Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

उदाहरण 2. Jd का मान ज्ञात कीजिए।

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in denominatior assume x^4 = t and then solve it further you will get the results

2.

able Tyt jd an

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12+13+14+15=54

3.

Evaluate Jd

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4.

Q.What picteme d) Shown in the Pope of tradeMagring about hundred syers ago 2toreuItsino :3Find value of (tan of secos

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5.

10. In a right triangle the acute angles are in the ratio of4:5. Find the acute angles of the triangle.

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1st angles=90•sum of ratio=9x9x=90x=10•2nd angle=4*10=40•3rd angle=50•

40 and 50 is the right answer

40° and 50° is the correct answer

the right answer is 40° and 50°

the right answer is 4o° and 50°

40°and 50° is the correct answer.

write answers of 40 degree and the 50 degree for this question

The acute angles are 40,50

6.

re acute angles such that cos A - cos B, then show that LA -LB.NCERTrA and 4Bare acute angles such that cos

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7.

Se appropriate p3× 2 ± 7-1x34. Renra

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By BODMAS theory,

-2/5 + 7/2 - 3/10

= 7/2 - 7/10

= 35-7/10

= 28/10

8.

Rewritethefollowingrational numbers in the simplest fo25454.(m) 2(fi)

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-8/6=-4/325/45=5/9

9.

6. If all the angles of a triangle areequal, then hnd el7.trwo acute angles of a triangle are equal, then find each acute ang

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acute angles are less than 90°

10.

) Find the value of k if the point (-8, 6) lies on the locus x^2 /4+ y^2 /3 =k

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if (-8,6) lies in given locus it will satisfy the equationso(-8)²/4 + (6)²/3 = k64/4 + 36/3 = k16 + 12 = kk = 28

thanks

11.

. If θ and 39-30"Ih 0 and 30.30 are acute angles such that sine-cos(38 30) then find the value of tan6.are acute angles such that sin6-cos(39-30"),then find the value of tanθ

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we can write it likecos(90- theeta)= cos(3theta-30)90-theeta= 3 theta-30120= 4 thetatheta = 30°then tan (30°)= 1/√3please like the solution 👍 ✔️

12.

5. Some numbers can be shown by two rectangles, e.g.,. .• ••• •18 -... . .. .•.....or..........Write atleast 5 such numbers.Seal

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16,12,8,6 is the four no.....shown by two rectangle

16,12,9_6,3 is the right answrr........

16,12,8,4 is the four no,shown by 2 rectangle

16,12,8,4...............

16,12,9,6,3 is the correct answer

6,8,12,16,3 are the 5 no shown in two ractangle

16,12,8,6 is the 4 not shown by two rectangle

16,12,8,6 is the four no.shown in twi rectangle

16,12,8,6 is four no.......shown by two rectangle

13.

Find the product:9 /2 *(-7/4)

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14.

state whether the following seal numbers aresational or is-sational o(1) 2.5675 ciu) 2.37517is 17.35

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iii) is the right answer of the following

ii) is the right answer or not

Yes had bdvnhfn cdnnnf

all numbers are rational

3 is right answer of this question

rational or irrational by 17.353535

second is the correct answer

option 3 is the correct answer

15.

Find the product:9/2 x (-7/4)

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16.

Sas tuoay

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Softwareis a general term for the various kinds of programs used to operate computers and related devices. (The term hardware describes the physical aspects of computers and related devices.)

17.

On 30th June 2009 the cash bort shows the balanceon coroaring Car Dook with Pass Book te showing reSNOUT A WINEMAYOth Bock shows the balance 16,000/ but Pass Book shows the different baleass Book te hollowing reasons fere foundParticularsreceived and deposited but not cleared <2,500/-ved to bunty 3,000/- which is not presented for payment in bankerest or Fixed deposit credited in ass book only 500% no WMATelephone bill paid by the bank 1,000/- Shiw60 216WCheque 2,000/- deposited but dishonoured.Sgnit209 216W ISBank charges and commission 500/- recorded in the Pass Book 15WDividend collected and credited in the Pass Book only R2000x4058 21 15W

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Debit balance of cashbook is 9556

18.

DateStatuso whose second number is 18:4-12(b)(d) 11:44-5

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1 : 5 can also be written as 5 : 1

19.

househoidsgrsilFind the mean daily expenditure on food by a suitable method.To find out the concentration of SO, in the air (in parts per million, i.e.,was collected for 30 localities in a certain city and is presented below:ppm),texFrequencyConcentration of SO, (in ppm)0.00 0.040.04 0.080.08- 0.120.12 0.160.16 0.200.20 0.24E:4FiSe924

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20.

Find the mean daily expenditure on food by a suitable method.ind out the concentration of SO, in the air (in parts per million, i.e. ppm),collected for 30 localities in a certain city and is presented below:Concentration of SO (in ppm)0.00-0.040.04- 0.080.08 0.120.12 0.160.16 0.200.20 0.24Frequency2

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21.

and3,10,17.equal ?8. Prove that/5 is an irrational number.

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22.

弱氠!, andINCERTFind the sum of the vectors a = i-2 j + k, b =-2 i+4j +5k

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23.

Find the mean daily expenditure on food by a suitable method.was collected for 30 localities in a certain city and is presented belowe concentration of SO2 in the air (in parts per million, i.e., ppm), the dataConcentration of SO, (in ppm)0.00 0.040.04 0.080.08 0.120.12 0.160.16 0.200.20 0.24Frequency4.9242Find the mean concentration of SO, in the air.

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24.

16.If α, β are the zeros of the polynomial x2-(k + 6) x2 (2k-1)TEnd

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25.

2 5kIfor,4., k,then k =are in A.P3816D)-1A) 2B) 1

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tq

26.

If one zero of the polynomial x2 – 8x + k exceeds the other by 2, find thevalue of k.

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4-8(4)+k=04-32+k=0-28+k=0k=28

let one zeros= a 2nd zeros= a+2sum of zeros (a+a+2)=82a=6 so a=3 product of zeros a(a+2)=k3(3+2)=k3×5=k15=k

27.

- If one zero of the polynomial x2 – 8x + k exceeds the other by 2, find thevalue of k.

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28.

चर o“m’” 3me—%CaE

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29.

33. Evaluate:48tan2 60 + 4 sin2 45+3 sec 30+5 cos 9cosec 30 sec 60° cot 30°T-2ICBSE 2011]

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30.

Simplify :-14-[9-{10+30÷(4-8-6)

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31.

Q4) Find the value of a, if 16 + = 32 - 16.Q.5J You have 700 in your Savings Account at the beginning of the month. The record below shows all of yourtransactions during the month:Cheque numberDateTransactionDescriptionPaymentDeposit3841024/9Mseb bill25027514613/9Deposit20032598724/9LIC of India25012345630/9Deposit150If the product of two integers is - 216 and one of them is-6, then what is the other integer?

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6)let other intezer=xX*-6=-216X=-216/-6=39

X=216/-6=39 is the right answer

32.

4 of 30 AlgebraIf xis real the minimum value of 4x - 49 is

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If you find this solution helpful, Please give it a 👍

33.

that 3s an irrational number, prove that (2-5) is an irrational number8.llel to AB and AC

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right answer

show that (√3+√5)² is an irrational number

34.

Prove that 3 +2/3 is an irrational number

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Let us assume that √3 is a rational number.

then, as we know a rational number should be in the form of p/q

where p and q are co- prime number.

So,

√3 = p/q { where p and q are co- prime}

√3q = p

Now, by squaring both the side

we get,

(√3q)² = p²

3q² = p² ........ ( i )

So,

if 3 is the factor of p²

then, 3 is also a factor of p ..... ( ii )

=> Let p = 3m { where m is any integer }

squaring both sides

p² = (3m)²

p² = 9m²

putting the value of p² in equation ( i )

3q² = p²

3q² = 9m²

q² = 3m²

So,

if 3 is factor of q² then, 3 is also factor of q

Since

3 is factor of p & q both

So, our assumption that p & q are co- prime is wrong

hence,. √3 is an irrational number

A rational number multiplied by an irrational is irrationalhence 2√3 is irrationalNow a rational number added to irrational is irrational hence 3+2√3 is irrational

35.

UsingBio-nomial Thearomexpandcae+5)

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x^3+15x^2+75x+125 is your answer.

(x+5)³=1(x)³+3x²(5)+3x¹(5)²+1(5)³=x³+15x²+75x+125

36.

In the given figure, LM CB andAM ANProve thatAB AD Aバ

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37.

AC CBthe given figure, 21 22 andE. Prove that Δ4CB ~ ADCE.BD

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38.

24. Find the common differene of an AP whoErst term is 4, last term is 49 and the szue suuof all its terms is 265.[CBSE 201

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hit like if you find it useful

39.

bauanas san be

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Cost of 4 dozens(12*4=48) bananas=Rs 80Rs80=48Rs15=48*15/80=9 bananas

40.

25. In the given figure, if AC = DC and CB = CE, then show that AB = DE.

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hi friend It can be done by sas because as two sides are given and /_ acd=/_ecb

it can be done by SAS congruence why because they had given 2 sides and the angle acd =angle ecb why because vertical opposite angles are equal

suppose AC=x. to CD=x hogaor CE=y to CB=y hoga yadi AB ka add x+y hab DE ka add karte h to x+y ayega isase pata chalta h ki AB = DE hai

AC+CB=AB ¹DC+CE=DE ²AC=DC ³CB=CE ⁴using 1,2,3,4,AB=DE

given AC=DC, CB=CEwe know that if equal added to equals then answer will be equalAC+CB=DC+CEAB=DC

hi friend It can be done by ses because as two sides are given and /_acd=/_ecb

AB=DE is a .....(alternate angle) tested

by sas congruence this is proved that about!=de

we can see that......AC=DC and CB=CE....then add these both...AC+CB=DC+CE......=AB=DE

AC=DC (i)BC=CE (ii)

FROM FIRST AND SECONDAC+BC=DC+CEAB=DE HENCE PROVED

AC=DCgivenCB=CE givenangleC=AngelC vertically opposite angeltriangles are congruent by SAS rule by CPCT rule triangles Are congruent AB=DE

given ,AC=DC. ,CB=CESOLVE:- in ∆ADC and ∆EBCAC=DCCB=CE<ACD=<ECB ( by SAS)SO. AD=

In triangle ACD and ECB ,Angle ACD= angle ECB (vertical angle) Now, Side-angle-

41.

7. In the given figure, if x y and AB CB thenprove that AE - CD.

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42.

(pl. I san):

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(-1/28a2b2) * (-9/2 a3bc2) (-9*-1/27*2 )a2b2*a3bc254a5b3c2

43.

P/ial

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2.357

44.

2: Divide 24x2y2 -4xy by 2xy.ial 4x2

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(24x²y²-4xy)/2xy4xy(6xy-1)/2xy2(6xy-1)12xy-2

45.

Simplify 34 + x to San

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16x/5 is correct answer.

16x/5 is right answer.

After taking the least common integer of the denominator,we get required result.

46.

If the polynomial p(x) = 6x3 + 2x2 - ax + b, when divided by (x +1) leaves remainder 14 and (x-1) is afactor of p(y). Find a and b.

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A=13. b=5. answer of question

47.

SUU(c)1. Subtract. Regroup only if needed.(a) 59 (b) 30949(f)5 7402. Subtract. Then check your answer with addition,(b)8206(2) 5 329

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55 26 84। 17। 25

1 a 55 b 26c 84f 17 g 25h 14

a,, 55b"34c"96f"17g"25h"11

48.

.Of K..nngIf α, β are the two zeroes owhose zeroes areand6.the polynomial 25 p-15 p t 2, find a quadratic polynomial

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49.

show that 5+2/3 san irrational number.

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50.

1. If p and q are roots of the equationsx 10, theni find the equation whose rootsare (p+ 2) and + 2)

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