Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

The line through (1-1)and (2-2)is also:

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m= y2-y1/x2-x1m= -2+1/2-1m= -1y-y1= m(x-x1)y-(-1)= -1(x-1)y+1= -x+1

2.

103 H x = 1+oglandy - 3+ 2loge, thenis equal to114b. -1c. 1d. +

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3.

In Fig 10.33,AB||CD, find the value of x and also of angle 1, 2, 3 and 4.

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It's a linear pair of anglesand we know sum of these linear angles will be 180°so as <3= 7x+5( alternative interior angles)and <4= 3x+5(same as above)10x+10= 180x= 17°angle 1= (17*3+5)= 56= angle 4angle 3= (180-56)= 124°= angle 2

Please like the solution 👍 ✔️

4.

cost of 15 pencil is equal to the cost of 5 pens if cost of one pen is 30 find the cost of seven pencil and four pen.

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Cost of 1 pen =30Cost of 5 pens=30*5=150RsCost of 15 pencils=150 RsCost of 1 pencil=150/15=10 RsCost of 7 pencils=10*7=70RsCost of 4 pens=30*4=120Rs

5.

. Find the ratio of the price of a Maths book and an English book if price of 12 Maths12 Maths book is*240 and the price of 15 English books is 135.

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6.

11. In a survey of 400 students 160 liked Maths, and rest dislike it. Find the probability that astudent chosen at random like Maths.

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Total students=400Students like maths=160Probability=160/400=4/10=2/5

7.

The radius and height of a cylinder are in the ratio 5 : 7 and its volume is 550cmFind its radius.a) 10 cmb) 5 cmc) 6 cmd) 12 cm

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8.

16.The radius and height of a cylinder are in the ratio 5:7 and its volume is 550cm.Find its radius.a) 10 cmby 5 cmC) 6 cmd) 12 cm

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B) H=5

......................

9.

Two Simple Properties of Multiples

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any no. when multiplied with 0 , the result is always 0.any no. when multiplied with 1 , the result is always same as the original no.

here are four properties involving multiplication that will help make problems easier to solve. They are the commutative, associative, multiplicative identity and distributive properties.

Commutative property: When two numbers are multiplied together, the product is the same regardless of the order of the multiplicands. For example 4 * 2 = 2 * 4

Associative Property: When three or more numbers are multiplied, the product is the same regardless of the grouping of the factors. For example (2 * 3) * 4 = 2 * (3 * 4)

Multiplicative Identity Property: The product of any number and one is that number. For example 5 * 1 = 5.

Distributive property: The sum of two numbers times a third number is equal to the sum of each addend times the third number. For example 4 * (6 + 3) = 4*6 + 4*3

10.

6) Find the sum of all two digit odd multiples of 3.

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a=15d=6l=99no of terms= 15sum of all 2 digit odd multiples of 3 =15÷2(a+l)=15÷2(15+99)855

final answer is 855 for this

Correct Ans =855a =15d=6an =16By Sn formula of AP.correct Ans =855

11.

thethe line segment Bainingto Ariseted at the point P and a such that Pis meaP also lies on the 1tne gitenalve

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- me ni aega

12.

\left. \begin{array} { l } { \text { ind the value of } x ^ { 4 } + \frac { 1 } { x ^ { 4 } } , \text { when } x + \frac { 1 } { x } = 4 } \\ { \text { } 192 \quad ( b ) 294 } \end{array} \right. , \text { when } x + \frac { 1 } { x } = 4

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13.

Mark (v) against the correct answer1. The supplement of 45° is

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14.

\frac { x } { x - 4 } - \frac { 1 } { ( x + 4 ) ( x - 4 ) }

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15.

I. Choose the correct answer.1. The numerical coefficientof "-y" isD-YB)- 1103

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The numerical coefficient of -y is -1

option B is correct

16.

For two triangles, if the ratio of their bases is 1 :2 and the ratio of their corresponding altitudeis also1: 2, then find the ratio of their areas.

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solving me my next doubt

17.

22. D is the midpoint of side BC of ΔABC and E isthe midpoint of BD. If O is the midpoint of AE,Ovprove thatar(ABOE)8ar(ABC)

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18.

22, D is the midpoint of side BC of △ABC and E isthe midpoint of BD. If O is the midpoint of AE,prove that ar(A BOE)--ar(0Ov

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thaamx bhaii

it's an incomplete question

19.

xample 6 Express the following in the form a + ib(i)に石1-v2i(ii) r35

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20.

(a) 25v3 cmone side of a right triangle of hypotenuse 20 cnn is 16 cm area of the triangle is(a) 320 cm6(b) 160 cm(c) 192 cn2(d) 96 cm7 am 30 cm and 26 cm, Area of the triangle is

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hit like if you find it useful

21.

CDxample 10 Find the ratio in which the line segment joining the points (4, 8, 10) and(6, 10,-8) is divided by the YZ-plane.DA

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22.

1. In the given figure, If AB DC andPis the midpoint of BD, prove thatP is also the midpoint of AC.

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23.

Exercise 11.41. In the given figure, If ABDC andP is the midpoint of BD, prove thatPis also the midpoint of AC.

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24.

its hypotehuse7.The lengths of the sides of some triangles are given below. Which of them are right(1) a = 15 cm, b=20 cm and c = 25 cm(i) a-9 cm, b -12 cm and c-16 cm(i)a-10 em, b 24 cm and c-26 cm

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Thanks

25.

.Theperimeterofrectangle whose breadth is 6.5 cm and length is double the breadth is(d) 9.75 cnm(a) 26 cmWhich statement ahout s,b 39 cm(c) 19.5

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Given breadth = 6.5 cmLength = 2*6.5 = 13 cm

Perimeter of ractangle= 2 (length + breadth)= 2 (13 + 6.5)= 2 (19.5)= 39 cm

b is correct option

26.

38. The sides of a triangle are in the ratiopoti 1.11: 3 7 anoits perimeter is 104 cm. The length of the longest sideis :A. 52 cmB. 48 cmC. 32 cmD. 26 cm

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A as 104 ×1by 2= 54,104×1by4=26

B. 48 is the right answer

27.

UL JUL UPWO squares.M umerence of their perimeters is 16 cm,0. The area of a rectangular plot is 528 m². The length of the plot (in metres) is one metre(CBSE 20131more then twice its breadth. Find the length and the breadth of the plot. (CBS

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Area=528Breadth =xLength =2x+1X(2x+1)=5282x^2+x-528=0B=13.3L=27.6

length=27.6 and breadth= 13.3 may be

28.

A circle of radius 2 cm is cut out from a square piece of an alumina6 em. What is the area of the left over aluminium sheet? (Take 3.1The circumference of a circle is 31.4 cm. Find the radius and(Take π-3.14)um shee11.the area of the12.

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29.

4. The lengths of 40 leaves of a plant are measured correct to the nearestthe data obtained is represented in the following table:Number of leavesLength (in mm)118-126127-135136-144145-153154-162163-171172-180

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nice one............................

30.

: The lengahsof 4o leaves of a plamt are measured correctto the nearest millimetre, and thedatais represented in the folowing tablesLength n mm)Number of leaves118-126127-135136-144145-153154-1623912163-171172-1S02

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31.

he lengths of 40 leaves of a plant are measured correct to the neareste data obtained is represented in the following table:Number of leavesLength (in mm)118-126127-135136-144145-153154-162163-171172-180De7. Th12145As we

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32.

sum of all interior angle of a regular Pentagon

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Sum of all angles in a regular n sided polygon is (n-2)180°Pentagon (n=5)=(5-2)*180=3*180=540°

33.

Q16. Find the number of diagonals in a regular pentagon?

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Number of diagonals in a polygon =n(n-3)/2where n is the number of sides of the polygon.(1) Number of sides in a pentagon = 5Number of diagonals =5(5-3)/2= 5

34.

xample 6 Express the following in the form a + ib(ii) i-35

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thank q🙏🙏

35.

what is the sum of interior angles of a regular pentagon.

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Ans :- The sum of all the angles is540 degrees.the measure of the interior angle of a regular pentagon is108 degrees.

right. thank you friend

36.

State and prove midpoint theorem

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The line segment joining the mid-points of any two sides of a triangle is parallel to the third side and is equal to half of it.

Take a triangle ABC,E and F are the mid-points of side AB and AC resp.

Construction:-Through C,draw a line II BA to meet EF produced at D.

Proof:-In Triangle AEF and CDF1.AF=CF(F is midpoint of AC)2.<AFE=<CFD (Vertically opp. angles)3.<EAF=<DCF [Alt. angles,BA II CD(by construction) and AC is a transversal]4.So,Triangle AEF = CDF(ASA)5.EF=FD AND AE = CD (c.p.c.t)6.AE=BE(E is midpoint of AB)7.BE=CD(from 5 and 6)8.EBCD is a IIgm [BA II CD (by construction) and BE = CD(from 7)]9.EF II BC AND ED=BC (Since EBCD is a IIgm)10.EF = 1/2 ED (Since EF = FD,from 5)11.EF = 1/2 BC (Since ED = BC,from 9)Hence,EF II BC AND EF = 1/2 BC which proves the mid-point theorem.

37.

(2) Theorem : The segment joining the centre of acircle and the midpoint of its chord is perpendicularto the chord.

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38.

The exterior angle of a regular pentagon inradian measure is2.

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o understand the sum of interior angles in a polygon, we should be aware of the following

The sum of all interior angles in a triangle is 180 degSum of all angles around a point is 360 degThe proof of the first property is fairly simple. Refer to the diagram below :

Next, let’s consider a pentagon. Let P be an interior point. Now, by connecting all the sides to this point we can form 5 triangles as shown in the figure. Sum of interior angles of the pentagon will be = sum of int. angles of all the triangles - sum of angles around the point.

i.e, S=5×180−360

This concept can be extended to the general case of n-sided polygon. Again, we’ll be able to form n triangles using the sides and any one unique interior point.

S=n× (sum of angles in a triangle) − (sum of angles around a point)

S=n×180−360

⇒ S=(n−2)×180

In case of pentagon, as discussed already in the above example, we’ll get S=540

Now, since each angle in a regular pentagon will be equal, we can safely conclude that all of them will have a value =5405=108 degrees

To get the value in radians, you should know the conversion factor, else you can learn it straight away.

180 degrees = π radians

⇒ 1 degree = π180 radians

⇒ 108 degrees = 108×π180 radians = 0.6π=3π5

39.

3. Find the number of degrees in each exteriorangle of a regular pentagon.

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the number of a degree in each exterior angle of a regular pentagon is is each exterior angle equals to 360 upon n is 5 exterior angle is 60 upon 5 equal to 72

40.

(i) (V3-t, V7)

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√3² + 2√3√7 + √7²

= 3+7+2√21

= 10+2√21

= 2(5+√21)

41.

Rationalize the denominator oV7-16

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ansher

42.

1. Expand and simplify. V7+ V5)2

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We know that(a+b)^2= a^2+b^2+2ab

= 7+5+2√3512+2√35

43.

Prove that V7 + V2 is an irrational number.

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√2 +√7 = a/b (where a and b are co-prime)√7 = a/b -√2Squaring both sidesa²/b² - 2√2a/b + 2 = 7a²/b² - 5 = 2√2a/b(a² - 5b²) / 2ab =√2

√2 is an irrational number .This contradicts the fact that√2 is irrational . So , our assumption is wrong.Hence , √2 +√7 is irrational.

V7+V2 x V7-V2/V7-V2= (V7)^2-(V2)^2/V7-V2=7-2/V7-V2=5/V7-V2

44.

2 &lt;i e NCERT,CBS42. e &amp; &gt; {

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45.

e(q€ — ण्ट) - g('q-g + v7) :Afduas है

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46.

(3) Write the degree of the polynomial v7

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degree of polynomial is 0 here.

47.

5. Prove that v7 is an irrational number.

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Let √7 be rationalLet √7 = a / b wher a,b are integers b ≠ 0we also suppose that a / b is written in the simplest form

Now √7 = a / b

⇒ 7 = a²/b² ⇒ 7b²= a²

∴ 7b²is divisible by 7

⇒ a²is divisible by 7

⇒ a is divisible by 7

∴ let a = 7c

a² = 49c²

⇒ 7b²= 49c²

⇒b²= 7c²

∴ 7c² is divisible by 7

∴ b² is divisible by 7

∴ b is divisible by 7

∴a are b are divisible by 7this contradicts our supposition that a/b is written in the simplest formHence our supposition is wrong

∴ √7 is irrational number.

48.

Construct a 2 x 2 matrix whose elements a are given as:

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49.

Construct a 3x 2 matrix whose elements are given by a (2i-j).

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50.

xample -11. Prove the followings(i)cos 10°.cos 30°. cos 50°. cos 70° =3/16

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