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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
article is sold at a certain price one gains 10%. What will be the gain percethe price?nt ifsoldfordouble9. If |
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| 2. |
3. If selling price is doubled, the profit triples. Findthe profit percent.2A. 66-3B100D. 120C. 105-3In a certain store, the profit is 320% of the cost.If the cost increases by 25% but the selling price4:remains constant, approximately whatpercentage of the selling price is the profit?A. 30%B. 70%C.100%D. 250905.A vendor bought toffees at 6 for a rupee. Howmany for a rupee must he sell to gain 20%? |
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Answer» Let C.P. be Rs. x and S.P. be Rs. y. Then, 3(y - x) = (2y - x) y = 2x. Profit = Rs. (y - x) = Rs. (2x - x) = Rs. x. Profit % ={(x/x)x100}% = 100% |
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| 3. |
trader buys certain items at 32 % off the list price and he wants to make aprofit of25 % after allowing a discount of 20 %. At what per cent above the listprice should he mark the items? |
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Answer» Let the List price(M.P) be 100 Rs.He buys it at 32% off the list priceC.P = 100 - 100*32/100 = 68 Rs.P= 25%S.P = C.P*(100+P)/100 = 68*125/100 = 85 Rs.Discount = 20%Discount is always given on M.PS.P = M.P*(100-discount)/10085 = M.P*80/100M.P = 106.25 Rs.The (assumed) list price was 100Hence, mark up % = 106.25-100/100 * 100 = 6.25%So he should mark 6.25% above the list price. hit like if you find it useful |
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| 4. |
. Why are 89 and-89 called opposites? Use a number line toexplain. |
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Answer» They lie exactly equal distance away on either side of zero but their signs are different. Hence they are called opposites. |
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| 5. |
75-23×67÷89 |
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Answer» 75-23×67÷89=57.6853932584 57.69 is the correct answer of the given question correct answer is57.69...... the correct answer of the given quetion is57.69 75-23×0.7575-17.3157.68is correct answer 57.69 is the right answer 57.69 is the right answer |
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| 6. |
9.6+89 |
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Answer» 9.6+89=98.6 answer is 98.6 95.6 is the correct answer 98.6 is the answer sorry 9.6+89=9.6 answer hoga the correct answer is 98.6 9.6+89= 98.6The easier way to remember this is:assume 9.6 to be the nearest whole number i.e. 10now add 89 and 1089+10=99now the difference between 10 and 9.6:10-9.6= 0.4so subtract 0.4 from 99:99-0.4= 98.6so the answer is 98.6 |
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| 7. |
2+89+100 |
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Answer» simple addition = 2+89+100 = 100 89 2 -------- 191 |
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| 8. |
289 92 |
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Answer» 1623 is the answer for ur question |
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| 9. |
(1)8 >yLt जद‘es%B> |
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Answer» hit like if you find it useful |
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| 10. |
es 3 Rationalize the denominator of -1(2+13) |
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| 11. |
Evaluate:\sin 23^{\circ} \cos 67^{\circ}+\cos 23^{\circ} \sin 67^{\circ} |
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Answer» sinx = cos(90-x)sin23 = cos(90-23) = cos67similarlycosx = sin (90-x)cos23 = sin(90-23) = sin67therefore it becomes(cos67)^2 + (sin67)^2 = 1because (cosx)^2+(sinx)^2 = 1answer is 1 |
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| 12. |
67+67= |
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Answer» the answer to this question is 134 |
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| 13. |
(cos2 67。-sin, 23°)虱册靭君?What is the value of (cos 67 -sin2 239)? |
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Answer» cos²67-sin²23=? cos(90-α)=sin(α)cos(90-23)=sin(23)cos(67)=sin(23) on squaring both sides cos²67=sin²23cos²67-sin²23=0 |
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| 14. |
(-3)-(-46)÷(-23)+(-3)(5) |
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Answer» (-3) - (-46) ÷ (-23) + (-3)(5) = (-3) - 2 - 15 = - 18 - 2 = - 20 |
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| 15. |
13.2 Write IUPAC names of the following compounds(a) CH,CH-C(CH3)2(b) CH-CH |
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| 16. |
_ Compare मद ना। ०0८4१ 2115.किला...109 20 “कस.कि. |
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Answer» 9*15/10*15 and 11*10/15*10=135/150 and 110/150hence135/150>110/150 |
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| 17. |
10. If 2*** 8175 = 2115, then x is equal to(b)win atV. 2 |
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Answer» 2^x * 8^1/5 = 2^1/5 2^x + 2^3/5] = 2^1/5 2^[x + 3/5] = 2^1/5 x + 3/5 = 1/5 x = 1/5 - 3/5 x = (1 - 3)/5 = - 2/5 (d) is correct option |
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| 18. |
Find the value of log,p 256 |
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| 19. |
GST stands for |
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Answer» GST stands for Goods and Services Tax |
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| 20. |
a customer gets a discount of rs 78 on an article if a discount of 12 % is allowed. find the marked price and the selling price of the article. |
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| 21. |
7.MTNL stands for |
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Answer» Mahanagar Telephone Nigam Limited (MTNL) is a state-owned telecommunications service provider in the metro cities of Mumbai and New Delhi in India and in the island nation of Mauritius in Africa. Like my answer if you find it useful! |
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| 22. |
दि व 2.व्यंजक 3८ 6+ 20८ + 346 का एक उभयनिष्ठ गुणनखंड होगा : |
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Answer» 3ab+2ac+3ad3ab+3ad+2ac3a(b+d)+2aca(3(b+d)+2c) ans is a only |
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| 23. |
346-67 |
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| 24. |
% loss on cost price but uses 14 gm. Instead of 16 yms. His110. A dishonest dealer sells goods at 6 -percentage of profit is - |
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| 25. |
346+96 |
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Answer» your answer 346+96=442 |
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| 26. |
प्रश्न 13. यदि_125][4 ]तथा B = 2 1 है, तब AB तथा BA ज्ञात[346| 15A0 |
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| 27. |
реж X 785= 2157855-21.28. |
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Answer» 7.85×7.85=61.62252.15×2.15=4.62257.85×7.85-2.15×2.15/(7.85-2.15)=2/5.7=0.35 |
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| 28. |
9% of1800 |
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Answer» 5/6% of 1800=5/6(1800)0.833×1800=1500 |
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| 29. |
Q11)Complete the number puzzle. Fill in the boxes with correct mathematicaloperations +, -, Xand - horizontally and vertically both.516 = 24=24324 21526 2 25II1221 |
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Answer» 8th maths rational numbers new syllabus exercises 1.1 Hi, Here is the answer to your question. |
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| 30. |
he16 256ziuate log, |
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| 31. |
\operatorname { log } _ { 4 } 16 - \operatorname { log } _ { 8 } 256 |
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Answer» Using base changing formula |
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| 32. |
Q 1 : If log 4 = 0.6021, then find the value of log 16 and log 256. |
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Answer» log 16=log4^2=2log4=2*0.6021=1.2042log 256=log4^4=4*0.6021=2.4084 thanks |
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| 33. |
16x /25664valuate log |
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Answer» Thank you so much |
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| 34. |
An article markeddiscount percent.800 is sold for704. Find the discount and |
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Answer» Discount percentage= 800-704/800*100= 12 percentagediscount = 800-704= 96 |
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| 35. |
A person pays? 2.800 for a cooler listed atoffered10.3,500. Find the discount percent |
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Answer» Selling price= 2800listed price= 3500so discount=700 now % of discount= 700/3500×100= 20% Like my answer if you find it useful! |
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| 36. |
A trader buys an article for1,200 and marks it 30% above the CP He thensells it after allowing a discount of 20%. Find the SP and profit percent |
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Answer» hit like if you find it useful |
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| 37. |
An article is marked for Rs. 1,300 and is soldfor Rs. 1,144. Find the discount percent. |
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| 38. |
A dishonest trader claims that he sells itemsat the cost price. However he uses weight of960 gm in place of 1 kg. What is hispercentage profit ? |
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Answer» let cost of 1000gm = ₹100sp of 960gm= 100 1gm= 100/960 1000gm= 1000×100/960profit = sp - cp = 100000/960-100 = 100000-96000/960 = 4000/960%profit = profit×100/cp = 4000×100/960×100 = 400/96= 100/24= 25/6% |
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| 39. |
. Pove that the area of rhombus is equal to half the rectangle contained by is diago |
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Answer» let ABCD is a rhombus whose diagonals AC=2x and BD= 2y. cut at point o. OA=OC=2x/2=x , and OB=OD=2y/2=y Area of right angled triangleAOB=(1/2)×x.y Area of rhombusABCD=4×Area of triangle AOB =4×(1/2).x.y =2x.y……………………..(1) Area of rectangle contained its diagonal=2x.2y=4xy =2×(2x.y)………………(2) from eq.(1) and(2) Area of rhombus is half of the area of rectangle contained by its diagonals. |
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| 40. |
16 256Evaluate log, -304- |
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| 41. |
12/304 |
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Answer» 25.333 is the answer. 25.333 is the correct answer |
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| 42. |
0.72 \div 0.09 \times 90 = ? |
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Answer» = 0.72÷0.09×90= 8×90= 720 |
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| 43. |
3(i) 17283-93 eTo भान कऊू ? |
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Answer» (1728)¹/³ =(12*12*12)¹/³ ={(12)³}¹/³ =12 |
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| 44. |
eto |
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Answer» √20.25=4.5is the value |
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| 45. |
1The perimeter of a rectangle is 200 m. If one of its sides is longthan the other side by 16 m, find the length of each of the sides. |
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Answer» Perimeter = 2(l+b)given thatl= 16+b200= 2(16+b+b)100-16= 2b84= 2bb= 42mlength= 42+16= 58m |
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| 46. |
DATE: 20find theeto the pai3end2 |
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Answer» plz my next qus. ans. |
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| 47. |
- और 15 क == = या है।| (5) 5.(८) 6= = = = = = ॐ लए HF 1820) ४(d)=M(1820 बराबर हैं। |
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Answer» 2| 272| 1783| 136| 89म सा वी = 2×3=6(c) 6 is the correct answer. 2| 272| 1783| 136| 89म सा वी = 2×3=6(c) 6 is the correct answer |
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| 48. |
30. A body of mass 10 kg is dropped from ae isheight of 20 m. Find (i) its potential energybefore it is dropped, (ii) its kinetic energywhen it is 8 m above the ground and (iii) itskinetic energy when it hits the ground.reisandr toTake g10 ms-2 |
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Answer» At any point of the time total sum of P.E + K.E will always be constant so, P.E at start = mgh = 10*10*20 = 2000J and loss in P.E when it is at 8 m above the ground will be equal to gain in K.E so, K.E = mg(20-8) = 10*10*12 = 1200J and K.E at bottom = P.E at top = 2000J and Please.. tag the Correct grade and subject to your question. This isn't a 7th grade questions and doesn't even fall under mathematics. |
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| 49. |
180 contained in a box consist of one-rupee, 50-paise and 25-paisecoins in the ratio of 2:3:4. How many 50-paise coins are there inthe box?(A) 120(B) 60(C) 40(D) 240 |
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| 50. |
press the following amou80 rupees 40 paise120 rupees 39 paiserite the following amount |
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