This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
B.Mr Hari spends 66% of his salary on his family, 20% of the remaining he gives to a trust for charity and is leftwith12240. What is the total salary of Mr Hari and how much amount does he give to the trust? |
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Answer» Let Salary = SSpent on family = 0.66 ×SRemaining = S - 0.66 S = 0.34 ×Sgiven to the trust = 0.20 ×0.34 ×S = 0.068 × S What is left = 0.80 ×(0.34 ×S) = 0.272 S 0.272× S = 12, 240 Rs S = Rs 45, 000 given to trust = 0.068 ×S = Rs 3, 060 wrong answers sorry for answers is wrong |
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| 2. |
21 -6 20 -1 5If Aand B = | 2 | , then AB equals : |
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Answer» If you find this solution helpful, Please like it. |
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| 3. |
When I add 6 times my age 6 years from now to 7 times my age 7 years from now, I get 14 times mycurrent age. How old will I be 5 years from now?" |
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Answer» Let the present age x.6(x + 6) + 7(x + 7) = 14x6x + 36 + 7x + 49 = 14x 13x + 85 = 14x x = 85 Age after 5 years = 85 + 5 = 90 years |
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| 4. |
(c) 30°2. The figure below shows three circles, each ofradius 25 and centres at P. O and R respectively,Further AB = 6,CD = 12 and EF = 15. What isthe perimeter of the triangle PQR?BV |
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Answer» Area of triangle is equal to 1/2×base×height |
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| 5. |
x = 2 × 2 × 2 × 17 which are prime factors of x.10. Show that any positive odd integer is of the form 6q 1 or 64+ 3 orinteger.NCERTCase-II1:dd integer and h = 6 Then, bv Euclid,s algorithm,r, for sa-gorithm, a 6Hence |
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Answer» Let a be the positive odd integer which when divided by 6 gives q as quotient and r as remainder. according to Euclid's division lemmaa=bq+ra=6q+r where a=0,1,2,3,4,5then,a=6qora=6q+1ora=6q+2ora=6q+3ora=6q+4ora=6q+5 but here,a=6q+1 & a=6q+3 & a=6q+5 are odd. |
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| 6. |
2. A vessel is in the form of a hollow hemisphere mounted by a hollow cylinder Thethediameter of the hemisphere is 14 cm and the total height of the vessel is 13inner surface area of the vessei.a. |
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| 7. |
2. A vessel is in the form of a hollow hemisphere mounted by a hollow cylinder. Theonndiameter ofthe hemisphere is 14 cm and the total height of the vessel is 13 cm. Find theinner surface area of the vessel. |
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| 8. |
2. A vessel is in the form of a hollow hemisphere mounted by a hollow cylinder. Thediameter of the hemisphere is 14 cm and the total height of the vessel is 13 cm. Find theinner surface area of the vessel. |
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Answer» D of hemisphere = 14cmr = 14/2 = 7cmCSA of hemisphere = 2πr²= 2 x 22/7 x 7 x 7 = 44x7= 308cm²r = 7cmh(total) = 13cmh(cylinder) = 13 - radius of heisphere = 13-7 = 6cmCSA of Cylinder = 2πrh = 2 x 22/7 x 7 x 6= 44x6 = 264cm²Surface area of the vessel = CSA of Hemisphere + CSA of Cyclinder= 308+264 = 572cm² hit like if you find it useful |
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| 9. |
1 - 3 + 9 - 27 + \dots \text { to } 9 |
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| 10. |
\frac{127+x !^{3}-3}{9-(27+x)^{\frac{2}{3}}} |
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| 11. |
-ture of the Yootsof the gactati..epnEonthe na |
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Answer» 2x²+x-1 => D = (b)²-4(a)(c) = (1)²-4(2)(-1) = 1+8 = 9 = 3² since S is a perfect square so, roots are real and rational. |
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| 12. |
हक 0 पर वि. gty₹५ के 6 की दर से केले खरीदकर X6 के5 की.दर से बेचे जाते हैं। लाभ प्रतिशत हैं...(3) 26%, (0) 42% (c) 44% (d) 48% |- i U EoEi SN4 &— इज |
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| 13. |
1.Use Euclid's division algorithm to find the HCF of :(G)135 and 225j3196 and 38220(iii): |
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| 14. |
Use Euclid's division algorithm to find the HCF of:.() 135 and 225(ii)196 and 38220(iii) 867 and 255 |
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| 15. |
Complete the series :21, 23, 27, 33, |
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Answer» The difference between the consecutive terms is increasing by 2. It follows the series 2,4,6,.. So, the next difference should be 2+6 = 8. Hence, the next number is 33+8 = 41 |
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| 16. |
) Sum the seriesto 6 terms3 9 27 |
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| 17. |
4. किसी 100 लोग 504. किसी शासकीय गोदाम के अनाज के संग्रह का।अनाज 4000 लोग 30 दिन तक खाते हैं तोसंग्रहित अनाज को 6000 लोग कितने दिन।खाएँगे?लोग कित |
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Answer» the maximum 20 days bro 4000 men =30 days1 men=4000×30days6000 men=120000/6000=20 days 20Is the correct answer; 120000/6000=20days is correct answer The answer is 20 days 20 days is the correct answer 15 is the correct answer me to 6000 peoples are eating food for 45 days 20 people eating tha food 20 dayscorrect answer for this question 4000 men=30 days 1men=4000×30 days 600 men=120000/6000=20days |
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| 18. |
(SSC Uटीम के पास कुछ मुर्गियों और गायें हैं। यदि सिरोंकी संख्या 48 और पैरों की संख्या 140 हो, तो मुर्गियोंकी संख्या कितनी है ?(2) 23 |
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Answer» no of hens will be 26 माना कि मुर्गी की संख्या = xतथा गायों की संख्या = yप्रश्न से,x+y = 48 .... (1)2x+4y = 140 .... (2)समी 1 तथा 2 को हल करने परx = 26 The right answer is 70 |
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| 19. |
thod of romnleting the square. |
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| 20. |
(a) ) Find the sum of the series +3 9 27 |
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| 21. |
Euclid's division algorithm to find the HCF of:(i) 135 and 225(ii) 196 and 38220(iii) 867 and 255 |
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| 22. |
Use Euclid's division algorithm to find the HCF of:(i) 135 and 225(ii) 196 and 38220(iii) 867 and 255 |
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| 23. |
What is the area of rectangular plot with sides 4 x^2 and 3y^2 |
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Answer» Area of recatngle is L×Bso here we have 4x² × 3y² = 12(xy)² |
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| 24. |
1. Use Euclid's division algorithm to find theof(i) 135 and 225(iii) 867 and 255(ii)196 and 3822 |
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| 25. |
saves 30% ofher monthly salary, if her income is15 Asma50,000, how much money does she spendeach month?a z12.000 |
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Answer» if she saves 30% then spent is 70%hence50000*70/100=35000 |
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| 26. |
UL 81% of 50RING QUANTITIESwild saves 6000 from her salary. 9. ConvertIf this is 15% of her salary. whatis her salary?ims:(14) |
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Answer» 15%=6000so ,1%=6000/15or,1%=400sototal salary=100%=400×100rupee=40000so total salary is Rs 40000 40000 is the right answer 15%=₹60001%=6000/15=400100%=400×100=₹40,000hence his salary is ₹40,000 40000 is her salary.... |
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| 27. |
sting Me thod |
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Answer» Q = { 1, 2, 3, 4, 5} Method As x belongs to N and between -5 and 5 and N is subset if Q so only Consider N. |
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| 28. |
. Find the number of terms to be added in the series 27,9,39,3,.. so that the sum is109327(2) 7(3) 8(4) 9 |
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| 29. |
1 Which one of the following is an irrational number?(a) 4(b)3V8(c)V100(d) -V0.642. The value of 163/4 +27 1/3is :(a) 4(b) 11(c) 8(d) 48uncian of rational number is terminating if factors of denominator are. |
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Answer» 1. option d is the right answer option (b) is the right ans 1. d is the right answer.... option -D is the answer for your question |
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| 30. |
\left. \begin{array} { l } { \text { If } a + b i = \frac { i + i } { 1 - i } \text { then } a ^ { 2 } + b ^ { 2 } = } \\ { 1 \quad b ) - 1 \quad c ) i } & { d ) - i } \end{array} \right. |
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| 31. |
02. Write the argument of -i |
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| 32. |
Calculate the argument of 2016-2016i |
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Answer» theta= arctan(b/a) Inthis case,arg(z)=arctan(−20162016)=arctan(−1)=−π4arg(z)=arctan(−20162016)=arctan(−1)=−π/4 asθ is in the fourth quardant |
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| 33. |
काट 903 के के डा कर + हा 1 |
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Answer» Sin3A/sinA+cos3A/cosA=(sin3AcosA+cos3AsinA)/sinAcosA=2sin(3A+A)/2sinAcosA [∵, sinαcosβ+cosαsinβ=sin(α+β)]=2sin4A/sin2A [∵, 2sinαcosα=sin2α]=(2×2sin2Acos2A)/sin2A=4cos2A (Proved) |
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| 34. |
Tick () the correct option.a) き402 + 501 is equal to(i)□ (ii) 903き9300 and 63 40 |
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| 35. |
61. If the number 4 8 3 27 8 isdivisible by 11, then theissing digit () is(a) 5 (b) 3 (c) 2 (d) 1 |
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| 36. |
Observe the given figures of AABC and ΔΡΟΙ. Then find whether they aresimilar or not.2.62 cm6 cmcmA 4 em B8 cm |
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| 37. |
\left. \begin{array} { l } { 6 . \text { If } \operatorname { log } ( 64 ) = 1.806 , \operatorname { log } ( 16 ) = ? } \\ { A .1 .204 \quad B .0 .903 } \end{array} \right. |
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| 38. |
11. Pind the area of the shaded region of each of the given figures6 cmD o3 cm GD 3 cm6 cm oA 6 cm, =: 23 Ynect25 cm |
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Answer» The area of the shaded region is = Area of rectangle - area of ∆ = (25*14) -(1/2*25*14)= 350-175 = 175cm² |
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| 39. |
10. If the distance of the point (x, y) from the point (a, 0) be a + x. Prove that y4a.otting a prime number less than 5. |
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| 40. |
|दो संख्याओं का अनुपात 3: 5 है। यदि उनका योगफल(d) 1/264 हो तो दोनों संख्या ज्ञात करें।(a) 24, 40 | (b) 36, 28(c) 16, 48 (d) 30, 34राहल ने 1200 रुपए में एक साइकिल खरीदी और उसे |
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Answer» (a) is a correct answer a is the correct or best answer (a) is a correct answer option A is the correct answer a is the correct or best answer 3x+5x=64; 8x=64; x=64/8=8; 3x=8; 8×3=24. 5x=8; x=5×8=40,; (1) 24, 40the correct answer. let 1st no. = 3x 2nd no. = 5x 3x+5x =64 8x=64 x= 64/8=8 1st no. =3×8=24 2nd no.=5×8=40 then A is the rite answer a) is correct answer do shankhiyan ka anupat 24,40 hoga |
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| 41. |
(it) 913-903issing quantities |
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Answer» wrong answer 1+91×90×3 check that out clealry it is right |
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| 42. |
ot Support1,000, 0sv |
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Answer» 100 |
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| 43. |
Fig. 2.1517.(x, x3) : x is a prime number less than 10 } in roster form.Write the relation R[N |
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| 44. |
The expenditure made on a dress is? 2050.20%。the expense was on embroidery, 50% on cloth andremaining on the stitching, find the money spent onstitching |
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| 45. |
Deepak Four-in-One (Revision Model Test PapeThe following data gives the distribution of total monthly household expenditure of 200 familisof a village. Find the modal monthly expenditure of the families.[H.B.S.E. 2014 (Set-A), 2015 (Se-8)]Expenditure (in) Number of families1000-15001500-20002000-25002500-30003000-35003500-40004000-45004500-50002440283016 |
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| 46. |
The sum of all two digit odd numbers is |
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Answer» pls feedback to me |
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| 47. |
37. A iluilnns Rs 10500 in a month. He spends of his money on food andey on travelling. Find the expenditure incurred on both separatelyof remaining |
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Answer» Thank you for answering |
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| 48. |
14892 Sabe site Damage 692 sall on theग्रसित है ? |
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Answer» 14892ka 692 ,21% hai |
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| 49. |
7 4Sall plants 4 saplings. in a row, In her garden. The distance between two adia ensaplings is m. Find the distance between the first and the last sapling.﹀34 |
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| 50. |
Or, Find the sum of all two-digit odd posive lhul17. In the adjoining figure, PA and PB aretangents drawn from an external point P to acircle with centre OProve that ZAPB- 2ZOAB |
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Answer» given : a circle with centre O. PA and PB are two tangents to the circle at A and B To prove : L APB = 2 <OAB Proof : join AB and OA OA is perpendicular to PA (tangent and the radius at the point of contact) therefore <OAP = 90degree let <OAB = x therefore <PAB = 90 - x ----- (1) PA = PB (tangent from same external point) therefore triangle APB is isosceles therefore <PAB = < PBA = 90-x (angles opp to equal sides) Tn triangle APB <P + 90 - x + 90 - x = 180 degree (angle sum property) <P + 180 - 2x = 180degree <P = 2x < APB = 2x ie, < APB = 2 < OAB |
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