + angle C = 1806 × angle C = 180angle C = 30°so angle A = 90°angle B = 60° |
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| 48. |
(i) In a AABC, if 6LA=32B=<C,findZA, LB and ZC.In a ASUN, if 3 LS=42U=62N, findZS, ZU and ZN(ii) |
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| 49. |
In the adjoining figure, ABCD is a Dparallelogram in which ZA-60°. If thebisectors of ZA and LB meet DC at Pprove that ZAPB -90, (6) AD -DP andPB PC BC, (ii) DC-2AD. |
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| 50. |
3-An the figure given alongside AO BO and ZA LBiii) Is ΔΑ°C MOD by ASA condition?(ilil What are the three facts which have made AAOC(iv) Is AOC= BOD, why?ABOD? |
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Answer» 1. They are alternate interior angles sorry they are vertically opposite angles AOC=DOC....VERTICALLY OPPOSITE ANGLE AO=BO... GIVENA=B... ALTERNET ANGLE AOC=BOD... V. O. A AO=BO... GIVENA=B... ALTERNET ANGLE AOC=BOD... V. O. A AOC=BOD... V. O. A |
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