In a AABC, if32A42B 6C, calculate the angles. – InterviewSolution

1.

In a AABC, if32A42B 6C, calculate the angles.

Answer»

3A = 4B = 6C B = 3A/4 C = A/2 A + B + C = 180 A + 3A/4 + A/2 = 180 (4A+3A+2A) = 180×4 9A = 180×4 A = 80 B = 3×80/4 = 60 C = 80/2 = 40

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