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Prove that the opposite side of a parallelogram are equal |
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Answer» ABCD is a parallelogram. To prove that AB = CD and AD = BC. Join the diagonal AC. In the triangles ABC and CDA:angleBAC= angleDCA(alternate angles, AB || DC) angleBCA= angleDAC (alternate angles, AD || BC) AC= CA (common)so triangleABC ≡ triangleCDA (AAS)Hence AB = CD and BC = AD (matching sides of congruent triangles) |
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