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Evaluate:\sin 23^{\circ} \cos 67^{\circ}+\cos 23^{\circ} \sin 67^{\circ} |
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Answer» sinx = cos(90-x)sin23 = cos(90-23) = cos67similarlycosx = sin (90-x)cos23 = sin(90-23) = sin67therefore it becomes(cos67)^2 + (sin67)^2 = 1because (cosx)^2+(sinx)^2 = 1answer is 1 |
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