This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
6. ABCD is a rhombus in which altitude from D onAB, bisects AB. Find the angles of the rhombus. |
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| 2. |
5x=5 then x=? |
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Answer» x=1 is right answer..... |
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| 3. |
60°10Find the value of x |
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| 4. |
Prove that the opposite side of a parallelogram are equal |
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Answer» ABCD is a parallelogram. To prove that AB = CD and AD = BC. Join the diagonal AC. In the triangles ABC and CDA:angleBAC= angleDCA(alternate angles, AB || DC) angleBCA= angleDAC (alternate angles, AD || BC) AC= CA (common)so triangleABC ≡ triangleCDA (AAS)Hence AB = CD and BC = AD (matching sides of congruent triangles) |
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| 5. |
12. 14 - PT> [s]", find the value of []".find the value ofNo10 |
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Answer» a/b=[3/2]^2*[2/3]^-4a/b=(3/2)^2*(3/2)^4a/b=3^2+4/2^2+4=3^6/2^6(a/b)=(3/2)^6(a/b)^-3=(3/2)^6^-3(3/2)^2=9/4 |
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| 6. |
5. One side of a parallelogram is 18 cm long and its area is 153 cm2. Find the distance of thegiven side from its opposite side.logram ABCD, AB = 18 cm, BC = 12 cm. ALDC and AML BC. |
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| 7. |
An oblong garden measures 60 m by 55 m. From the centre of each side, a path 2 metres wide goes across to the centre of the opposite side. Find the area of the paths. |
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| 8. |
c)Ifthe volume ofa cube is 3V3л░ли then total surface area of the cube isi) 6a2ii) 18a2iv) 18v3ad) The arithmetic mean of numbers 5,10,15,22,20,35 and 40 will be |
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Answer» Volume of cube = 3sqrt(3)a^3 Let side length of cube be s Then, volume of cube= s^3 Hence,s^3 = (3)^3/2*a^3s = sqrt(3)a Surface area of cube= 6s^2= 6(sqrt(3)a)^2= 6*3a^2= 18a^2 (c) is correct option |
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| 9. |
Theorem 8.7: If the diagonals of a quadrilateralbisect each other, then it is a parallelogram. |
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| 10. |
RepeaTheorem 8.3: If each pair of opposite sides of a quadrilateral is equal, then itis a parallelogram.Eac |
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Answer» Given: A quadrilateral ABCD in which To Prove: ABCD is a parallelogram i.e., AB ║ DC and AD ║ BC Construction : Join A and C Proof : In ∆ABC and ∆CDA AB = DC [Given] AD = BC [Given] And AC = AC [Common] ∴ ∆ABC ≅ ∆CDA [By SSS] ⇒ ∠1 = ∠3 [By cpctc] And ∠2 =∠4 [By cpctc] But these are alternate angles and whenever alternate angles are equal, the lines are parallel. ∴ AB ║ DC and AD ║ BC ⇒ ABCD is a parallelogram. |
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| 11. |
B - 35-14+07) |
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Answer» 12÷(3.5-1.4+0.7)=12÷(4.2-1.4)=12÷(2.8)=4.28 |
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| 12. |
1. 35 का कितने प्रतिशत 14 होगा? |
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Answer» x% * 35 = 14 (x/100) * 35 = 14 x = 40% 35 ka 60% 14 hoga |
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| 13. |
Find x, if mean of 30, x+ 4, 14, 35, x+ 2, 13, 32 and10 is 24. |
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| 14. |
( \frac { - 16 } { 35 } ) \div ( \frac { - 15 } { 14 } ) |
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| 15. |
67/14 %2B 35*42 |
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| 16. |
(5x 5x5x5x 5x 5)4 x (5x 5)6+52(25) |
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| 17. |
(5x + 2) (5x-3) |
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Answer» (5x + 2) ( 5x - 3)25x² - 15x + 10x - 625x² - 5x - 6 thanks |
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| 18. |
8,(2x)2 + 5x = 4x + 5x = 9x |
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| 19. |
5x+5x=10 find value of x |
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Answer» x=1 is the right answer |
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| 20. |
10 workers earn ₹4,800 in 4 days what amount will 8 workers earn in 6 days |
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Answer» 10 workers earn 4800 in 4 days1 worker earn in 4 days is 4800/10= 4801 worker earn in 1 day is 480/4= 1201 worker earn in 6 days is 120*6= 7208 worker earn in 6 days is 720*8= 5760 hence, 8 workers earn Rs.5760 in 6 days |
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| 21. |
10x2 + 1 5x + 63-2x+3() 5x-25x +12 |
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Answer» please like my answer if you find it useful |
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| 22. |
6. Write the measure of the complement of each of the following angles.(1) 630(1) 450 (ili) 600 (iv) 74° |
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Answer» 45 this is the abswer 45°is the correct answer. option (ii) i.e 45° is the best answer. 45° is the correct answer. 45 is the correct answer 45 is the right answer 45 is the compliment (ii) 45° is the correct answer 1)272)453)304)16 is the best answer correct answer is 45° 45 is a right answer 45 is the correct answer 45° is the right answer As we know the complement of angle is 90-angleso complement of 63 degree would be 27 degreecomplement of 45 degree would be 45 degreecomplement of 60 degree would be 30 degree andcomplement of 74 degree would be 16 degree (ii)45° is the right answer for this questions...... 45 is the right answer 45° is correct answer. 45 degree is the correct answer 45 is the corect answer 1)117° 2)135°3)120°4)106° 2)1353)1304)106° 1). 272). 453). 304). 16is the correct answer 45 is correct answer of this question 45 is the best answer 45° is the best answer 1)27 2)453)304)16 ii 45° is the correct 45 is a good answer that question the correct answer is 45 45 is correct answer 45° is correct answer 45 is the correct answer to this question 45 the measure of the complement of each of the following angles 2nd answer 45 is the correct answer ans1is 27 degree isthe right answer i)27ii)45iii)30iv)16 90-45=45so , 45 is the correct answer this questions ans is 45 right answer is 45° hoga option ii is the best answer 16 is question of the answer this questions ans is45 45 degree correct answer 27 is complement of 63,45 is complement of 45,30 is complement of 60,16 is complement of 74 complement of 63 = 63-90=72 (ii)45 is right correct answer 45degree is the right answer.... (2) 45° is correct. 45 ans carrect this answer 1=90-63=272=90-45=453=90-60=304=90-74=16 45 is correct answer 45 is the right answer hai (1)117°(2)135°(3)120°(4)106° Measure 45 is the absolute answer 45° is the correct answer (ii) 45 is the correct answer 45 degree is the answer 45 is the answer of the question The answer is this question option (ii) 45°. 1) 272) 453) 304) 16 is the correct answer 27degrees, 45degree, 30degree and 16degree 45° is accurate answer correct answer is 45 45 Digree is the correct 45 is a correct answer 45 is the correct solution right answer is option (ll) my opinion 45° is the correct answer 45°is the correct answer h 45°is correct answer right answer is 45 hoga 45° is now the anwer of your question 45° write answer according to me i. 27ii. 45iii 30iv. 16 45°is the correct answer 27,45,30,16 is the answer 45( ✔) Correct Answer . 60 measures of completion of Angie's 27,45,30,16 is the correct answer 45° is the correct answer (2) 45° Sahi answer hoga 45 hi is the ans... 45° is the best answer. option b 45° is the correct answer 45° is right answer these questions a_ 27' b_45' c_30' d_16' 6.i. Complement of 63 degree = 90 degree -- 63 degree = 27 degree ii. Complement of 45 degree = 90 degree -- 45 degree = 45 degreeiii. Complement of 60 degree = 90 degree -- 60 degree = 30 degreeiv. Complement of 74 degree = 90 degree -- 74 degree = 16 degree (i)27(ii)45(iii)30(iv)16 45 is the correct answer because one angle is 45 |
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| 23. |
Daily wages of 45 workers in a factory are given below:Daily wages (in) 300 3 75 4 50Number of workers 6895251260010Find the median and the mean.Using empirical formula, calculate its mode. |
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Answer» Here,Nis45,whichisodd.Median={(N+12)thobservation}={45+12}observation=23thobservationMedian=150Mean=∑(fi×xi)∑fi=705045=156.67Mode=3(Median)−2(Mean)=3(150)−2(156.67)=450−313.34=136.6Here,Nis45,whichisodd.Median=N+12thobservation=45+12observation=23thobservationMedian=150Mean=∑(fi×xi)∑fi=705045=156.67Mode=3(Median)-2(Mean)=3150-2(156.67)=450-313.34=136.6 Hence, the median is 150, the mean is 156.67 and the mode is 136.6. The ages(in years)of11 cricket playear are given below |
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| 24. |
|2. The following table shows the weights of 12 workers in a factory:- Weight (in kg) 60 63 , 66 | 69 | 72No. of workers 4 3 2 2 1Find the mean weight of the workers. |
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| 25. |
2. 10 workers earn 4,800 in 4 days. What amount will 8 workers earn in 6 days? |
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Answer» thanks |
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| 26. |
16m of fencing was laid by 4 workers in 6 hours. How many workers arerequired to lay 108 m of fencing in the same time? |
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| 27. |
16m of fencing was laid by 4 workers in 6 hours. How many workersrequired to lay 108 m of fencing in the same time? 2.7 |
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Answer» 16 m of fencing was laid by 4 workers in 6 hrsso for 108 m of fencing need to be laid in 6 hrs by 4*6*108/(16*6)=27 workers |
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| 28. |
8.The following table shows the weights of 12 workers in a factoryWeight (in Kg)60 64 68 70 72Number of workers 3 4 2 2 1Find the mean weight of the workers. |
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| 29. |
In triangle ABC, if X & Y are points on AB and AC respectively such that AX/AB = 3/4, AY=5 and YC=9, then state whether XY & BC are parallel or not? |
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Answer» If you like the solution, Please give it a 👍 |
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| 30. |
, wo sides AB & BC and median AM of A ABC are respectively cqual to sides PO & ORand median PN of Δ PQR. Show that Δ ABM ΔΡΟΝ18. Two |
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Answer» tq |
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| 31. |
2. Find the ratio of the volumes of a cone and of a cylinder whose basediameter and heights are equal |
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Answer» Volume of a cone= 1/3πr^2hvolume of cylinder= πr^2hratio= 1/3πr^2h/πr^2h1/3:11:3please like the solution |
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| 32. |
7, Q is a point on the side SR of a ∆PSR such that PQPR. Prove that PS = PQ.prove that Ps>PQ |
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Answer» 1 2 |
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| 33. |
5. What is the sum of all intertor angles of a regular(iv) polygon of 12 sides?(1) pentagon(ii) hexagon(ili) nonagon |
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| 34. |
4. ABC is a triangle in which altinudes BE and CF osides AC and AB are cqual (see Fig. 7.32) Showthat) AB AC.ie, ABC is an isosceles triangle.Fig. 7.32 |
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| 35. |
4 asLa |
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Answer» 15a-60-2a+18+5a+30=018a-12=018a=12so a=12/18=2/3 |
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| 36. |
Look at the figures and complete the table below.FigureSide ABSide PQSide LMNames of sidesNames of vertices |
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Answer» triangle , rectangle ,square sides of triangle = AB,BC,AC and vertices are A,B,C .sides of rectangle = PQ,QR,RS,SP and vertices are P,O,R,Ssides of the square=LM,MN,NO,LO and the vertices are L,M,N,O triangle , rectangle, square |
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| 37. |
In Î DEF, line PQ ll side EF, If DPPE 7.2, PQ 1 then find QF.2.4,Et |
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Answer» Answer: QF = 2 Step-by-step explanation: It is given that, In ∆ DEF, line PQ || side EF, If DP = 2.4, PE = 7.2, PQ = 1 then find QF. Here PQ || side EF If a line is drawn parallel to one side of a triangle to intersect the other two sides in distinct points, the other two sides are divided in the same ratio To find QF DP/PE = PQ/PF PF = (PQ x PE)/DP =(7.2 x 1)/2.4 = 7.2/2.4 QF = PF - PQ = 7.2/2.4 - 1 = 2 Therefore QF = 2 answer is QF = 5.4BUT explain the method please |
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| 38. |
7, Qis a point on the side SR of a APSR such that PQ=PR. Prove that PSPQ |
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Answer» given : PSR is a triangle.and PQ = PRTPT:PS > PW proof : inΔ PQR, PQ = PR therefore∠PQR =∠PRQ now∠prq >∠psq∠PRQ> PSQ or∠PRS > PSRnow in the triangle PSR :∠PRS>∠PSR therefore PS >PRthus PS > PQ HENCE ITS PROVED |
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| 39. |
4Prove that :eolnomial 2-22-1+1 by +1 and verify remainder by using remainder 4theorem43.6State Factor theorem. Using Factor theorem, factorise x3 -3x2-x+ment Save Future" a rally was organized by some 4For spreading the message "Save environstudents of a school. They were gto two parts by drawing the angle bisectors BO and CO of base aniven triangular cardboard piece ABC which they divided ingles B and C. Prove thatBOC90A What is the benefit of these types of rallies?2 |
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Answer» tq plz give me answer of other questions also state and probe bpt theorme |
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| 40. |
totheTHEOREM 1third side and equal to halfofitThe line segment joining the mid-points ofany two sides of a triangle is parallelofsides ARand AC respectively. DEis |
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| 41. |
1. Which number is neither a prime number nor a composite number? |
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Answer» your answer is 1 1 is nor prime or composite 1 is neither a prime number nor a composite number 1 number is the neither a prime number nor composite number. 1 is correct answer on question 1 is 9 prime or nor composite this is your answer 1is neither prime number nor composite number 1 does not have any factor except 1 . so it is neither prime nor composite 1 doesn't have any factor except itself 1. so it is neither prime nor composite number |
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| 42. |
Find the ratio of(a) 90 cm to 1.05 m(c) 150 mL to 2 L |
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Answer» ok thanks for your response |
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| 43. |
1 Which number is neither a prime number nor a composite number? |
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Answer» the Answer is actually 0 because it is not even but it is not odd |
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| 44. |
Two sides AB and BC and median AM Aof one triangle ABC are respectivelyequal to sides PQ and QR and medianPN of Δ PQR (see Fig. 7.40). Show that:Fig. 7.40 |
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| 45. |
4. In the given figure, two sides AB and BC and the median AD of AABC areequal respectively to the two sides PQ and QR and the median PM of theother triangle PQR.NCERTProve that1) AABD APQM(ii) AABC-APQRCBSE 20111 |
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| 46. |
Q 15: The probability of a defective egg in a lot of 400 eggs is 0.035. Calculate the number of defectiveeggs in the lot. Also calculate the probability of taking out a non-defective egg from the lot. |
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Answer» A = Getting defective eggs B = Getting non defective eggs P(A) = 0.035 P(A) = No. of detective egg------------------------------- Total eggs 0.035 × 400 = No. of defective egg No. of defective egg = 14 |
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| 47. |
tan™! (tanउनKT |
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| 48. |
o. Find the area of the minor segment of a circle of radius 42em, if length of the correspondingarc is 44cm.Water is flowing at thr rats of 15 km per hour through a pipe of diameter 14cm into a3MOIOT TINL OL |
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Answer» Let part of minor segment be xradius r = 42 cm Then,Length of minor segmentx*2*pi*r = 44x*2*22/7*42 = 44x = 7/42 = 1/6 Area of minor segment = x*pi*r*r= (1/6)*22/7*42*42= 22*42= 924 cm^2 |
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| 49. |
efig = पक w7z oHK9 =T KT ) |
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| 50. |
11-Draw a line segment of lengt 7.8 i ald uldtJ12 find the area of the sector of a circle with radius 4 cm and of angle 30°. Also, find the area of the conremajor sector (Use 3.14)sponding |
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